OCR A-Level Chemistry Periodic table, elements and physical chemistry (01), June 2017: Question 5
1 mark · Medium difficulty · Multiple Choice
Calculate the volume of hydrochloric acid required to react completely with a given amount of calcium oxide.
Practise this questionQuestion
Question text
5 0.0200 mol of calcium oxide is reacted completely with 2.00 mol dm–3 HCl.
What is the volume, in cm3, of 2.00 mol dm–3 HCl required for this reaction?
A 15
B 20
C 30
D 60
Your answer [1]
Mark scheme
Show the mark scheme
5 B 1 ALLOW 20 in the box
How to answer it
Calculating Solution Volume from Moles
What this question tests
This question assesses your ability to write a balanced neutralisation equation, apply stoichiometric molar ratios, and convert between moles, concentration, and volume in cubic centimetres (cm³).
Question 5 Solution Guide
Multiple Choice Part (Option B)
✅ Correct Answer
B (20)
The required volume of hydrochloric acid is 20 cm³ .
💡 Key Knowledge
- Metal oxides react with acids to form a salt and water: CaO + 2HCl → CaCl₂ + H₂O
- The stoichiometric ratio of calcium oxide to hydrochloric acid is 1 : 2 .
- Concentration formula: Moles = Concentration × Volume (in dm³)
🧠 Exam Technique
Always write out the balanced chemical equation first to secure the correct molar ratio. Watch out for unit conversions between dm³ and cm³ (multiply by 1000 at the final step).
❌ Common Errors
- 1:1 ratio trap: Forgetting the coefficient of 2 in front of HCl , leading to a calculated volume of 10 cm³ (Option A).
- Unit conversion omission: Forgetting to multiply by 1000 , leaving the volume in dm³ ( 0.020 dm³ ).
📐 Step-by-Step Calculation
- Step 1: Write the balanced equation
CaO (s) + 2HCl (aq) → CaCl₂ (aq) + H₂O (l) - Step 2: Determine moles of HCl required using the 1:2 ratio
Moles of CaO = 0.0200 mol
Moles of HCl = 0.0200 × 2 = 0.0400 mol - Step 3: Rearrange the concentration formula to find volume in dm³
Volume (dm³) = Moles / Concentration = 0.0400 / 2.00 = 0.0200 dm³ - Step 4: Convert volume into cm³
Volume (cm³) = 0.0200 × 1000 = 20 cm³
Topics
Module 2: Foundations in chemistry · 2.1 Atoms and reactions
Question and mark scheme from the OCR A-Level Chemistry examination, Periodic table, elements and physical chemistry (01), June 2017. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.