Edexcel A-Level Chemistry AS Paper 2, June 2019: Question 5
13 marks · Hard difficulty · Open Response
Investigate the elimination and substitution reactions of bromobutanes to produce butenes and butan-1-ol using experimental apparatus, calculations, mechanisms, and chemical tests.
Practise this questionQuestion
Question text
5 Bromobutanes react with hot ethanolic potassium hydroxide solution to produce
gaseous butenes.
C H9Br + OH− → C H8 + Br− + H O
44 2
Apparatus
gas
syringe
clamp to seal
gas syringe reflux
condenser
rubber seal for
injection of
bromobutane
hot ethanolic
potassium hydroxide
hot oil bath
Procedure
Ɣ 0.0080 mol of liquid 1-bromobutane was injected into a round bottom flask
containing hot ethanolic potassium hydroxide.
Ɣ After the reaction, the syringe was sealed using a clamp.
Ɣ The syringe was then removed from the apparatus and allowed to cool to
room temperature (298 K).
Result
The final volume of but-1-ene collected was 22.0 cm3.
(a) State the purpose of the condenser.
(1)
(b) Describe a chemical test on the gas in the syringe to identify its functional group.
Include the expected result.
(2)
… *P55611A01228*
(c) Calculate the percentage of 1-bromobutane which was converted to but-1-ene.
[Molar volume of a gas at r.t.p. = 24 000 cm3 mol–1]
(2)
(d) Before cooling, the volume of but-1-ene in the gas syringe was 24.0 cm3.
Calculate the temperature of the gas in the syringe before it cooled.
[Assume no loss from the gas syringe during cooling, and a constant pressure]
(2)
(e) (i) Another compound formed from 1-bromobutane under these conditions is butan-1-ol.
Identify the type of reaction taking place to form butan-1-ol.
(1)
(ii) The functional group in butan-1-ol can be confirmed using a single chemical test.
What is the single chemical test and expected observation?
(1)
Chemical test reagent Observation 13
A sodium carbonate solution*P55611A01328*effervescence
B aqueous silver nitrate cream precipitate
C Fehling’s solution red precipitate
D phosphorus(V) chloride steamy fumes
(iii) Draw the mechanism for the reaction of 1-bromobutane with hydroxide ions
to form butan-1-ol.
Include curly arrows, and any appropriate lone pairs and dipoles.
(3)
(f ) Alkene molecules are formed by elimination from 2-bromobutane.
How many isomeric alkene products will be formed in this reaction?
(1)
A 1
B 2
C 3
D 4
(Total for Question 5 = 13 marks)
Mark scheme
Show the mark scheme
How to answer it
Halogenoalkanes: Elimination, Substitution & Mechanisms
This comprehensive question assesses your practical and theoretical understanding of halogenoalkane chemistry. It covers reflux apparatus design, functional group testing for alkenes and alcohols, gas molar volume and gas law calculations, reaction mechanisms (nucleophilic substitution / SN2), and structural isomerism in alkenes.
Part (a): Purpose of the Condenser
Exam Question Part (a)
✅ Correct Answer
Returns or condenses volatile reactants/evaporated gases (except the product gas, but-1-ene) back to the reaction mixture so they are not lost.
💡 Key Knowledge
Reflux setups prevent the escape of volatile organic starting materials (like 1-bromobutane) and solvents when heated strongly, ensuring complete reaction without losing reactants.
❌ Common Errors
Students often lose the mark by stating it "condenses the products" or "cools down gases" generally. You must specify that volatile reactants are returned, while the gaseous alkene product passes through into the syringe.
Part (b): Chemical Test for Alkenes
Exam Question Part (b)
✅ Correct Answer
Reagent: Bromine water ( Br₂(aq) ) or bromine in an organic solvent.
Observation: Goes from orange/brown to colourless.
Alternative: Acidified potassium manganate(VII) ( KMnO₄/H⁺ ), goes from purple to colourless.
🧠 Exam Technique
Always state both the specific reagent and the clear colour change (initial and final colours). Writing "it clears" is insufficient—specify the starting colour and the resulting colourless state.
Part (c): Percentage Conversion Calculation
Exam Question Part (c)
📐 Step-by-Step Calculation
- Find moles of gas collected:
Moles = Volume / Molar Volume = 22.0 / 24000 = 9.167 × 10⁻⁴ mol - Calculate percentage converted:
Percentage = (Moles of product / Initial moles of reactant) × 100
= ( 9.167 × 10⁻⁴ / 0.0080 ) × 100 = 11.5% (or 11.46%)
❌ Common Calculation Traps
Watch out for unit mismatches! Ensure volume units match (cm³ to cm³, or converting both to dm³). Do not prematurely round intermediate steps in your calculator.
Part (d): Gas Laws & Temperature Calculation
Exam Question Part (d)
📐 Step-by-Step Calculation
- Recognize proportional relationships: At constant pressure and constant moles of gas, V₁ / T₁ = V₂ / T₂ . Therefore, T₂ = T₁ × (V₂ / V₁) .
- Substitute values (remembering Kelvin):
Initial temperature T₁ = 298 K .
Initial volume before cooling V₁ = 24.0 cm³ , final cooled volume V₂ = 22.0 cm³ . - Calculate final temperature:
T₂ = 298 × (22.0 / 24.0) = 273.17 K (or 0.17 °C ). Alternatively, using pV = nRT directly yields credit.
💡 Key Knowledge
Always convert temperatures to Kelvin ( K = °C + 273 ) when applying gas laws or ideal gas equations.
Part (e): Substitution Reactions & Mechanisms
Exam Question Part (e)
✅ (i) Type of Reaction
Substitution (or hydrolysis / nucleophilic substitution). Do not accept elimination or electrophilic substitution.
✅ (ii) Functional Group Test
Answer: D (phosphorus(V) chloride | steamy fumes)
PCl₅ reacts with the hydroxyl group in alcohols to produce misty/steamy fumes of hydrogen chloride gas ( HCl ).
💡 (iii) Mechanism for Formation of Butan-1-ol (SN2)
- Curly arrow 1: From the lone pair of electrons on the oxygen atom of the hydroxide ion ( OH⁻ ) to the carbon atom bonded to the halogen.
- Curly arrow 2: From the C-Br bond directly to the bromine atom, resulting in departure of the bromide ion ( Br⁻ ).
- Dipoles & Charges: Partial positive charge ( δ⁺ ) on carbon and partial negative charge ( δ⁻ ) on bromine, along with a complete negative charge on the leaving bromide ion.
Part (f): Alkene Isomerism from Elimination
Exam Question Part (f)
✅ Correct Answer
Answer: C (3)
🧠 Exam Technique
Elimination from 2-bromobutane ( CH₃-CH(Br)-CH₂-CH₃ ) can yield hydrogen from carbon-1 or carbon-3. This produces:
- But-1-ene
- cis-but-2-ene (Z isomer)
- trans-but-2-ene (E isomer)
Topics
Organic Chemistry · Physical Chemistry · Topic 5: Formulae, Equations and Amounts of Substance · Topic 6: Organic Chemistry I
Question and mark scheme from the Edexcel A-Level Chemistry examination, AS Paper 2, June 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.