Edexcel A-Level Chemistry AS Paper 1, November 2020: Question 3

9 marks · Medium difficulty · Short Open Response

Explain covalent bonding, draw a dot-and-cross diagram, estimate bond angles, explain solubility through hydrogen bonding, and give reasons for hydrazine acting as a rocket fuel.

Practise this question

Question

Exam question about hydrazine, N2H4. Part (a)(i) asks to explain a covalent bond (2 marks). Part (a)(ii) asks to draw a dot-and-cross diagram for hydrazine showing outer electrons only (1 mark). Part (a)(iii) asks to estimate the H-N-H bond angle (1 mark). Part (b) asks to explain why hydrazine is very soluble in water using a labelled diagram and naming intermolecular interactions (3 marks). Part (c) gives an equation for the reaction of hydrazine with hydrogen peroxide and asks for two reasons why it is a good rocket fuel (2 marks).
Question text

3 Nitrogen forms several hydrides. In addition to ammonia, NH3, it forms hydrazine, N2H4,

in which the two nitrogen atoms are covalently bonded together.

(a) (i) Explain what is meant by a covalent bond.

(2)

(ii) Draw a dot-and-cross diagram for hydrazine, showing the outer electrons only.

Use crosses (×) to represent the electrons from nitrogen and dots (•) to

represent the electrons from hydrogen.

(1)

(iii) Estimate the H N H bond angle in hydrazine.

(1)

Bond angle = …

(b) Hydrazine is very soluble in water.

Explain, using a labelled diagram and naming the relevant intermolecular interactions,

why hydrazine is very soluble in water.

(3)

… *P62306A0624*

(c) Hydrazine has been used as a rocket fuel.

It is a powerful reducing agent and will react very exothermically with oxidising agents

such as hydrogen peroxide.

The equation for the reaction of hydrazine with hydrogen peroxide is

N2H4(l) + 2H2O2(l) → N2(g) + 4H2O(g)

Give two reasons why hydrazine is a good rocket fuel when reacted with

hydrogen peroxide.

(2)

(Total for Question 3 = 9 marks)

Mark scheme

Show the mark scheme Mark scheme for question 3. Part (a)(i) awards 1 mark for electrostatic attraction of two nuclei and 1 mark for a shared pair of electrons. Part (a)(ii) awards 1 mark for a correct dot-and-cross diagram showing N-N single bond and bonded hydrogens. Part (a)(iii) awards 1 mark for 107 degrees (range 105 to 108). Part (b) awards 3 marks for mentioning hydrogen bonding in water/hydrazine, a diagram showing hydrogen bonds between correct atoms with a lone pair, and approximately 180 degrees linear arrangement at the hydrogen bond. Part (c) awards 2 marks for points such as large quantities of gases produced from liquids and formation of strong triple bonds or hot gases expanding.

How to answer it

Hydrazine and Covalent Bonding

What this question tests

This question assesses fundamental AS Chemistry bonding definitions, dot-and-cross electron configurations, VSEPR theory for bond angle predictions, intermolecular forces (specifically hydrogen bonding in solution), and real-world thermodynamic/kinetic applications of redox reactions.

Question 3 (a) (i)

Defining a Covalent Bond

✅ Correct Answer

An electrostatic attraction between a shared pair of electrons and the nuclei of the bonded atoms.

💡 Key Knowledge

  • Must mention both the electrostatic attraction and the shared pair of electrons.
  • The attraction acts between the positive nuclei and the negatively charged shared electrons.

❌ Common Errors

Students often lose marks by stating that atoms "share electrons to gain a full outer shell" rather than defining what holds the bond together physically (the electrostatic attraction).

Mark breakdown: 1 mark for electrostatic attraction of two nuclei; 1 mark for a shared pair of electrons.
Question 3 (a) (ii)

Dot-and-Cross Diagram for Hydrazine (N₂H₄)

✅ Correct Answer

Each nitrogen atom has 5 outer electrons. They share one pair between the two N atoms, one pair with each of the two H atoms per nitrogen, leaving one lone pair on each nitrogen atom.

🧠 Exam Technique

  • Nitrogen electrons = crosses (×), Hydrogen electrons = dots (•).
  • Show the N-N single covalent bond clearly with one cross and one dot (or two crosses depending on atom choice).
  • Do not forget the non-bonding lone pairs on both nitrogen atoms!

❌ Common Errors

Failing to include the lone pairs on the nitrogen atoms, or drawing a double bond between the two nitrogen atoms resulting in pentavalent nitrogen.

Mark breakdown: 1 mark for fully correct dot-and-cross diagram showing outer electrons only.
Question 3 (a) (iii)

Estimating Bond Angles

✅ Correct Answer

107° (Acceptable range: 105° to 108°)

💡 Key Knowledge

Hydrazine has a tetrahedral electron-pair geometry around each nitrogen atom (3 bonding pairs, 1 lone pair). Because lone pairs repel more than bonding pairs, the normal 109.5° tetrahedral angle is compressed down to approximately 107° (similar to ammonia).

Mark breakdown: 1 mark for stating 107° (or an angle within the 105°-108° range).
Question 3 (b)

Solubility and Hydrogen Bonding

✅ Correct Answer

Hydrazine is very soluble because it forms hydrogen bonds with water molecules between the lone pairs on nitrogen/oxygen and the hydrogen atoms bonded to electronegative atoms (N or O).

🧠 Exam Technique

  • Labelled Diagram Description: Draw a water molecule interacting with hydrazine via a dashed line labelled "hydrogen bond" involving a H attached to N or O.
  • Include partial charges (δ+ and δ-) if helpful, and show the linear alignment of the hydrogen bond with the lone pair (approx. 180°).

❌ Common Errors

Labelling a covalent bond inside the molecule as a hydrogen bond, or failing to show the hydrogen bond connecting a hydrogen atom to a lone pair on a separate molecule.

Mark breakdown: 3 marks total (1 for mentioning hydrogen bonding between hydrazine and water; 1 for a diagram showing the H-bond between correct atoms; 1 for showing the lone pair and a bond angle of approximately 180° at the hydrogen bond site).
Question 3 (c)

Rocket Fuel Properties

✅ Correct Answer

Any two of the following valid reasons:

  • Large quantities of gases are produced from liquids, creating high pressure for thrust.
  • Formation of the exceptionally strong triple bond in N₂ releases a massive amount of energy (highly exothermic).
  • The reaction is very fast / self-igniting.
  • Hot gases expand rapidly.

💡 Key Knowledge

Look closely at the state symbols in the equation: N₂H₄(l) + 2H₂O₂(l) → N₂(g) + 4H₂O(g) . Going from liquids to exclusively gas products creates an enormous volumetric expansion.

❌ Common Errors

Simply stating "it is exothermic" without linking it to the specific thermodynamics (like the strong triple bond in nitrogen gas forming) or failing to reference the production of gases from liquids.

Mark breakdown: 2 marks total (1 mark per valid reason based on gas production and energy release/kinetics).

Topics

Physical Chemistry · Topic 2: Bonding and Structure

Question and mark scheme from the Edexcel A-Level Chemistry examination, AS Paper 1, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.