Edexcel A-Level Chemistry Paper 1, November 2021: Question 6

5 marks · Medium difficulty · Short Open Response

Explain why entropy change is positive and why a wooden block freezes to a flask in an endothermic reaction, and calculate standard molar entropy change.

Practise this question

Question

Question 6 about entropy. Part (a) shows a diagram of a flask containing hydrated barium hydroxide and ammonium thiocyanate placed on a few drops of water on a wooden block, which after stirring can lift the wooden block. Equation given is Ba(OH)2.8H2O(s) + 2NH4SCN(s) -> Ba(SCN)2(aq) + 2NH3(g) + 10H2O(l). Part (a)(i) asks for two reasons why Delta S system is positive (2 marks). Part (a)(ii) asks to explain why the wooden block is lifted up by the flask (2 marks). Part (b) gives a table of standard molar entropies for the reaction 2Mg(s) + O2(g) -> 2MgO(s) with values Mg(s) 32.7, O2(g) 205.0, MgO(s) 26.9, and four multiple-choice options A (+210.8), B (-210.8), C (+216.6), D (-216.6) (1 mark).
Question text

6 This question is about entropy.

(a) Some hydrated barium hydroxide is added to ammonium thiocyanate in a flask

which is placed on a few drops of water on a wooden block. After the addition,

the contents are stirred and then the flask can be lifted up with the wooden block

attached, as shown.

hydrated barium

hydroxide flask with

mixed contents

ammonium

thiocyanate wooden

water

block

wooden

block

table table

The equation for the reaction is

Ba(OH)2.8H2O(s) + 2NH4SCN(s) → Ba(SCN)2(aq) + 2NH3(g) + 10H2O(l)

(i) Give two reasons why you would expect ΔS d to be positive.

system

(2)

(ii) Explain why the wooden block is lifted up by the flask.

(2)

(b) What is the standard molar entropy change, ΔS d , in J K–1 mol–1, for the reaction shown?

system

2Mg(s) + O2(g) → 2MgO(s)

Substance Standard molar entropy, S d / J K–1 mol–1

Mg(s) 32.7

O*P65463A01428*2(g)205.0

MgO(s) 26.9

(1)

A +210.8

B –210.8

C +216.6

D –216.6

(Total for Question 6 = 5 marks)

Mark scheme

Show the mark scheme Mark scheme for question 6. Part (a)(i) awards 1 mark for increase in number of moles and 1 mark for change of state producing gas/liquid/solution from solids. Part (a)(ii) awards 1 mark for stating the reaction is endothermic and 1 mark for explaining it freezes the water attaching the block. Part (b) gives the correct answer as D (-216.6) with explanatory notes for why other options are incorrect.

Question

Answer Additional Guidance Mark

Number

6(a)(i) An answer that makes reference to the following points: (2)

• there is an increase of number of moles (1) Allow particles for moles

3 to 13 moles

Do not award 11 to 13 moles

Do not award reference to ‘more types’ of

products than reactants

• change of state as gas / liquid / solution are produced from Ignore references to ∆H

solids (1)

Question

Answer Additional Guidance Mark

Number

6(a)(ii) An explanation that makes reference to the following points: (2)

• the reaction is endothermic (1) Allow description of endothermic

• (and so) freezes the water (which attaches the wooden block to

the flask) (1)

Question

Answer Mark

Number

6(b) The only correct answer is D (-216.6) (1)

A is not correct because the values for magnesium and magnesium oxide have not been doubled and the

entropy for the products has been incorrectly subtracted from the reactants entropy

B is not correct because the values for magnesium and magnesium oxide have not been doubled

C is not correct because the entropy for the products has been incorrectly subtracted from the entropy of the

reactants

(Total Question 6 = 5 marks)

How to answer it

A-Level Chemistry Study Guide: Entropy

What this question tests

This question assesses your understanding of system entropy changes (ΔS_system), the factors that influence entropy (such as moles of particles and changes of state), linking thermodynamic feasibility observations to practical contexts (endothermic processes freezing water), and applying the standard molar entropy formula using correct stoichiometric balancing multipliers.

Question 6 (a)(i)

Predicting the sign of ΔS_system

✅ Correct Answer

Two reasons required for the 2 marks:

  • There is an increase in the number of moles of particles (from 3 moles of solid reactants to 13 moles of products).
  • There is a change of state producing gases, liquids, and aqueous solutions from solid reactants.

💡 Key Knowledge

Entropy measures the dispersal of thermal energy within a system. Systems that lead to more ways of arranging particles and energy quanta (more disorder) experience a positive entropy change. Gaseous states and larger numbers of moles significantly increase entropy.

🧠 Exam Technique

Always count moles carefully from the balanced equation: 1 Ba(OH)₂·8H₂O(s) + 2 NH₄SCN(s) gives 3 moles of solid on the left, turning into 1 + 2 + 10 = 13 moles of products on the right. Explicitly state both mole increase and state changes to secure both independent marks.

❌ Common Errors

Students lose marks by vague statements like "there are more types of products". Avoid referencing enthalpy change (ΔH) when explaining entropy changes. Note that examiners accept particle counts ranging from 3 to 13, but do not award credit if you write absolute statements like "11 to 13 moles".

Mark breakdown: (2) total - 1 mark for increase in moles, 1 mark for change of state producing gas/liquid/solution from solids.

Question 6 (a)(ii)

Explaining the Physical Observation (Wooden Block Freezing)

✅ Correct Answer

The explanation must state:

  • The reaction is endothermic (absorbs thermal energy from its surroundings).
  • This causes the water drops on the wooden block to freeze, gluing the block to the flask.

💡 Key Knowledge

Endothermic reactions absorb heat from the immediate surroundings, causing a dramatic temperature drop. When water reaches 0 °C under a cold reaction vessel, phase change occurs from liquid water to solid ice.

🧠 Exam Technique

Link thermodynamic concepts directly to macroscopic observations. Use clear cause-and-effect language: "Because the reaction absorbs heat, the surroundings cool down, which freezes the water..."

❌ Common Errors

Confusing endothermic and exothermic directions. Simply stating "the temperature drops" without explicitly mentioning that the reaction is endothermic or missing the link to the water freezing will cause you to drop marks.

Mark breakdown: (2) total - 1 mark for identifying the reaction as endothermic, 1 mark for linking this to the freezing of water attaching the block.

Question 6 (b)

Calculating Standard Molar Entropy Change

✅ Correct Answer

D (-216.6 J K⁻¹ mol⁻¹)

📐 Calculation Steps

  1. Formula: ΔS_system = ΣS(products) - ΣS(reactants)
  2. Products: 2 moles of MgO(s) = 2 × 26.9 = 53.8 J K⁻¹ mol⁻¹
  3. Reactants: (2 × S(Mg)) + S(O₂) = (2 × 32.7) + 205.0 = 65.4 + 205.0 = 270.4 J K⁻¹ mol⁻¹
  4. Subtract: 53.8 - 270.4 = -216.6 J K⁻¹ mol⁻¹

🧠 Exam Technique

Always write down the full equation including stoichiometric coefficients before plugging in values. Double-check that you multiply individual standard molar entropies by the large numbers in front of the chemical species in the balanced equation.

❌ Common Errors

Option A (-210.8) occurs if you forget to multiply by 2 for Mg and MgO and subtract backwards. Option B (-210.8) happens if you omit the stoichiometric multipliers for magnesium terms. Option C (+216.6) is the classic trap of doing reactants minus products instead of products minus reactants.

Mark breakdown: (1) total for selecting option D.

Topics

Physical Chemistry · Topic 13: Energetics II

Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 1, November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.