Edexcel A-Level Chemistry AS Paper 2, June 2024: Question 6
7 marks · Medium difficulty · Practical Techniques and Data Analysis
Analyse the disappearing cross reaction between sodium thiosulfate and hydrochloric acid to determine reaction rate and the effect of concentration.
Practise this questionQuestion
Question text
6 Sodium thiosulfate solution reacts with aqueous hydrochloric acid as shown.
Na2S2O3 + 2HCl → S + SO2 + H2O + 2NaCl
During the reaction the mixture becomes cloudy.
A student carried out an investigation to determine the effect of the concentration of
sodium thiosulfate on the rate of the reaction.
Procedure
Step 1 Place 10 cm3 of a solution of sodium thiosulfate and 40 cm3 of deionised water
in a clean 200 cm3 conical flask.
Step 2 Place the flask on a piece of paper with a black cross marked on it.
Step 3 Add 20 cm3 of hydrochloric acid (an excess) to the flask, swirl the solution and
start a timer.
Step 4 Look down through the solution at the black cross and record the time taken
for the cross to no longer be visible through the solution.
Step 5 Calculate 1/time to find the average rate of reaction.
Step 6 Change the concentration of sodium thiosulfate by repeating
Steps 1–5 using different volumes of the sodium thiosulfate solution and
deionised water.
Apparatus
reaction mixture
paper marked with cross
(a) State why the reaction mixture becomes cloudy.
(1)
(b) A student carried out the investigation using five different concentrations of
sodium thiosulfate solution.
20 Experiment 1 2 3 4 5
Volume of Na2S2O3*P76894A02032*solution added in Step1/ cm31020 30 40 50
Volume of water added in Step 1 / cm3 40 30 20 10 0
Volume of hydrochloric acid added in Step 3 / cm3 20 20 20 20 20
Concentration of Na2S2O3 immediately after
–3 0.03 0.06 0.09 0.12 0.15
adding the acid in Step 3 / mol dm
(i) What was the concentration, in mol dm–3, of the original solution of
sodium thiosulfate?
(1)
A 0.03
B 0.15
C 0.21
D 0.71
(ii) State why water is added in Experiments 1 to 4, but not in Experiment 5.
(1)
(c) The student plotted a graph of 1/time against concentration of
sodium thiosulfate.
0.05
0.04
0.03
1/time
/ s–1
0.02
0.01 *P76894A02132*
0.00
0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 0.16
Concentration of Na S2O3 in the reaction mixture / mol dm–3
(i) Calculate, using the graph, the time taken for the cross to be obscured using
a concentration of sodium thiosulfate of 0.10 mol dm–3.
(1)
(ii) State and justify the relationship between the rate of reaction and the
concentration of sodium thiosulfate as shown by the graph.
(1)
(d) Which will decrease the accuracy of the experiment?
(1)
22 A rinsing the flask with deionised water before each new experiment
B stirring the solution throughout each experiment*P76894A02232*
C using a different 50 cm3 measuring cylinder for each solution
D using the same piece of paper in each experiment
(e) Experiment 1 is repeated at the same temperature, but using a 100 cm3
conical flask in place of the 200 cm3 flask.
Which statement is correct about the repeated experiment?
(1)
A it is not possible to predict how the time taken will be affected
B the time taken will decrease using the 100 cm3 flask
C the time taken will increase using the 100 cm3 flask
D the time taken will be the same using the 100 cm3 flask
(Total for Question 6 = 7 marks)
Mark scheme
Show the mark scheme
Question
Answer Additional Guidance Mark
Number
6(a) An answer that makes reference to the following point: (1)
• sulfur is insoluble in water / precipitates Allow sulfur forms a yellow solid / comes out of solution /
does not dissolve
Allow just ‘sulfur is formed’
Question
Answer Mark
Number
6(b)(i) The only correct answer is C (0.21) (1)
A is not correct because this is the concentration in the first experiment which is diluted with water and acid
B is not correct because this is the concentration in the most concentrated of the experiments and is diluted with acid
D is not correct because this is the ratio of the volumes of thiosulfate and total volume in the reaction = 5/7
Question
Answer Additional Guidance Mark
Number
6(b)(ii) An answer that makes reference to the following point: (1)
• so that the total volume of the reaction mixture Accept the volume of sodium thiosulfate and water is kept
is kept constant / 70 cm3 constant / 50 cm3
Allow the same volume of 70 cm3 / 50 cm3
Question
Answer Additional Guidance Mark
Number
6(c)(i) Example of calculation (1)
• find the value of 1/time for the concentration of 1/time = 0.03 (s‒1)
0.10 mol dm‒3
and
calculates time time = 1 ÷ 0.03 = 33.3 / 33.333 (s)
Ignore SF except 1SF
Allow ± ½ small square so range can be up to
time = 1 ÷ 0.0305 = 32.79 / 32.8 (s)
Question
Answer Additional Guidance Mark
Number
6(c)(ii) An answer that makes reference to the following point: (1)
• (directly) proportional Allow just directly proportional
and Allow as concentration doubles rate doubles
because the graph is a straight line (which passes Allow linear
through the origin) Ignore increasing concentration increases rate
Question
Answer Mark
Number
6(d) The only correct answer is A (rinsing the flask with deionised water before each new experiment) (1)
B is not correct because any effect on the rate of the reaction will be equal in each case
C is not correct because each cylinder is the same size so will measure with the same accuracy
D is not correct because this will not affect the rate of the reaction
Question
Answer Mark
Number
6(e) The only correct answer is B (the time taken will decrease using the 100 cm3 flask) (1)
A is not correct because the depth of the solution has increased so more solid is between the eye and the cross
C is not correct because the depth of the solution has increased so more solid is between the eye and the cross
D is not correct because the depth of the solution has increased so more solid is between the eye and the cross
(Total for Question 6 = 7 marks)
How to answer it
Rates of Reaction: Sodium Thiosulfate & Hydrochloric Acid
This question assesses practical and mathematical competencies in chemical kinetics, including:
- Identifying the chemical product responsible for turbidity (precipitate formation).
- Dilution calculations using volume and concentration relationships ( C₁V₁ = C₂V₂ ).
- Understanding control variables in reaction rate experiments (maintaining constant depth/volume).
- Interpreting graphical rate data ( 1/time against concentration) and justifying mathematical relationships.
- Evaluating procedural errors and apparatus modifications (path length and light obstruction).
Why the Reaction Mixture Becomes Cloudy
Identifying products and state changes [1 Mark]
✅ Correct Answer
Sulfur is formed, which is insoluble in water / precipitates as a solid.
💡 Key Knowledge
Of all four reaction products, only elemental sulfur ( S ) is insoluble in water. It forms a pale yellow precipitate that suspended in solution causes light scattering (cloudiness).
❌ Common Errors
Stating that "sulfur dioxide gas causes bubbles/cloudiness". SO₂ is a soluble toxic gas; only the solid sulfur precipitate causes turbidity.
Original Concentration of Sodium Thiosulfate
Dilution calculation from reaction mixture data [1 Mark]
📐 Step-by-Step Calculation
- Identify total volume in any experiment:
For Exp 5: V(thiosulfate) = 50 cm³, V(water) = 0 cm³, V(acid) = 20 cm³.
Total volume = 50 + 0 + 20 = 70 cm³. - Use the dilution equation:
C₁ × V₁ = C₂ × V₂
C(original) × 50 cm³ = 0.15 mol dm⁻³ × 70 cm³ - Solve for initial concentration:
C(original) = (0.15 × 70) / 50 = 10.5 / 50 = 0.21 mol dm⁻³
✅ Correct Answer
C (0.21 mol dm⁻³)
❌ Common Distractor Traps
- A (0.03): Concentration of Exp 1 after dilution by both water and acid.
- B (0.15): Concentration of Exp 5 after adding the 20 cm³ acid. Students forget the acid also dilutes the stock solution!
- D (0.71): Incorrect volume ratio inversion ( 50 / 70 = 0.71 ).
Purpose of Adding Water in Experiments 1 to 4
Controlling experimental variables [1 Mark]
✅ Correct Answer
To keep the total volume of the reaction mixture constant (at 70 cm³) across all experiments.
🧠 Exam Technique
Always state what is being kept constant and why. If the volume varied, the concentration of the acid and the depth of the liquid would also change, introducing multiple uncontrolled variables.
❌ Common Errors
Vague answers such as "to dilute the solution" or "to make it a fair test" without specifying that volume is the variable being kept constant.
Calculate Time Taken from the Rate Graph
Graph reading and reciprocal relationship [1 Mark]
📐 Step-by-Step Calculation
- Locate 0.10 mol dm⁻³ on the x-axis:
Read vertically up to the line of best fit. - Read the corresponding y-axis value:
1/time = 0.030 s⁻¹ (allow ±½ square: 0.0300 to 0.0305 s⁻¹). - Calculate the time taken (t):
time = 1 / (1/time) = 1 / 0.030 = 33.3 s
(Range: 32.8 s to 33.3 s).
✅ Correct Answer
33.3 s (accept 33 s, 33.33 s, or range 32.8 to 33.3 s)
❌ Common Calculation Traps
- Forgetting to invert: Quoting the y-axis reading 0.03 directly as the time!
- Rounding incorrectly: Truncating to 1 significant figure ( 30 s ) loses the mark. Standard guidance permits 2 or 3 sig figs.
Relationship Between Rate and Concentration
Mathematical interpretation of the graph [1 Mark]
✅ Correct Answer
Rate is directly proportional to concentration because the graph is a straight line passing through the origin (0,0).
🧠 Exam Technique: "State and Justify"
Two essential elements are required for a complete answer:
- State: "Directly proportional" (first order).
- Justify: Must mention both that it is a straight line AND it passes through the origin.
❌ Insufficient Responses
Writing "as concentration increases, rate increases" only describes a positive correlation, NOT direct proportionality. This scores 0 marks.
Source of Experimental Inaccuracy
Evaluating laboratory procedure [1 Mark]
✅ Correct Answer
A (rinsing the flask with deionised water before each new experiment)
💡 Why Option A Decreases Accuracy
Rinsing leaves residual water droplets inside the flask. This unmeasured extra water dilutes the reaction mixture in subsequent runs, altering the intended concentrations and decreasing accuracy.
❌ Why Other Options Are Incorrect
- B (stirring continuously): Improves mixing consistency and ensures homogeneity across all runs.
- C (different cylinders): Prevents cross-contamination between reagents.
- D (same paper): Ensures the darkness/thickness of the cross remains a strictly controlled visual standard.
Effect of Flask Size on Reaction Time
Apparatus geometry and optical depth [1 Mark]
✅ Correct Answer
B (the time taken will decrease using the 100 cm³ flask)
💡 The Physics of the "Disappearing Cross"
A smaller conical flask (100 cm³ vs 200 cm³) has a narrower base.
- The same total volume of liquid (70 cm³) will reach a greater depth (height).
- Looking down from above, the light must pass through a longer path length of solution.
- Fewer sulfur particles per unit volume are required to obscure the cross, so the cross disappears sooner (shorter time).
❌ Common Misconception
Thinking that because the quantities/concentrations are identical, the time taken must be the same (Option D). Flask geometry directly dictates liquid column height!
Topics
Physical Chemistry · Topic 9: Kinetics I · Topic 5: Formulae, Equations and Amounts of Substance
Question and mark scheme from the Edexcel A-Level Chemistry examination, AS Paper 2, June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.