OCR A-Level Chemistry Synthesis and analytical techniques (02), June 2018: Question 2

1 mark · Medium difficulty · Multiple Choice

Identify which given compound is a secondary amide from four structural options.

Practise this question

Question

Multiple choice question 2 asks 'Which compound is a secondary amide?' with four options labeled A, B, C, and D showing different chemical structures containing carbonyl and amino/amide groups.
Question text

2 Which compound is a secondary amide?

O CH

A HO C CH N

H

O CH

B HO C CH N

CH3

O CH

C H C C N

H

O CH

D H C C N

CH3

Your answer

[1]

Mark scheme

Show the mark scheme Mark scheme indicates the correct answer for question 2 is C, awarding 1 mark.

2 C 1

How to answer it

Identifying a Secondary Amide

📌 What this question tests

This question assesses your ability to recognise functional groups in organic molecules—specifically distinguishing between amines and amides, and classifying amides as primary, secondary, or tertiary based on the substitution of the nitrogen atom.

Question Analysis & Answer

Multiple Choice Question (Part 2)

✅ Correct Answer: C

Compound C features a carbonyl group ( C=O ) directly attached to a nitrogen atom, which defines an amide functional group. Furthermore, the nitrogen atom is bonded to one hydrogen atom ( H ), one methyl group ( CH₃ ), and the carbonyl carbon, making it a secondary amide (N-substituted amide).

Mark Awarded: 1 / 1

💡 Key Knowledge: Classifying Amides & Amines

  • Amide linkage: Contains a carbonyl group ( C=O ) bonded to a nitrogen atom ( -C(=O)-N< ).
  • Primary amide ( -CONH₂ ): Nitrogen is bonded to 0 carbon chains (2 hydrogens).
  • Secondary amide ( -CONHR ): Nitrogen is bonded to 1 carbon chain/group (1 hydrogen).
  • Tertiary amide ( -CONR₂ ): Nitrogen is bonded to 2 carbon chains/groups (0 hydrogens).
  • Amines vs Amides: Amines contain -C-N bonds without the adjacent C=O carbonyl group.

🧠 Exam Technique

Approach structural multiple-choice questions systematically in two steps:

  1. Identify the core functional group: Look for the C=O connected to N to eliminate non-amides.
  2. Count nitrogen substituents: Look at what else is attached directly to the nitrogen atom to determine the degree of substitution.

❌ Common Errors & Distractor Analysis

  • A & B (Incorrect): These structures contain a carboxylic acid group ( -COOH ) and an amino group ( -NH- or -N(CH₃)₂ ) separated by a -CH₂- spacer. They are amino acids/derivatives, not amides, because the nitrogen is not directly adjacent to the C=O .
  • D (Incorrect): While compound D is an amide (has C=O attached to N ), the nitrogen is bonded to two methyl groups and has zero hydrogens, making it a tertiary amide instead of secondary.

Topics

Module 6: Organic chemistry and analysis · 6.2 Nitrogen compounds, polymers and synthesis

Question and mark scheme from the OCR A-Level Chemistry examination, Synthesis and analytical techniques (02), June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.