Edexcel A-Level Chemistry Paper 2, June 2018: Question 1
4 marks · Easy difficulty · Multiple Choice
Identify properties and reactions of alkanes, including free-radical substitution, incomplete combustion, reforming, and molecular formula determination from skeletal structures.
Practise this questionQuestion
Question text
1 This question is about alkanes.
(a) The reaction of ethane and chlorine in UV radiation produces chloroethane.
C2H6 + Cl2 → C2H5Cl + HCl
This reaction is classified as
(1)
A addition
B elimination
C initiation
D substitution
(b) The black smoke produced from the incomplete combustion of alkane fuels is
(1)
A carbon particulates
B oxides of nitrogen
C oxides of sulfur
D unburnt hydrocarbons
(c) A reaction of hexane is shown below.
+ H2
This is best described as
(1)
A elimination
B hydrogenation
C isomerisation
D reforming
(d) The skeletal formula of decalin is
2 The molecular formula of decalin is
*P52293A0224* (1)
A C10H22
B C10H20
C C10H18
D C10H16
(Total for Question 1 = 4 marks)
Mark scheme
Show the mark scheme
Question
Acceptable Answer Mark
Number
1(a) The only correct answer is D (1)
A is incorrect because it is not an addition reaction
B is incorrect because no multiple bond is formed
C is incorrect because initiation is only the first stage in the mechanism of the reaction
Question
Acceptable Answer Mark
Number
1(b) The only correct answer is A (1)
B is incorrect because oxides of nitrogen are not black solids
C is incorrect because oxides of sulfur are not black
D is incorrect because unburnt hydrocarbons are not black solids
Question
Acceptable Answer Mark
Number
1(c) The only correct answer is D (1)
A is incorrect because no alkenes are produced
B is incorrect because hydrogen is formed
C is incorrect because the molecular formulae of the organic compounds are not the same
Question
Acceptable Answer Mark
Number
1(d) The only correct answer is C (1)
A is incorrect because there are not 22 hydrogen atoms
B is incorrect because there are not 20 hydrogen atoms
D is incorrect because there are not 16 hydrogen atoms
(Total for Question 1 = 4 marks)
How to answer it
A-Level Chemistry Study Guide: Alkanes Properties & Reactions
What this question tests
This multiple-choice sequence assesses core foundational knowledge of alkane chemistry, including free-radical halogenation mechanisms, incomplete combustion products, catalytic reforming definitions, and interpreting skeletal formulae to determine molecular formulae.
Halogenation of Ethane
C₂H₆ + Cl₂ → C₂H₅Cl + HCl
✅ Correct Answer
D: substitution
💡 Key Knowledge
- Alkanes react with halogens in the presence of UV light via free-radical substitution.
- A hydrogen atom in the alkane is replaced by a halogen atom.
❌ Common Errors
- Choosing C (initiation): Initiation is only the first step of the mechanism, not the overall reaction type.
- Choosing A or B: Alkanes do not undergo addition or simple elimination under these conditions.
Incomplete Combustion of Alkanes
✅ Correct Answer
A: carbon particulates
💡 Key Knowledge
- Incomplete combustion occurs when oxygen is in limited supply.
- It produces carbon monoxide and solid carbon particulates (soot/black smoke), rather than just carbon dioxide and water.
❌ Common Errors
- Confusing particulates with oxides of nitrogen or sulfur, which arise from high-temperature combustion of nitrogen in air or sulfur impurities in fossil fuels respectively, not alkane soot.
Reactions of Hexane
Hexane → Cyclohexane + H₂
✅ Correct Answer
D: reforming
💡 Key Knowledge
- Catalytic reforming involves converting straight-chain alkanes into cycloalkanes or branched-chain alkanes, often releasing hydrogen gas in the process.
❌ Common Errors
- Selecting A (elimination): While hydrogen is eliminated, reforming is the specific industrial term used for converting straight-chain alkanes into cyclic hydrocarbons.
Molecular Formula from Skeletal Formula
✅ Correct Answer
C: C₁₀H₁₈
🧠 Exam Technique & Counting
- Carbons (10): Decalin consists of two fused six-membered rings (cyclohexane rings sharing a C-C bond). Total vertices/carbons = 10.
- Hydrogens (18): Apply the general formula for a bicyclic alkane with two rings, CₙH₂ₙ₋₂ (since 2 rings require the removal of 4 hydrogens total compared to an open-chain alkane). Therefore, for n = 10, 2(10) - 2 = 18 hydrogens. Alternatively, count junctions (2 CH groups with 1 H each) and unbranched CH₂ carbons (8 × 2 H) = 2 + 16 = 18.
❌ Common Errors
- Assuming a saturated hydrocarbon must fit the standard open-chain alkane formula CₙH₂ₙ₊₂ (which would give C₁₀H₂₂). Remember that ring structures reduce the hydrogen count by 2 for each ring present.
Topics
Organic Chemistry · Topic 6: Organic Chemistry I
Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 2, June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.