Edexcel A-Level Chemistry Paper 3, November 2020: Question 4

10 marks · Medium difficulty · Calculations

Calculate enthalpy changes and construct an enthalpy level diagram for the hydration of copper(II) sulfate using experimental calorimetry data and Hess's law.

Practise this question

Question

A multi-part chemistry exam question about Hess's law and calorimetry. Part (a) asks to calculate the mass of 0.0250 mol of hydrated copper(II) sulfate. Part (b) gives an enthalpy change for the dissolution of hydrated copper(II) sulfate and asks for the temperature change. Part (c) includes an empty grid for an enthalpy level diagram representing the reactions of hydrated and anhydrous copper(II) sulfate with water, and part (c)(ii) asks to determine a reaction enthalpy from the diagram. Part (d) asks why the direct enthalpy change cannot be measured.
Question text

4 Hess’s law can be used to determine enthalpy changes for reactions which cannot be

obtained directly.

An example is the reaction of anhydrous copper(II) sulfate with water to form

hydrated copper(II) sulfate, CuSO4.5H2O.

The following outline procedure was carried out.

Step 1 42.75g of deionised water was weighed out in a polystyrene cup and the

temperature measured.

Step 2 0.0250mol of hydrated copper(II) sulfate was added to the water in the

polystyrene cup with stirring, making a total of 45.00g of water.

Step 3 The temperature change was recorded.

Step 4 Steps 1 to 3 were repeated using 45.00g of deionised water and

0.0250mol of anhydrous copper(II) sulfate.

(a) Calculate the mass of 0.0250mol of hydrated copper(II) sulfate, CuSO4.5H2O.

(2)

(b) The reaction of hydrated copper(II) sulfate with water is shown.

CuSO .5H O(s) + aq → CuSO (aq) ∆H = +18.2 kJ mol−1

42 4 1

Calculate the temperature change that would have given this enthalpy change for

the stated experimental procedure.

Give your answer to a measurable number of significant figures and state whether

the temperature increases or decreases.

−1 oC−1]

[Specific heat capacity of the solution = 4.18J g

(3)

(c) The reaction of anhydrous copper(II) sulfate with water is shown.

CuSO (s) + aq → CuSO (aq) ∆H = −84.5 kJ mol−1

44 2

(i) Draw to scale, on the graph paper, a labelled enthalpy level diagram which

shows the enthalpy changes for the reactions of water with hydrated

copper(II) sulfate (∆H1)and anhydrous copper(II) sulfate(∆H2).

(3)

*P62670A01132*

Arbitrary CuSO4(aq)

zero

(ii) Use your enthalpy level diagram in (c)(i) to determine the enthalpy change, ∆rH,

for the reaction

CuSO4(s) + 5H2O(l) → CuSO4.5H2O(s)

You must show your working on the diagram.

12 (1)

*P62670A01232*

∆rH …

(d) State why the enthalpy change for the reaction of one mole of

anhydrous copper(II) sulfate with five moles of water to form

hydrated copper(II) sulfate, CuSO4.5H2O, cannot be measured directly.

(1)

(Total for Question 4 = 10 marks)

Mark scheme

Show the mark scheme The mark scheme provides detailed answers and guidance for all parts of Question 4. Part (a) awards marks for molar mass and correct mass calculation (6.24 g). Part (b) outlines the calculation for Q and temperature change, resulting in 2.4 degrees Celsius decrease. Part (c)(i) shows an example of the completed enthalpy level diagram with properly labelled axes, correct arrows for enthalpy changes +18.2 and -84.5, and state symbols. Part (c)(ii) gives the Hess's law calculation resulting in -102.7 kJ mol^-1. Part (d) accepts that water cannot react in a controlled 1:5 ratio without side reactions or that temperature change cannot be measured for a solid.

How to answer it

Hess's Law and Enthalpy Changes Study Guide

📌 What this question tests

This question assesses core thermochemistry skills: calculating molar masses, applying calorimetry equations ( Q = mcΔT ), constructing accurate enthalpy level (Hess's Law) diagrams, and explaining experimental limitations regarding direct enthalpy measurement.

Question Part (a)

Calculating Mass from Moles

Calculate the mass of 0.0250 mol of hydrated copper(II) sulfate, CuSO₄·5H₂O. (2 marks)

✅ Correct Answer

Mᵣ(CuSO₄·5H₂O) = 63.5 + 32.1 + (16.0 × 4) + 5 × (1.0 × 2 + 16.0) = 249.6 g mol⁻¹

Mass = moles × Mᵣ = 0.0250 × 249.6 = 6.24 g (Accept 2 or 3 significant figures)

📐 Calculation Steps

  1. Find the molar mass (Mᵣ) of the hydrated salt by carefully including the 5 moles of water of crystallization.
  2. Multiply the number of moles (0.0250) by the calculated Mᵣ.
  3. Ensure correct units ( g ) are understood.

❌ Common Errors

  • Omitting the mass of the 5 water molecules ( 5H₂O ) in the Mᵣ calculation.
  • Rounding intermediate values too early, leading to slight inaccuracies in final mass.
Mark breakdown: 1 mark for correct molar mass; 1 mark for correct final mass calculation. (Allow Error Carried Forward from an incorrect Mᵣ).
Question Part (b)

Calorimetry and Temperature Change

Calculate the temperature change for the dissolution of hydrated copper(II) sulfate. State significant figures and whether it increases or decreases. (3 marks)

✅ Correct Answer

Q = ΔH × n = 18.2 kJ mol⁻¹ × 0.0250 mol = 0.455 kJ = 455 J

ΔT = Q / (m × c) = 455 / (45.00 × 4.18) = 2.4189... °C

Final Answer: 2.4 °C (or 2 °C), and state that the temperature decreases.

💡 Key Knowledge

  • ΔH₁ = +18.2 kJ mol⁻¹ is endothermic, meaning heat is absorbed from the solution, causing the temperature to drop.
  • Watch out for unit conversions: kJ must be converted to J by multiplying by 1000 before using Q = mcΔT .

🧠 Exam Technique

  • Significant figures: The data in the prompt uses 3 s.f. ( 18.2 , 45.00 , 4.18 ), so give your answer to 1 or 2 significant figures ( 2.4 °C or 2 °C ) as requested by the mark scheme.
  • Don't forget to explicitly state "decreases" to secure the final marking point.
Mark breakdown: 1 mark for evaluating Q; 1 mark for rearranging to find ΔT; 1 mark for correct significant figures (1 or 2 s.f.) and stating the temperature decreases.
Question Part (c)(i)

Enthalpy Level Diagram Construction

Draw to scale a labelled enthalpy level diagram for the reactions of water with hydrated and anhydrous copper(II) sulfate. (3 marks)

✅ Correct Answer Requirements

  • y-axis: Labelled clearly as "Enthalpy" or "H" with units ( kJ mol⁻¹ ) and an appropriate linear scale.
  • Entities & Levels: Place CuSO₄(s) + 5H₂O(l) at the top, CuSO₄(aq) in the middle, and CuSO₄·5H₂O(s) at the bottom.
  • Arrows & Values: Draw directed arrows showing ΔH₂ = -84.5 kJ mol⁻¹ downwards from solid anhydrous to aqueous, and ΔH₁ = +18.2 kJ mol⁻¹ upwards from hydrated solid to aqueous.

🧠 Exam Technique

  • Always use a ruler for energy levels and arrow lines.
  • Make sure arrowheads point strictly in the correct vertical direction (down for exothermic, up for endothermic).
  • Include state symbols ( s , l , aq ) for all chemical species.

❌ Common Errors

  • Omitting units on the enthalpy axis.
  • Placing the hydrated level above the anhydrous level (failing to reflect the relative exothermic/endothermic magnitudes).
  • Using double-headed arrows instead of single-headed reaction pathway arrows.
Mark breakdown: 1 mark for labelled y-axis with units; 1 mark for correct relative levels, directions, and values of ΔH₁ and ΔH₂; 1 mark for correct chemical entities with state symbols.
Question Part (c)(ii)

Applying Hess's Law

Use your enthalpy level diagram to determine the enthalpy change, ΔᵣH, for: CuSO₄(s) + 5H₂O(l) → CuSO₄·5H₂O(s). (1 mark)

✅ Correct Answer

ΔᵣH = ΔH₂ - ΔH₁ = -84.5 - (+18.2) = -102.7 kJ mol⁻¹ (Also accept -103 kJ mol⁻¹ )

💡 Hess's Law Route Analysis

According to Hess's Law, the total enthalpy change of a reaction is independent of the route taken. Going from CuSO₄(s) + 5H₂O(l) to CuSO₄(aq) releases 84.5 kJ mol⁻¹ ( ΔH₂ ), and reversing the hydration step removes 18.2 kJ mol⁻¹ ( ΔH₁ ).

Mark breakdown: 1 mark for correct application of Hess's Law calculation resulting in -102.7 kJ mol⁻¹ (or -103 kJ mol⁻¹ ). Working must be supported by the diagram.
Question Part (d)

Experimental Limitations

State why the enthalpy change for the direct reaction cannot be measured directly. (1 mark)

✅ Correct Answer

It is impossible to react exactly 5 moles of water with 1 mole of anhydrous copper(II) sulfate and measure the temperature change of a solid reaction mixture accurately.

❌ Common Errors & Rejections

  • Simply stating "heat loss to surroundings" (this applies to all calorimetry, but isn't the primary reason the direct hydration of a solid is impossible).
  • Stating "heat is needed to start the reaction" (incorrect, the reaction is spontaneous).
  • Vague statements about incomplete mixing without mentioning the specific stoichiometric water constraint (5:1 ratio).
Mark breakdown: 1 mark for stating that you cannot react exactly 5 moles of water with 1 mole of solid anhydrous salt / cannot measure temperature change for a solid.

Topics

Physical Chemistry · Core Practicals · Core Practical 8: Determine the enthalpy change of a reaction using Hess’s law · Topic 5: Formulae, Equations and Amounts of Substance · Topic 8: Energetics I

Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 3, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.