Edexcel A-Level Chemistry Paper 3, June 2025: Question 9
21 marks · Hard difficulty · Synoptic Questions
Complete the mechanism for the sulfonation of 1,4-dimethylbenzene, describe recrystallisation and dilution techniques, and perform back-titration calculations with error evaluation.
Practise this questionQuestion
Question text
9 This question is about the compound 2,5-dimethylbenzenesulfonic acid, which has
the structure shown.
O
HO S O
It is used to analyse levels of cholesterol in blood plasma. It can be synthesised by the
reaction of 1,4-dimethylbenzene with concentrated sulfuric acid.
The electrophile in this reaction is sulfur trioxide.
(a) Complete a possible mechanism for this reaction by adding curly arrows, and any
relevant dipoles, charges and lone pairs.
(3)
O
S
O O
structure of intermediate
O
HO S O
(b) The 2,5-dimethylbenzenesulfonic acid formed can be purified by recrystallisation
using hot water as a solvent.
Procedure
Step 1 Dissolve impure 2,5-dimethylbenzenesulfonic acid in the minimum
28 volume of hot water.
Step2 Allow the solution to cool until 2,5-dimethylbenzenesulfonic acid*P77834A02836*
has crystallised.
Step 3 Separate the 2,5-dimethylbenzenesulfonic acid by filtering under
reduced pressure.
Step 4 Rinse the 2,5-dimethylbenzenesulfonic acid using a small amount of
ice-cold water.
Step 5 Dry the 2,5-dimethylbenzenesulfonic acid between two pieces of
filter paper.
(i) Explain how recrystallisation reduces the amount of soluble impurities.
(3)
(ii) A student carrying out this procedure noticed some insoluble impurities in
their sample.
Describe how the procedure should be amended to remove these
insoluble impurities.
(2)
(c) The hydrated form of the acid has the formula C6H3(CH3)2SO3H•nH2O.
An experiment was carried out to determine the number of moles of water of
crystallisation, n, in this formula.
The method involves adding excess sodium hydroxide to a known mass of the 29
hydrated 2,5-dimethylbenzenesulfonic acid.*P77834A02936*
The amount of unreacted sodium hydroxide is then determined by titration.
Procedure
Step 1 10.0 cm3 of 1.00 mol dm−3 NaOH(aq) was added to 1.60 g of hydrated
2,5-dimethylbenzenesulfonic acid in a small conical flask.
Step 2 The solution formed was diluted to give a volume of exactly 100 cm3.
Step 3 20.0 cm3 samples of the diluted solution required a mean titre of
22.40 cm3 of 0.02500 mol dm−3 HCl(aq) to neutralise the unreacted
sodium hydroxide present in the sample.
(i) Describe how to make the diluted solution, in Step 2.
(4)
(ii) Calculate the relative formula mass of hydrated*P77834A03036*
2,5-dimethylbenzenesulfonic acid and hence deduce the value of n.
(5)
(d) A student carrying out this experiment used a funnel as shown to try to ensure
the acid was added safely to the burette during the titration.
(i) Give one change to this technique that would reduce the risk to this student.
(1)
(ii) The student forgot to remove the funnel from the burette and during the
titration five drops of acid from the funnel dripped into the burette.
Explain what effect, if any, this error will have on the final value for n.
(3)
… *P77834A03136*
(Total for Question 9 = 21 marks)
Mark scheme
Show the mark scheme
Question
Answer Additional Guidance Mark
Number
9(a) An answer that makes reference to the following points: (3)
• arrow from inside the hexagon to sulfur atom
• partial charges on S and O
• basic structure of intermediate, including both
methyl groups, and broken circle covering at least
three carbons, facing the tetrahedral carbon, and
containing (some part of) positive charge
• lone pair
and
negative charge on O of intermediate
In point 2 allow δ− on all O atoms
In point 5 allow arrow from lone pair on O to H+,
• arrow from (lone pair on) oxygen to H on ring +
or hydrogen on H2O, H3O , or H2SO4
• return of C−H bond pair towards/ inside (broken)
ring 6 points scores 3 marks
4 or 5 points scores 2 marks
2 or 3 points scores 1 mark
0 or 1 point scores 0 marks
Question
Answer Additional Guidance Mark
Number
9(b)(i) An explanation that makes reference to the following points: (3)
• both 2,5-dimethylbenzenesulfonic acid and (soluble)
impurities dissolve in hot water / hot solvent (1)
• impurities are soluble in cold solvent Allow impurities are present in small amounts
or (and so do not crystallise in cold solvent)
2,5-dimethylbenzenesulfonic acid is (much) less soluble / (1) Do not award the ice-cold water (in step 4)
insoluble in cold solvent dissolves the soluble impurities
• so impurities remain in solution (as the solvent cools) / (1) Allow the ice-cold water washes off any
impurities remain in the filtrate surface impurities
and
2,5-dimethylbenzenesulfonic acid recrystallises / solid
remains (on filter paper)
Question
Answer Additional Guidance Mark
Number
9(b)(ii) A description that makes reference to the following points: (2)
• filter when still hot / filter funnel and / or paper are heated (1)
• (filtration) carried out after step 1 / before step 2 (to (1) Allow redissolve in a different solvent
remove insoluble impurities)
If no other credit awarded, allow 1 mark for
decant (off from the impurities) whilst still
hot
Question
Answer Additional Guidance Mark
Number
9(c)(i) A description that makes reference to the following points: (4)
• (add the solution formed) to a 100 cm3 volumetric flask (1) Ignore starting with just the acid and omitting
the alkali
• (rinse remaining solution from conical flask) with (1)
distilled / deionised water and add washings to volumetric
flask
• add distilled / deionised water (1)
• make up to the line / mark (1)
and
• (add stopper) then invert / mix (to ensure solution is Do not award shake
homogenous)
Question
Answer Additional Guidance Mark
Number
9(c)(ii) Example of calculation (5)
• calculation of moles of HCl(aq) (1) (22.4/1000) × 0.0250 = 5.6 × 10–4 (mol)
(1) 5.6 × 10–4 × 5 = 2.8 × 10–3 (mol)
• calculation of moles of NaOH in in small conical flask
(1) (10/1000) – 2.8 × 10–3 = 7.2 × 10–3
• calculation of moles of 2,5-dimethylbenzenesulfonic acid
(1) 1.60 / 7.2 × 10–3 = 222.2 (g mol–1)
• calculation of Mr of 2,5-dimethylbenzenesulfonic acid
• deduction of value for n (must be an integer) (1) 222.2 – 186.1 = 36.1 so n = 2
Allow TE throughout
Correct answer with no working scores M5
only
If you see 222.2 for the Mr this will score
M1-M4 as the other steps will have been
carried out correctly.
Do not award negative value of n
Question
Answer Additional Guidance Mark
Number
9(d)(i) An answer that makes reference to the following point: (1)
• lower burette so pouring in acid below eye-level / Allow alternative methods of height reduction
place stand in sink / on (stable) stool / on floor Ignore just an observation that the top of the burette is
too high
Ignore just lower the burette / stand
Do not award student raises themselves e.g. standing
on a stool
Question
Answer Additional Guidance Mark
Number
9(d)(ii) An explanation that makes reference to the following (3)
points:
• reduce the value of the titre (1)
• smaller (calculated) value of excess NaOH / greater (1) M3 dependent on M2
(calculated) moles of 2,5-dimethylsulfonic acid that Allow smaller Mr but negligible effect on
reacted (calculated value) of n
If M1 is answered as ‘increase the value of the
• so smaller Mr, hence smaller (calculated value of) n (1) titre’ then allow reverse arguments for M2 and
M3
(Total for Question 9 = 21 marks)
TOTAL FOR PAPER = 120 MARKS
How to answer it
Synthesis, Purification & Analysis of 2,5-Dimethylbenzenesulfonic Acid
This comprehensive 21-mark practical and physical-organic question tests:
- Electrophilic Aromatic Substitution: Drawing the curved arrow mechanism with neutral electrophile sulfur trioxide (SO₃), including dipole generation, horseshoe intermediate carbocation, and proton loss.
- Organic Practical Skills: Principles of recrystallisation, removal of soluble vs insoluble impurities (hot filtration), and volumetric flask standard solution preparation.
- Quantitative Back Titration: Multi-stage stoichiometry to find molar mass and water of crystallisation ( n ).
- Apparatus & Error Propagation: Laboratory safety during burette filling and tracing systematic error propagation through titration calculation steps.
Part (a): Mechanism of Electrophilic Substitution
Electrophilic attack of sulfur trioxide on 1,4-dimethylbenzene (3 Marks)
✅ Mechanism Checklist (6 Key Scoring Points)
- Initial attack: Curly arrow originating from inside the benzene delocalised pi-system pointing directly to the sulfur atom of SO₃.
- Dipoles & SO₃ cleavage: Partial charges on SO₃ (δ+ on S, δ- on O atoms) AND a curly arrow from the S=O double bond onto the oxygen atom.
- Intermediate structure: Hexagonal ring with both methyl groups, tetrahedral carbon with bonded -H and -SO₃⁻, and an open horseshoe carbocation spanning at least 3 carbon atoms facing the sp³ carbon, containing a positive charge (+).
- Intermediate charges: A full negative charge ( - ) and lone pair on the single-bonded oxygen of the sulfonate group.
- Proton transfer: Curly arrow from the lone pair on the sulfonate oxygen atom (or a base/water molecule) to the H atom attached to the tetrahedral carbon.
- Aromatic regeneration: Curly arrow from the C-H bond pointing back into the broken ring carbocation.
🧠 Exam Technique & Mark Scheme Conversion
This 3-mark question uses an aggregate points system:
- 6 points: 3 marks
- 4 or 5 points: 2 marks
- 2 or 3 points: 1 mark
- 0 or 1 point: 0 marks
Draw with precision: Make sure your horseshoe does not extend past the meta carbons (it must span 5 carbons total, open at the tetrahedral carbon). Ensure the '+' charge is placed strictly inside the horseshoe.
❌ Common Errors in this Mechanism
- Starting the first arrow from a localized carbon atom instead of the inside of the delocalised pi-electron ring.
- Forgetting to show the formal negative charge on the oxygen atom in the -SO₃⁻ intermediate.
- Drawing the arrow from the hydrogen atom rather than from the C-H bond back into the ring.
Part (b): Recrystallisation & Purification
Principles of solubility separation and hot filtration (5 Marks Total)
💡 (b)(i) How Recrystallisation Removes Soluble Impurities (3 Marks)
- Mark 1: Both the 2,5-dimethylbenzenesulfonic acid and the soluble impurities completely dissolve in the hot water / solvent.
- Mark 2: Soluble impurities are soluble in cold water / present in small quantities, whereas 2,5-dimethylbenzenesulfonic acid is much less soluble / insoluble in cold water.
- Mark 3: As the solution cools, the acid crystallises out (remains on filter paper), while the soluble impurities remain dissolved in the solution / filtrate (and are washed away).
✅ (b)(ii) Removing Insoluble Impurities (2 Marks)
- Mark 1 (Technique): Carry out hot filtration (filter while the solution is still hot, using a pre-heated funnel / fluted filter paper).
- Mark 2 (Placement): Perform this filtration after Step 1 and before Step 2 (i.e. before allowing the solution to cool and crystallise).
❌ Common Misconceptions in Recrystallisation
- Confusing the steps: Filtering after cooling would trap both insoluble impurities AND the desired crystallised product together on the filter paper!
- Cold wash purpose: Step 4 (rinsing with ice-cold water) washes off soluble impurities adhering to the surface of the crystals; it does not dissolve the bulk impurities.
Part (c)(i): Making the Diluted Standard Solution
Practical method for Step 2 dilution (4 Marks)
✅ Standard Solution Preparation Steps (4 Marks)
- Transfer: Transfer the reaction mixture from the conical flask into a 100 cm³ volumetric flask.
- Rinsing: Rinse the conical flask with distilled (deionised) water and add the washings into the volumetric flask.
- Make up to volume: Add distilled water until the bottom of the meniscus touches the graduation mark at eye level.
- Homogenise: Insert the stopper and invert / invert repeatedly to ensure the solution is thoroughly mixed.
❌ Examiner Trap
"Shaking" vs "Inverting": The mark scheme specifically states: "Do not award shake". Always state: "stopper and invert to mix" to guarantee Mark 4.
Part (c)(ii): Back Titration Calculation
Determining Molar Mass and Water of Crystallisation, n (5 Marks)
📐 Step-by-Step Calculation
Moles of HCl = (volume / 1000) × concentration
Moles of HCl = (22.40 / 1000) × 0.02500 = 5.60 × 10⁻⁴ mol
NaOH + HCl → NaCl + H₂O (1:1 ratio)
Moles of excess NaOH in 20.0 cm³ = 5.60 × 10⁻⁴ mol
Scaling factor = 100.0 cm³ / 20.0 cm³ = 5
Total excess NaOH in 100 cm³ flask = 5.60 × 10⁻⁴ × 5 = 2.80 × 10⁻³ mol
Initial NaOH added = (10.0 / 1000) × 1.00 = 1.00 × 10⁻² mol
Moles reacted = Initial NaOH - Excess NaOH
Moles reacted = 1.00 × 10⁻² - 2.80 × 10⁻³ = 7.20 × 10⁻³ mol
Since 2,5-dimethylbenzenesulfonic acid is monoprotic (1:1 ratio):
Moles of hydrated acid = 7.20 × 10⁻³ mol
Mass of sample = 1.60 g
Mᵣ = mass / moles = 1.60 / (7.20 × 10⁻³) = 222.2 g mol⁻¹
Formula of anhydrous acid = C₆H₃(CH₃)₂SO₃H = C₈H₁₀SO₃
Mᵣ(anhydrous) = (8 × 12.0) + (10 × 1.0) + 32.1 + (3 × 16.0)
Mᵣ(anhydrous) = 96.0 + 10.0 + 32.1 + 48.0 = 186.1 g mol⁻¹
Mass of water of crystallisation = 222.2 - 186.1 = 36.1 g mol⁻¹
n = 36.1 / 18.0 = 2.006 → n = 2
❌ Calculation Pitfalls
- Forgetting to scale up: Failing to multiply the titration moles by 5 (100/20) is the most frequent blunder.
- Integer requirement: The question asks for the value of n. Writing 2.01 without rounding to the integer 2 forfeits Mark 5.
Part (d): Safety & Error Analysis
Apparatus risk reduction and titration error propagation (4 Marks Total)
🧠 (d)(i) Safety Modification (1 Mark)
Correction: Lower the burette so that the top is below eye level when pouring acid (e.g. place the stand in a sink or safely on the floor / lower clamp).
Examiner Warning: Do not suggest the student stands on a stool or chair (this introduces a fall hazard!). Do not simply write "lower the burette" without explaining that pouring must occur below eye level.
💡 (d)(ii) Effect of Acid Dripping into Burette (3 Marks)
Follow the chain of reasoning carefully:
- Effect on Titre (Mark 1): Dripping extra acid into the burette during titration increases liquid level, meaning the delivered volume appears smaller → reduces the value of the titre.
- Effect on Acid Reacted (Mark 2): A smaller titre means a lower calculated value for unreacted excess NaOH. Consequently, the calculated moles of reacted sulfonic acid is greater.
- Effect on n (Mark 3): A greater calculated number of moles of acid means calculated Mᵣ is smaller (Mᵣ = mass / moles). A smaller Mᵣ means less mass is attributed to water, so the calculated value of n is smaller.
Topics
Organic Chemistry · Physical Chemistry · Core Practicals · Topic 18: Organic Chemistry III · Topic 5: Formulae, Equations and Amounts of Substance · Core Practical 2: Preparation of a standard solution from a solid acid · Core Practical 3: Find the concentration of a solution of hydrochloric acid
Question and mark scheme from the Edexcel A-Level Chemistry examination, Paper 3, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.