Edexcel A-Level Chemistry Paper 1, November 2020: Question 1
8 marks · Medium difficulty · Open Response
Identify equations for third ionisation energy, deduce group and element positions from ionisation energy tables and trends, determine isoelectronic ion formulae, and discuss why scandium and zinc are d-block elements but not transition metals using electronic configurations.
Practise this questionQuestion
Question text
1 (a) Which equation shows the third ionisation energy of aluminium?
(1)
A Al(g) → Al3+(g) + 3e−
B Al2+(g) → Al3+(g) + e−
C Al3+(g) + 3e− → Al(g)
D Al3+(g) + e− → Al2+(g)
(b) Which element in this table is in Group 2?
Ionisation energy / kJ mol−1
Element First Second Third Fourth
W 1086 2353 4621 6223
X 653 1592 2987 4740
Y 590 1145 4912 6474
Z 496 4563 6913 9544
(1)
A W
B X
C Y
D Z
(c) The graph shows the first ionisation energies (IE) of eight successive elements
from the first 20 elements in the Periodic Table.
Which letter represents the first ionisation energy of oxygen?
(e)
(b) (d)
(a)
(c)
1st IE / kJ mol−1
2 (g)
*P62668A0224*
(f ) (h)
Atomic number
(1)
A (a)
B (b)
C (c)
D (h)
(d) Give the formula of a stable ion that is isoelectronic with the
magnesium ion, Mg2+.
(1)
(e) A student stated that ‘the elements scandium and zinc are d-block elements but
are not transition metals’.
Discuss this statement, using appropriate electronic configurations to support
your answer.
(4)
… *P62668A0324*
(Total for Question 1 = 8 marks)
Mark scheme
Show the mark scheme
How to answer it
Ionisation Energies, Periodicity and Transition Metals
What this question tests
This question assesses core Inorganic and Physical Chemistry concepts: writing accurate ionisation energy equations including state symbols, deducing Group placement from successive ionisation energy data, interpreting first ionisation energy trends across periods using atomic numbers, identifying isoelectronic species, and explaining the formal definition of transition metals using electronic configurations.
Third Ionisation Energy Equation
✅ Correct Answer
B: Al²⁺(g) → Al³⁺(g) + e⁻
💡 Key Knowledge
- The $n$-th ionisation energy is the energy required to remove one electron from each atom or ion in one mole of gaseous ions to form one mole of gaseous ions with a higher positive charge.
- State symbols must always be (g) for gaseous species.
❌ Common Errors
- Choosing option A, which represents the overall sum of the first three ionisation energies combined into a single equation.
- Selecting options C or D, which incorrectly show electrons being gained (reduction/electron affinity) rather than removed.
Deduce Group Number from Successive Ionisation Energies
✅ Correct Answer
C (Element Y)
💡 Key Knowledge
- Look for a massive "jump" or large increase in successive ionisation energies. This indicates an electron is being removed from a new, inner quantum shell closer to the nucleus.
- For Element Y: First IE = 590, Second = 1145, Third = 4912. The huge leap between the 2nd and 3rd ionisation energy shows it has 2 electrons in its outer shell (Group 2).
🧠 Exam Technique
Calculate the ratio between successive values if unsure. A jump of 3x to 5x or more flags a change of shell. Element Z shows a huge jump between 1st and 2nd IE (496 to 4563), meaning Z is in Group 1.
First Ionisation Energy Periodic Trends (Oxygen)
✅ Correct Answer
C (letter c)
💡 Key Knowledge
- Oxygen (atomic number 8) follows nitrogen (atomic number 7, represented by b ).
- There is a characteristic drop in first ionisation energy from Group 5 (N) to Group 6 (O) due to electron-electron repulsion in the doubly-filled p -orbital.
❌ Common Errors
- Confusing the dip at Group 6 with the general upward trend. Note that c is lower than b , correctly depicting the drop for oxygen. Point a is carbon, b is nitrogen, and d is fluorine.
Isoelectronic Ion Formula
✅ Correct Answer
Any valid isoelectronic ion: N³⁻ , O²⁻ , F⁻ , Na⁺ , or Al³⁺
💡 Key Knowledge
- Isoelectronic means having the same number of electrons (and identical electronic configuration).
- Magnesium atom has 12 electrons; the Mg²⁺ ion has lost 2 electrons, leaving 10 electrons.
- Any stable ion with 10 electrons is accepted (e.g., O²⁻ or Na⁺ ).
❌ Common Errors
- Giving a neutral atom like Neon ( Ne ). The question explicitly asks for the formula of a stable ion.
- Writing incorrect charges or non-existent ions like C⁴⁻ or Si⁴⁺ .
D-block Elements vs Transition Metals Discussion
💡 Core Definitions
- d-block element: An element whose last added electron enters a d-subshell.
- Transition metal: A d-block element that forms at least one stable ion with an incomplete d-subshell/d-orbital.
✅ Required Marking Points (4 marks available)
- Point 1: Both Sc and Zn have their last added electron in a d-subshell (making them d-block elements).
- Point 2: Neither forms a stable ion with an incomplete d-subshell (disqualifying them as transition metals).
- Point 3: Scandium forms Sc³⁺ which has an empty d-subshell ( 1s² 2s² 2p⁶ 3s² 3p⁶ or [Ar] ).
- Point 4: Zinc forms Zn²⁺ which has a full d-subshell ( 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ or [Ar] 3d¹⁰ ).
❌ Common Pitfalls
- Simply stating that the elements "contain d-electrons" without specifying that the last added electron is in the d-subshell.
- Failing to explicitly link the electronic configuration of the stable ions ( Sc³⁺ and Zn²⁺ ) to the definition of a transition metal.
Topics
Physical Chemistry · Inorganic Chemistry · Topic 1: Atomic Structure and the Periodic Table · Topic 15: Transition Metals
Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 1, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.