Edexcel A-Level Chemistry Paper 3, June 2025: Question 1
7 marks · Medium difficulty · Open Response
Define first ionisation energy, deduce the group to which elements X, Y, and Z belong using successive ionisation energy data, and explain which element has the highest atomic number.
Practise this questionQuestion
Question text
1 This question is about ionisation energies.
The table shows the first four ionisation energies of three elements in the same group
of the Periodic Table.
The letters used are not the symbols of the elements.
First ionisation Second ionisation Third ionisation Fourth ionisation
Element energy energy energy energy
/ kJ mol−1 / kJ mol−1 / kJ mol−1 / kJ mol−1
X 403 2632 3900 5080
Y 419 3051 4412 5877
Z 496 4563 6913 9544
(a) State what is meant by the term ‘first ionisation energy’.
(2)
(b) Explain to which group the elements X, Y and Z belong.
(2)
(c) Explain which of the elements X, Y and Z has the highest atomic number.
(3)
… *P77834A0236*
(Total for Question 1 = 7 marks)
Mark scheme
Show the mark scheme
Question
Answer Additional Guidance Mark
Number
1(a) An answer that makes reference to the following points: (2)
• energy (required) to remove / lose 1 (1) Allow e(−) for electron
electron / first electron / last electron from
an / each atom (of an element)
• in 1 mol (e) of gaseous atoms (to form 1 mol (1)
of positive ions)
1 mol(e) must be referenced in either M1 or M2
to score both marks
e.g. ‘energy to remove 1 mol of electrons from
gaseous atoms’ scores 2 marks
Correct example symbol or generic equation, for
first IE, including state symbols scores 1 mark
e.g. X(g) → X+(g) + e(–) / X(g) – e(–) → X+(g)
Ignore references to standard conditions /
standard states
Question
Answer Additional Guidance Mark
Number
1(b) An explanation that makes reference to the following points: Allow there is a very large increase in 2nd IE (2)
• as there is a large difference / large increase / (1)
(large) jump / in ionisation energy between first and
second ionisation energy / after first ionisation energy /
before second ionisation energy Allow alkali metal
• Group 1 (1) M2 dependent on M1
Ignore reference to the subshell / orbital of the
(outer) electron even if incorrect
Question
Answer Additional Guidance Mark
Number
1(c) An explanation that makes reference to the following points: Penalise ionic radius once only (3)
• element X as it has the lowest (first) ionisation energy
(1) Allow X as the (first) ionisation energy
decreases down the group
Do not award reference to other ionisation
• as electron removed is furthest from nucleus energies (unless all are mentioned as being
lower)
(1)
Allow ‘outer electron’ for ‘electron removed’
Allow atomic radius is greater
Ignore more shells
• so there is greater shielding (even though there is an Do not award ionic radius
increase in the number of protons)
(1)
Allow greater repulsion from inner electron
shells
Allow 1 mark for there is less attraction
between the nucleus and the outer electron if
neither M2 or M3 is awarded.
Allow 1 mark for ‘Z, because the nuclear
charge / number of protons is the greatest’
Ignore effective nuclear charge
(Total for Question 1 = 7 marks)
How to answer it
Successive Ionisation Energies & Group Trends
This question evaluates your foundational understanding of atomic structure and periodic trends:
- Precision in definitions: Recalling the strict, unambiguous textbook definition of first ionisation energy.
- Analysing successive IE data: Identifying large energy jumps to deduce valence electron configuration and group number.
- Down-group periodic trends: Explaining variations in nuclear attraction using atomic radius, shielding, and nuclear charge.
Provided Exam Data
| Element | 1st IE / kJ mol⁻¹ | 2nd IE / kJ mol⁻¹ | 3rd IE / kJ mol⁻¹ | 4th IE / kJ mol⁻¹ |
|---|---|---|---|---|
| X | 403 | 2632 | 3900 | 5080 |
| Y | 419 | 3051 | 4412 | 5877 |
| Z | 496 | 4563 | 6913 | 9544 |
Definition of First Ionisation Energy
State what is meant by the term 'first ionisation energy'.
✅ Model Answer
The energy required to remove one electron from each atom in one mole of gaseous atoms (to form one mole of gaseous 1+ ions).
• [1 mark]: Energy needed to remove 1 electron from each atom.
• [1 mark]: In 1 mole of gaseous atoms.
Note: Mentioning "1 mole" in either statement is compulsory to unlock both marks.
🧠 Exam Technique & Equation Fallback
- Always include key terms: "Energy required", "1 mole", "gaseous", and "atoms".
- Symbolic representation: A fully correct state-annotated equation scores 1 mark if your text definition is incomplete:
X(g) → X⁺(g) + e⁻ - Do not mention standard conditions; ionisation energy is defined strictly in the gas phase.
❌ Common Errors
- Missing the state: Writing "from an atom" instead of "from a gaseous atom".
- Confusing quantities: Writing "molecules" instead of "atoms".
- Omitting the mole: Saying "energy to remove one electron from a gaseous atom" only secures 1 of the 2 marks.
Deducing the Group Number
Explain to which group the elements X, Y and Z belong.
✅ Model Answer
- There is a large jump (large increase) between the first and second ionisation energies for all three elements.
- Therefore, elements X, Y and Z belong to Group 1 (alkali metals).
• [1 mark]: Identifying the large increase between the 1st and 2nd IE.
• [1 mark]: Stating Group 1 (dependent on identifying the jump).
💡 Key Knowledge
A massive jump in ionisation energy occurs when an electron is removed from a new principal quantum shell closer to the nucleus with significantly less shielding. Since only 1 electron is easily removed before the jump, there is 1 valence electron, placing the elements in Group 1.
🧠 Exam Technique
Always state between which successive values the jump occurs. Never just say "there is a big jump in the numbers". You must specify: "between the 1st and 2nd ionisation energy".
Determining Relative Atomic Number Down a Group
Explain which of the elements X, Y and Z has the highest atomic number.
✅ Model Answer
- Element X has the highest atomic number because it has the lowest first ionisation energy (403 kJ mol⁻¹).
- Its outer electron is furthest from the nucleus (largest atomic radius / most electron shells).
- There is greater shielding from inner shells, which outweighs the increase in nuclear charge, resulting in weaker nuclear attraction for the outer electron.
• [1 mark]: Identifies Element X due to having the lowest 1st IE (IE decreases down the group).
• [1 mark]: Outer electron is furthest from the nucleus (greater atomic radius / more shells).
• [1 mark]: Greater electron shielding (outweighs increased nuclear charge).
💡 The Three Competing Factors
Whenever explaining group IE trends, evaluate:
- Atomic Radius: Increases down the group as extra quantum shells are added.
- Shielding: Increases significantly due to additional full inner electron shells.
- Nuclear Charge: Increases (more protons), but this is completely overridden by the increased distance and shielding.
❌ Common Errors & Examiner Traps
- Saying "ionic radius": Automatic zero for that point! You are ionising neutral gaseous atoms, so you must refer to atomic radius or distance from the outer electron to the nucleus.
- Choosing Element Z: Confusing the trend and assuming higher IE means higher atomic number. In a group, atomic number increases downwards while IE decreases.
- Vague "nuclear charge" claims: Simply stating "nuclear charge increases" without explaining that shielding and radius dominate will lose marks.
Topics
Physical Chemistry · Inorganic Chemistry · Topic 1: Atomic Structure and the Periodic Table · Topic 4: Inorganic Chemistry and the Periodic Table
Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 3, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.