Edexcel A-Level Chemistry Paper 3, June 2023: Question 5
12 marks · Hard difficulty · Open Response
Construct electrochemical cells, use electrode potentials to determine reaction feasibility, and explain electron flow and redox processes in a hydrogen-oxygen fuel cell.
Practise this questionQuestion
Question text
5 This question is about electrochemical cells.
(a) A diagram is shown of the apparatus that is used to measure the emf of a cell
with a zinc/zinc(II) electrode and an acidified manganese(II)/manganate(VII)
electrode system.
Complete the labels Y and Z by naming the substances needed.
Temperature and concentrations are not required.
(3)
voltmeter
V
Zn
salt bridge
Y …
Z …
solution of …
zinc nitrate (aq)
(b) Excess zinc is added to an acidified solution of sodium dichromate(VI).
Some electrode data are given in the table.
Electrode system E d / V
Cr2+(aq) + 2e– Cr(s) –0.91
Cr3+(aq) + e– Cr2+(aq) –0.41
½Cr O2–(aq) + 7H+(aq) + 3e– Cr3+(aq) + 3½H O(l) +1.33
27 2
Zn2+(aq) + 2e– Zn(s) –0.76
Explain, using only the data in the table, the final oxidation state of chromium
that is formed when zinc is added to acidified dichromate(VI) ions.
Include E d values where appropriate. Equations are not required.
cell
(5)
… *P71914A01132*
(c) A cell diagram is shown.*P71914A01232*
Ni(s) ½ Ni2+(aq) ½½ [NO–(aq) + 2H+(aq)], [NO (g) + H O(l)] ½ Pt(s) E d = +1.06 V
32 2 cell
Deduce the reduction half-equation.
State symbols are not required.
(1)
(d) State the direction of the electron flow in the hydrogen-oxygen fuel cell shown.
Justify your answer by reference to the redox processes in the cell.
hydrogen
acidic electrolyte
negative electrode
membrane cell load
positive electrode
water oxygen
(2)
(e) State one advantage of the hydrogen-oxygen fuel cell over the use of petrol as
fuel in a vehicle.
(1)
(Total for Question 5 = 12 marks)
Mark scheme
Show the mark scheme
Question
Answer Additional Guidance Mark
Number
5(a) An answer which makes reference to the following points: Names or formulae accepted but if both given then (3)
both must be correct
All three are standalone marks
• (Y) platinum / Pt (1) Ignore reference to (platinum) black
(Z)
• manganese(II) nitrate / Mn(NO3)2 Allow MnSO4
and
potassium manganate(VII) / KMnO4 (solution) (1) Allow sodium manganate(VII)/ NaMnO4
Allow potassium permanganate for KMnO4
Oxidation numbers essential if only the names are
given
• sulfuric acid (1) Allow nitric acid
Do not award use of hydrochloric acid
Ignore concentrations throughout
Penalise use of hydrochloric acid or manganese
halides once only
Question
Answer Additional Guidance Mark
Number
5(b) An explanation that makes reference to the following points: (5)
• (chromium(VI) reduced to) chromium +2 / (II) (1) Allow Cr2+
Allow TE on candidate EƟ values, e.g. all
cell
EƟ values positive then Cr(0) is the result
cell
because
Ɵ EƟ = (+1.33 − −0.76 =) (+) 2.09 (V)
• E cell value for the reduction of chromium(VI) to chromium(III) (1) cell
Ɵ EƟ = (−0.41 − −0.76 =) (+) 0.35 (V)
• E cell value for the reduction of chromium(III) to chromium(II) (1) cell
Ɵ EƟ = (−0.91 − −0.76 =) −0.15 (V)
• E cell value for the reduction of chromium(II) to chromium (1) cell
• first two reductions occur (because EƟcell is positive in both cases) Accept feasible for occur
and
final reaction does not occur (because EƟ is negative) (1) Ignore equations even if incorrect
cell
Penalise reference to Zn2+ reacting in the written
answer once only for M2 and M3
Question
Answer Additional Guidance Mark
Number
5(c) Example of equation (1)
• half-equation NO − + 2H+ + e(−) → NO + H O
32 2
Allow multiples / ⇌
Ignore state symbols even if incorrect
Question
Answer Additional Guidance Mark
Number
5(d) An answer that makes reference to the following points: (2)
• (electrons move) from the negative to the positive electrode (1) Allow annotation on diagram, see below
Allow move from the top electrode to the bottom
electrode
Ignore just electrons move down/clockwise
Do not allow movement through the middle of the fuel
cell
Allow anode for negative electrode and cathode for
positive electrode
• (because) the hydrogen is being oxidised / losing electrons Allow half-equations such as
and the oxygen is being reduced / gaining electrons (1) (Oxidation) H → 2H+ + 2e(−)
and
(Reduction) ½O +2H+ + 2e(−) → H O
Do not award formation of O2− ions
M2 is not dependent on M1
Question
Answer Additional Guidance Mark
Number
5(e) An answer which makes reference to any one of the following points (1)
• harmless product/water compared to pollutants Accept named pollutants e.g. CO/CO2/SO2/NOx
Allow hydrogen fuel cell only produces water
or
less reliant on fossil fuels/non-renewable fuels Allow hydrogen (fuel) is renewable/sustainable
Allow no use of fossil fuels
or Allow less/no green house gases produced
more efficient energy production Ignore just ‘more efficient’
or
(can be) smaller and lighter fuel
cell
(Total Question 5 = 12 marks)
How to answer it
Electrochemical Cells Study Guide
What this question tests
This comprehensive question assesses your understanding of electrochemical cells, standard cell diagrams, predicting redox feasibility using standard electrode potentials (E-theta values), identifying sequential reduction steps, interpreting fuel cell schematics, and evaluating the environmental benefits of hydrogen-oxygen fuel cells.
Part (a): Setting up an Electrochemical Cell
Labelling a manganese(II)/manganate(VII) half-cell
✅ Correct Answers
- Y: Platinum / Pt (electrode)
- Z: Manganese(II) nitrate / Mn(NO₃)₂ AND Potassium manganate(VII) / KMnO₄ (solution)
- Acid: Sulfuric acid (H₂SO₄)
💡 Key Knowledge
- A platinum electrode is required because both the oxidized and reduced species in the half-cell are aqueous ions (solution phase), meaning they cannot act as an electrical contact themselves.
- The half-cell requires both Mn²⁺ ions and MnO₄⁻ ions alongside a source of H⁺ ions to function.
❌ Common Errors
- Using hydrochloric acid instead of sulfuric acid (Cl⁻ ions would be undesirably oxidized by manganate(VII)).
- Omitting either of the required ionic components for solution Z. Both manganese(II) and manganate(VII) must be present.
🧠 Exam Technique
- Names or chemical formulae are both accepted by examiners, but ensure formulas have correct ionic charges if used.
- Concentrations do not need to be specified unless standard conditions are explicitly demanded.
Part (b): Feasibility and Sequential Reductions
Determining the final oxidation state of chromium with excess zinc
✅ Correct Answer & Mark Breakdown (5 Marks)
- Final State: Chromium(II) / Cr²⁺ (1 mark)
- Step 1 (Cr(VI) to Cr(III)): E-theta cell = (+1.33) - (-0.76) = +2.09 V (Positive, feasible) (1 mark)
- Step 2 (Cr(III) to Cr(II)): E-theta cell = (-0.41) - (-0.76) = +0.35 V (Positive, feasible) (1 mark)
- Step 3 (Cr(II) to Cr(0)): E-theta cell = (-0.91) - (-0.76) = -0.15 V (Negative, not feasible) (1 mark)
- Conclusion link: First two reductions occur because E-theta cell is positive, but the final reduction does not occur because E-theta cell is negative. (1 mark)
📐 Step-by-Step E-theta Calculation Strategy
- Calculate E-theta cell = E-theta (reduction) - E-theta (oxidation) for each successive half-equation. Remember that zinc acts as the reducing agent and is itself oxidized (E-theta = -0.76 V).
- Check if the calculated E-theta cell value is positive (indicating a feasible reaction).
- Stop the sequence when the calculated E-theta cell value becomes negative.
❌ Common Errors
- Forgetting to test the final step (Cr²⁺ to Cr) and incorrectly assuming all transition metal ions are reduced completely to metal atoms.
- Incorrectly subtracting electrode potential values, leading to wrong signs for E-theta cell.
🧠 Exam Technique
- You must quote the specific E-theta cell values for each stage to gain full credit. Simply stating "the numbers are positive" will not score top marks.
Part (c): Cell Diagrams to Half-Equations
Deducing the reduction half-equation from cell notation
✅ Correct Answer
NO₃⁻ + 2H⁺ + e⁻ ⇌ NO₂ + H₂O (or using = )
💡 Key Knowledge
In standard cell representations, the right-hand side of the double vertical line ( || ) represents the reduction process (cathode). You must balance the half-equation using electrons and hydrogen ions as indicated by the species present in the diagram.
❌ Common Errors
- Including state symbols when the question explicitly states: "State symbols are not required."
- Incorrect stoichiometry for electrons or protons.
🧠 Exam Technique
Multiples of the balanced equation are accepted as long as all stoichiometric coefficients are correctly proportioned.
Part (d): Fuel Cell Electron Flow & Redox
Explaining electron movement and redox processes in a hydrogen-oxygen fuel cell
✅ Correct Answers
- Direction: Electrons move from the negative electrode to the positive electrode through the external circuit. (1 mark)
- Justification: Hydrogen is oxidized (loses electrons) at the negative electrode, while oxygen is reduced (gains electrons) at the positive electrode. (1 mark)
💡 Key Knowledge
- Negative electrode (Anode): H₂ → 2H⁺ + 2e⁻
- Positive electrode (Cathode): ½O₂ + 2H⁺ + 2e⁻ → H₂O
❌ Common Errors
- Stating that electrons flow through the internal membrane (electrons cannot cross the proton-exchange membrane; only ions do).
- Mixing up oxidation and reduction locations.
🧠 Exam Technique
To secure both marks, link the physical direction of flow directly to the chemical terms oxidation and reduction.
Part (e): Advantages of Hydrogen-Oxygen Fuel Cells
Evaluating green energy alternatives to petrol combustion
✅ Correct Answers (Any one of)
- Produces harmless products / water only (compared to toxic exhaust pollutants like CO, CO₂, NOₓ, or unburned hydrocarbons).
- Less reliant on finite fossil fuels / renewable energy source.
- More efficient energy production.
- Can be smaller and lighter as a power unit.
❌ Common Errors
- Vague answers such as just saying "more efficient" without context (though "more efficient energy production" is credited, simple single-word descriptions lack rigor).
- Ignoring that hydrogen production itself can require fossil fuels unless specified as green hydrogen. Stick closely to the mark scheme points regarding the vehicle operation.
Topics
Physical Chemistry · Core Practicals · Core Practical 10: Construct electrochemical cells and measure electrode potentials · Topic 14: Redox II
Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 3, June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.