Edexcel A-Level Chemistry Paper 1, June 2019: Question 5

8 marks · Medium difficulty · Open Response

Explain homogeneous and heterogeneous catalysis using transition metal examples including iron, cobalt, manganese, tungsten, and platinum.

Practise this question

Question

A four-part exam question about catalysis. Part (a) asks about the reaction between iodide and peroxodisulfate ions catalysed by iron(II) ions, including why it has a high activation energy and writing two equations for the catalytic mechanism. Part (b) asks to deduce two ionic equations for the cobalt(II)-catalysed oxidation of sulfite ions in acidic solution. Part (c) is a multiple-choice question identifying the autocatalyst in the oxidation of ethanedioate ions by manganate(VII). Part (d) provides a gas adsorption trend for tungsten, platinum, and silver, asking why tungsten would be unsuitable as a replacement for platinum in a catalytic converter.
Question text

5 This is a question about catalysis.

(a) The reaction between iodide ions and peroxodisulfate ions is catalysed by iron(II) ions.

Fe2+

2I– + S O82– o I + 2SO2–

22 4

(i) Give a reason why the reaction between iodide ions and peroxodisulfate ions

has a high activation energy and is therefore very slow without a catalyst.

(1)

(ii) Explain, with the aid of two equations, how the iron(II) ions catalyse this

reaction. State symbols are not required.

(3)

(b) The oxidation of sulfate(IV) ions to sulfate(VI) ions is catalysed by cobalt(II) ions in

acidic solution. The role of cobalt(II) ions is similar to that of iron(II) ions in (a).

Co2+

SO2– + ½O o SO2–

32 4

Deduce two ionic equations to show how cobalt(II) ions catalyse the reaction in

acidic solution. State symbols are not required.

(2)

(c) The rate of oxidation of ethanedioate ions by manganate(VII) ions starts slowly

and then rapidly increases.

2MnO– + 16H+ + 5C O42– o 2Mn2+ + 8H O + 10CO

42 2 2

What is the catalyst in this reaction?

(1)

A CO2

B H+

C Mn2+

12 D MnO–

*P58306A01228*

(d) The trend in the strength of gaseous adsorption by three transition elements is

tungsten ! platinum ! silver

Silver is not suitable as a replacement for platinum in a catalytic converter

because the adsorption of gases is too weak to allow significant chemical reaction.

Give a possible reason why tungsten would also not be a suitable replacement

for platinum in a catalytic converter. Refer to the mechanism of heterogenous

catalysis in your answer.

(1)

(Total for Question 5 = 8 marks)

Mark scheme

Show the mark scheme The mark scheme provides detailed guidance for all parts of Question 5. Part (a)(i) awards 1 mark for stating the two negative ions repel each other. Part (a)(ii) awards 3 marks: one for the oxidation of iron(II) equation, one for the reduction of iron(III) equation, and one for stating variable oxidation states or oppositely charged ions. Part (b) awards 2 marks for the cobalt(II) oxidation and reduction equations. Part (c) confirms C as the correct multiple-choice answer. Part (d) awards 1 mark for stating that tungsten's adsorption is too strong, leading to slow desorption.

How to answer it

Edexcel A-Level Chemistry: Catalysis Masterclass

📋 What this question tests

This question assesses your understanding of homogeneous and heterogeneous catalysis, transition metal chemistry (variable oxidation states), reaction kinetics, activation energy barriers, and the specific mechanisms of adsorption and desorption in catalytic processes.

Question 5 (a)(i): Activation Energy in Homogeneous Systems

Why the reaction between iodide and peroxodisulfate is slow

✅ Correct Answer

The two reacting ions both possess negative charges ( I⁻ and S₂O₈²⁻ ) and therefore experience electrostatic repulsion when they approach one another.

💡 Key Knowledge

For any reaction to occur, particles must collide with sufficient energy (greater than or equal to the activation energy). Because both species are anions, significant energy is required to overcome the repulsive forces between their electron clouds before bond rearrangement can happen.

❌ Common Errors

  • Stating only that "ions repel" without specifying that they are both negative.
  • Vague references to general collision theory without mentioning charge or repulsion.
🎯 Marks: 1/1 available

Question 5 (a)(ii): Catalytic Mechanism of Fe²⁺

Writing two-step catalytic equations

✅ Correct Answer

Step 1 (Oxidation): 2Fe²⁺ + S₂O₈²⁻ → 2Fe³⁺ + 2SO₄²⁻
Step 2 (Reduction): 2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂

Reasoning: Catalysis is possible because iron exhibits variable oxidation states (+2 and +3), and breaking the reaction into two steps involves oppositely charged ions in each step, avoiding direct repulsion.

🧠 Exam Technique

State symbols are explicitly not required by the prompt, so save time by omitting them. Ensure your equations balance stoichiometrically. You may write them in reverse order, but keeping oxidation first mirrors the logical flow of the catalytic cycle.

❌ Common Errors

  • Forgetting to state why the catalyst works (mentioning variable oxidation states or opposite charges is vital for the 3rd mark).
  • Balancing errors with sulfate or iron species.
🎯 Marks: 3/3 available (1 for step 1, 1 for step 2, 1 for explaining variable oxidation states / alternative pathway with opposite charges)

Question 5 (b): Cobalt(II) Catalysis in Acidic Solution

Applying catalytic principles to a new system

✅ Correct Answer

Step 1: 2Co²⁺ + 0.5O₂ + 2H⁺ → 2Co³⁺ + H₂O
Step 2: 2Co³⁺ + SO₃²⁻ + H₂O → 2Co²⁺ + SO₄²⁻ + 2H⁺

💡 Key Knowledge

Just like iron, cobalt demonstrates variable oxidation states ( Co²⁺ / Co³⁺ ). Because the medium is acidic, H⁺ ions and H₂O molecules will frequently appear in the half-equations to balance oxygen and hydrogen atoms.

🧠 Exam Technique

Check your species carefully: ensure the catalyst ( Co species) is regenerated at the end of the second step. Multiples of these equations are fully accepted by examiners.

🎯 Marks: 2/2 available

Question 5 (c): Identifying an Autocatalyst

Multiple-choice rate analysis

✅ Correct Answer

C: Mn²⁺

Explanation: The reaction starts slowly because it involves two negative ions repelling each other ( MnO₄⁻ and C₂O₄²⁻ ). As the reaction proceeds, Mn²⁺ ions are formed as a product, which then act as an autocatalyst, speeding up the rate dramatically.

❌ Common Errors

  • Selecting H⁺ (Option B), confusing the role of the acid medium with catalytic product generation.
  • Selecting CO₂ (Option A) due to misinterpreting gas evolution as the catalytic driver.
🎯 Marks: 1/1 available

Question 5 (d): Heterogeneous Catalysis and Adsorption Strength

Why tungsten fails as a catalytic converter material

✅ Correct Answer

Tungsten is unsuitable because adsorption is too strong, meaning desorption of the products would be far too slow.

💡 Key Knowledge

In heterogeneous catalysis, a delicate balance is required: adsorption must be strong enough to hold reactants on the surface and weaken their internal covalent bonds, but weak enough that the final products can detach (desorb) to free up active sites for the next catalytic cycle.

❌ Common Errors

  • Using the spelling "absorption" instead of "adsorption" (penalised by examiners as it refers to a different bulk physical process).
  • Discussing reactivity series, melting points, or cost instead of focusing strictly on the surface adsorption/desorption mechanism.
🎯 Marks: 1/1 available

Topics

Inorganic Chemistry · Physical Chemistry · Topic 9: Kinetics I · Topic 15: Transition Metals

Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 1, June 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.