OCR A-Level Chemistry Periodic table, elements and physical chemistry (01), June 2017: Question 17

12 marks · Medium difficulty · Structured Questions

Answer questions on Group 2 reactivity, disproportionation of chlorate(V), systematic naming, and entropy changes for precipitation and atomisation reactions.

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Question

An OCR A-Level Chemistry exam question numbered 17, consisting of four main parts (a), (b), (c), and (d) about Group 2 and Group 17 chemistry. Part (a) asks for the equation for preparing barium chloride from barium hydroxide. Part (b) asks to explain why Group 2 reactivity increases down the group. Part (c)(i) asks about disproportionation and oxidation numbers for a given equation involving KClO3, and (c)(ii) asks for the systematic name of KClO4. Part (d) requires equations with state symbols and explanations of entropy changes for two specified changes: the reaction of aqueous barium nitrate with aqueous sodium sulfate, and the standard enthalpy change of atomisation of iodine.
Question text

17 This question is about Group 2 and Group 17 (7).

(a) Barium chloride can be prepared from barium hydroxide in a neutralisation reaction.

Write the equation for this reaction. State symbols are not required.

… [1]

(b) The reactivity of the Group 2 elements Mg–Ba increases down the group.

Explain why.

… [3]

(c) On gently heating, the compound KClO3 reacts as shown in the equation.

4KClO3(s) KCl(s) + 3KClO4(s)

This reaction is an example of disproportionation.

(i) State what is meant by disproportionation and use oxidation numbers to show that

disproportionation has taken place.

… [3]

(ii) What is the systematic name for KClO4?

… [1]

(d) Two changes are described below.

For each change,

• write an equation, including state symbols,

• state and explain how the entropy changes.

(i) The reaction of aqueous barium nitrate with aqueous sodium sulfate.

Full equation with state symbols

Explanation of entropy change …

… [2]

(ii) The change that accompanies the standard enthalpy change of atomisation of iodine.

Equation with state symbols

Explanation of entropy change …

… [2]

Mark scheme

Show the mark scheme The official mark scheme for question 17, divided into parts (a), (b), (c)(i), (c)(ii), (d)(i), and (d)(ii), showing acceptable answers, allocation of marks totaling 12 marks, and examiner guidance such as IGNORE and ALLOW instructions.

Question Answer Marks Guidance

17 (a) Ba(OH)2 + 2HCl BaCl2 + 2H2O 1 ALLOW multiples

IGNORE state symbols (even if wrong)

(b) 3 FULL ANNOTATIONS WITH TICKS, CROSSES,

CON, etc MUST BE USED

Increasing size:

Atomic radius increases IGNORE more orbitals OR more sub-shells

OR Alternative must refer to shells

more shells

OR ALLOW Energy levels for shells

more (electron) shielding

ALLOW more electron repulsion between shells

IGNORE just ‘shielding’ (more/greater needed)

IGNORE ‘nuclear shielding’

Attraction

Nuclear attraction decreases IGNORE ‘pull’ for attraction

OR IGNORE ‘electrons less tightly held’

(outer) electron(s) experience less attraction IGNORE ‘nuclear charge’ for ‘nuclear attraction’

IGNORE ‘easier to remove electron’

Ionisation energy Energy is required

Ionisation energy decreases

OR ALLOW less energy to oxidise

less energy needed to remove electron(s)

(c) (i) Disproportionation: 8 3

oxidation and reduction of the same element ALLOW ‘chlorine’ OR ‘Cl’ for same element

IGNORE ‘species’ for ‘element’

Redox:

Cl is oxidised from +5 (in KClO3) to +7 (in KClO4) ALLOW after number, e.g. 5+

IGNORE ionic charges, e.g. Cl5+

Cl is reduced from +5 (in KClO3) to –1 (in KCl) IGNORE ‘5’ (signs required)

IGNORE any reference to electron loss/gain (even

if wrong)

ALLOW one redox mark if oxidation numbers are

correct but reduction/oxidation is incorrectly

assigned

(ii) potassium chlorate(VII) 1 Brackets required

(d) (i) Equation 2

Ba(NO3)2(aq) + Na2SO4(aq) BaSO4(s) + 2NaNO3(aq) ALLOW multiples

Entropy change and explanation M2 is dependent on BaSO4(s) (even if formula is

entropy decreases OR entropy change negative incorrect – eg Ba(SO4)2(s)) seen as a product in the

AND attempted equation as long as reactants are not

(BaSO4) solid/ppt has less disorder/ more order/ solid.

fewer ways of arranging energy/ less freedom/ less BaSO4 solid/ppt may be assumed from BaSO4(s)

random particles/dispersal of energy seen in the attempted equation.

(ii) Equation 9 2

½ I2(s) I(g) DO NOT ALLOW I2(s) 2I(g)

state symbols required

Entropy change and explanation

entropy increases OR entropy change positive DEPENDENT on ½ I2(s) I(g) OR I2(s) 2I(g)

AND

gas has more disorder/ less order/ more ways of

arranging energy/ more freedom/ more random

particles / more dispersal of energy

Total 12

How to answer it

Group 2 & Group 17 Chemistry Study Guide

What this question tests

This exam question tests your knowledge across inorganic and physical chemistry topics: neutralisation reactions involving Group 2 hydroxides, periodic trends down Group 2 (atomic radius, shielding, nuclear attraction, and first ionisation energy), redox disproportionation with oxidation number changes, systematic nomenclature (IUPAC naming with oxidation states), precipitation reactions, and entropy changes associated with physical and chemical transformations.

Question Part (a)

Neutralisation Equation

✅ Correct Answer

Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O

💡 Key Knowledge

  • Barium hydroxide is a strong base containing the divalent OH⁻ ion.
  • Hydrochloric acid provides H⁺ ions to form water alongside barium chloride salt.

❌ Common Errors

  • Writing an incorrect formula for barium hydroxide (e.g., BaOH ) due to forgetting Group 2 valency.
  • Balancing the equation incorrectly by missing the coefficient 2 in front of HCl and H₂O .
Marks: 1 | Guidance: Multiples allowed. State symbols are ignored even if incorrect.
Question Part (b)

Group 2 Reactivity Trend

✅ Correct Answer

  1. Atomic size: Atomic radius increases down the group / more electron shells.
  2. Attraction: Outer electrons experience more shielding and weaker nuclear attraction.
  3. Ionisation Energy: Less energy is required to remove outer electrons (first ionisation energy decreases).

🧠 Exam Technique

This is a classic 3-mark explanation question. Ensure you hit the logical chain in order: Structure (shells/radius) → Electrostatics (shielding/nuclear attraction) → Energetics (ionisation energy/ease of losing electrons).

❌ Common Errors

  • Vague statements like "shielding increases" without linking it to the decreasing pull from the nucleus.
  • Mentioning "nuclear charge increases down the group, so reactivity increases" — examiners penalise this because increased nuclear charge alone would pull electrons *closer*, missing the dominant effect of extra shells and shielding.
Marks: 3 | Guidance: Full annotations/marks require clear mention of shells/radius, attraction, and energy.
Question Part (c)

Disproportionation and Systematic Nomenclature

✅ Correct Answer (i)

Definition: Oxidation and reduction of the same element in a single reaction.

Oxidation number changes for Cl in 4KClO₃ → KCl + 3KClO₄ :

  • Chlorine is oxidised from +5 (in KClO₃ ) to +7 (in KClO₄ ).
  • Chlorine is reduced from +5 (in KClO₃ ) to -1 (in KCl ).

✅ Correct Answer (ii)

potassium chlorate(VII)

💡 Key Knowledge

Disproportionation requires a single species to undergo simultaneous oxidation (loss of electrons / increase in oxidation number) and reduction (gain of electrons / decrease in oxidation number).

❌ Common Errors

Forgetting to include the Roman numerals in brackets for systematic names (e.g., writing just "potassium chlorate"), or mixing up oxidation state signs (omitting the + sign for positive numbers).

Marks: (i) = 3 marks, (ii) = 1 mark. Guidance: Signs are required for oxidation numbers. Brackets are required for Roman numerals in IUPAC names.
Question Part (d)(i)

Precipitation Reaction & Entropy Change

✅ Correct Answer

Equation: Ba(NO₃)₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaNO₃(aq)

Entropy change: Entropy decreases / entropy change is negative ( ΔS < 0 ).

Explanation: Aqueous ions form a solid precipitate ( BaSO₄ ), resulting in less disorder, fewer ways of arranging energy, and a more ordered system.

🧠 Exam Technique

Mark 2 (the explanation) is dependent on identifying the formation of a solid or a decrease in disorder. Always explicitly contrast the state change (aqueous/ions to solid precipitate) to secure the mark.

❌ Common Errors

Omitting state symbols or getting them wrong. Note that state symbols are explicitly requested in the prompt for part (d).

Marks: 2 | Guidance: Full equation with correct state symbols required. Explanation must reference the solid precipitate reducing disorder.
Question Part (d)(ii)

Enthalpy of Atomisation & Entropy Change

✅ Correct Answer

Equation: ½ I₂(s) → I(g)

Entropy change: Entropy increases / entropy change is positive ( ΔS > 0 ).

Explanation: A solid changes into a gas, which has more disorder, greater freedom of movement, and more ways of dispersing energy.

💡 Key Knowledge

The standard enthalpy change of atomisation is the enthalpy change when one mole of gaseous atoms is formed from the element in its standard state under standard conditions.

❌ Common Errors

Writing I₂(s) → 2I(g) instead of using a fraction ( ½ ), which violates the per-mole-of-gaseous-atoms definition for atomisation. Also forgetting state symbols ( (s) and (g) ).

Marks: 2 | Guidance: Equation must represent 1 mole of gaseous atoms (using ½ I₂ ). Explanation must link phase change from solid to gas with increased disorder.

Topics

Module 3: Periodic table and energy · Module 5: Physical chemistry and transition elements · 5.2 Energy · 3.1 The periodic table

Question and mark scheme from the OCR A-Level Chemistry examination, Periodic table, elements and physical chemistry (01), June 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.