OCR A-Level Chemistry Synthesis and analytical techniques (02), June 2019: Question 16
13 marks · Hard difficulty · Structured Questions
Outline the electrophilic addition mechanism of hydrogen bromide to 3-methylbut-2-enal, explain isomerism, and distinguish between functional groups of geraniol and citronellal.
Practise this questionQuestion
Question text
16 This question is about unsaturated aldehydes and alcohols.
(a) 3-Methylbut-2-enal, shown below, is used as a food flavouring.
H3C CHO
C C
H3C H
3-methylbut-2-enal
3-Methylbut-2-enal is reacted with hydrogen bromide, forming a mixture of two organic
products.
One of the organic products forms in a much greater quantity than the other organic product.
(i) Outline the reaction mechanism for the formation of one of the organic products.
Include curly arrows and relevant dipoles.
[4]
(ii) Explain why one of the organic products forms in a much greater quantity than the other
organic product.
… [2]
(b) Geraniol and citronellal, shown below, are isomers present in ‘citronella oil’, used as an insect
repellent.
OH O
Geraniol Citronellal
• Geraniol and citronellal are structural isomers of each other.
• They also show stereoisomerism.
(i) Describe how the observations from a chemical test would distinguish between geraniol
and citronellal.
… [2]
(ii) What is the molecular formula of geraniol?
… [1]
(iii) Explain why geraniol and citronellal are structural isomers of each other.
… [1]
(iv) Explain the term stereoisomerism.
… [1]
(v) The structures of geraniol and citronellal are repeated below with the carbon atoms
numbered.
71 7 1
54 3 5 4 3 2
86 2 OH 8 O
Geraniol Citronellal
Explain the types of stereoisomerism shown by geraniol and citronellal.
In your answer,
• refer to the numbered carbon atoms in the structures above
• draw diagrams clearly showing any stereoisomers.
Geraniol stereoisomers
Citronellal stereoisomers
[4]
Mark scheme
Show the mark scheme
AO
Question Answer Marks Guidance
element
16 (a) (i) ANNOTATE ANSWER WITH TICKS AND CROSSES 4 NOTE: curly arrows can be straight, snake-like,
etc.
but NOT double headed or half headed arrows
1st curly arrow must
• go to the H atom of H–Br
H3C CHO AND
C C • start from, OR be traced back to any
point across width of C=C
H3C H
H δ+
Br δ−
Curly arrow from C=C bond to H of H–Br AO1.2
DO NOT ALLOW partial charge on C=C 2nd curly arrow must
• start from, OR be traced back to any
Correct dipole shown on H–Br part of δ+H–Brδ– bond
AND curly arrow showing breaking of H–Br bond AO1.2 AND
• go to Brδ–
AO
element
Correct carbocation IGNORE connectivity of CHO and CH3 groups in
AND curly arrow from Br– to C+ of carbocation AO2.5 carbocation and product
DO NOT ALLOW δ+ on C of carbocation e.g. ALLOW
CHO CHO
OR
H C CHO CH3 CHO
C C H H3C C C ALLOW COH for CHO (reaction does not
involve this group)
H3C H H
H
Br− Br− 3rd curly arrow must
OR
• go to the C+ of carbocation
---------------------------------------------------------------------- AND
Correct product AO2.5 • start from, OR be traced back to any
point across width of lone pair on :Br–
CH3 CHO CH3 CHO –
• OR start from – charge of Br ion
H3C C C H H3C C C H
Br H OR H Br
(Lone pair NOT needed if curly arrow shown
from – charge of Br– ion)
IF Br2 is used instead of HBr contact your Team
Leader
(a) (ii) (major product forms from) most/more stable 2 For carbocation,
6 AO
element
intermediate/carbocation AO1.1 ALLOW carbonium ion or cation
(major product forms from a) tertiary carbocation IGNORE descriptions of the major/minor product
OR carbocation bonded to more C atoms / more alkyl in terms of Markownikoff’s rule
groups e.g. H atom joins to C with most H
OR carbocation bonded to no H atoms AO1.2
IGNORE references to stability of the product
--------------------------------------------------------------
ALLOW ORA, i.e.
(minor product forms from) least/less stable
intermediate/carbocation
(minor product forms from a) secondary
carbocation
OR carbocation bonded to fewer C atoms /
more alkyl groups
OR carbocation bonded to H atoms
-------------------------------------------------------------
(b) (i) Tollens’ (reagent) 2 AO1.2 ALLOW ammoniacal silver nitrate OR Ag+/NH
7 AO
element
×2
Silver (mirror/precipitate/ppt/solid)
with citronellal/the aldehyde ALLOW black ppt OR grey ppt
IGNORE references to acidified dichromate
reacting with both compounds
------------------------------------------------------------
ALLOW 2,4-DNP/2,4-DNPH
ALLOW Brady's reagent
Yellow/orange/red precipitate with
citronellal/aldehyde/carbonyl group
-------------------------------------------------------------
IF other reagents are seen, contact your Team
Leader
(b) (ii) C10H18O 1 AO1.2 DO NOT ALLOW C10H17OH
(b) (iii) 1 Same formula is not sufficient
(no reference to molecular)
Same molecular formula Different arrangement of atoms is not sufficient
AND (no reference to structure/structural)
Different structural formulae AO1.1
For structural formulae,
ALLOW structure/displayed/skeletal formulae/
OR functional groups
Both (geraniol and citronellal) have the molecular DO NOT ALLOW any reference to spatial/space
formula C10H18O
AND ALLOW ECF from incorrect molecular formula
Different structural formulae in (b)(ii)
(iv) Same structural formula 1 AO1.1 ALLOW structure/displayed/skeletal formula
AO
8 element
AND
Different arrangement (of atoms) in space DO NOT ALLOW same empirical formula
OR different spatial arrangement (of atoms) OR same general formula
IGNORE same molecular formula
Reference to E/Z isomerism or optical
isomerism is not sufficient
(v) Geraniol: 4 ANNOTATE ANSWER WITH TICKS AND
(Carbon-carbon) double bond at carbon-2(,3) CROSSES ETC
AND
E OR Z AO1.2 CHECK diagrams of citronellal and geraniol for
annotations that may be worthy of credit
DO NOT ALLOW isomerism at C=C at carbon
6(,-7)
Structure of Z geraniol (E isomer is shown in question)
ALLOW identification of carbon-2(,3) from
correct Z geraniol isomer if not stated in text or
diagram
IGNORE cis OR trans isomerism (none of the
substituent groups attached to the C=C are the
OH AO2.5 same)
IGNORE geometric
ALLOW type of isomerism from E/Z labels, even
if incorrectly assigned
In geraniol,
ALLOW C6H11 OR R to represent alkenyl chain
ALLOW CH3O to represent CH2OH
9 AO
element
Citronellal:
chiral/asymmetric C at carbon-3
OR carbon-3 is bonded to 4 different groups ALLOW identification of carbon-3 from 3D
AND structure citronellal if not stated in text or
optical isomerism AO1.2 diagram
Two 3D structures of citronellal that are mirror IGNORE connectivity of groups around chiral C
images AO2.5
e.g. In citronellal,
ALLOW C6H11 OR R to represent alkenyl chain
ALLOW C2H3O to represent CH2CHO
IF structural formula of alkenyl chain is used
IGNORE one small slip in one/both isomers
e.g.(CH3)2CHCH2CH2 (missing carbon-7)
ALLOW two 3D structures with 2 groups
swapped
e.g.
O
H
O
H
Total 13
How to answer it
Unsaturated Aldehydes and Alcohols Study Guide
What this question tests
This question assesses your mastery of organic reaction mechanisms (electrophilic addition), carbocation stability, functional group identification using chemical tests, isomerism definitions (structural, E/Z stereoisomerism, and optical isomerism), and structural drawing skills.
Outline the reaction mechanism for the formation of one of the organic products.
✅ Correct Answer & Mark Scheme
- 1st curly arrow: From the C=C double bond to the H atom of H-Br.
- Dipole: Correct partial charges (δ+ on H, δ- on Br) shown on H-Br.
- 2nd curly arrow: Showing the breaking of the H-Br bond (from the bond to the Br atom).
- Intermediate: Correct carbocation structure with a curly arrow going from the lone pair/minus charge of the Br⁻ ion to the C+ carbon.
🧠 Exam Technique & Guidance
Make sure your first curly arrow originates clearly from the C=C bond (either from the midpoint or right across the width of the bond) and points directly to the hydrogen atom. Double-headed arrows are essential.
❌ Common Errors
- Starting curly arrows from the wrong place (e.g., starting on a hydrogen rather than the bond).
- Omitting partial charges (δ+ / δ-) on the H-Br molecule.
- Placing a δ+ charge directly onto the carbon atom within the carbocation structure.
Explain why one of the organic products forms in a much greater quantity.
✅ Correct Answer
The major product forms from the more stable tertiary carbocation intermediate, which is bonded to more alkyl groups (or more carbon atoms).
💡 Key Knowledge
Alkyl groups are electron-releasing (positive inductive effect), which spreads out the positive charge on the carbon atom, stabilizing the intermediate.
Describe how the observations from a chemical test would distinguish between geraniol and citronellal.
✅ Correct Answer
- Reagent: Tollens' reagent (or ammoniacal silver nitrate, Ag(NH₃)₂⁺).
- Observation with geraniol (alcohol): No change / negative result (stays colourless).
- Observation with citronellal (aldehyde): Silver mirror formed / grey precipitate / black precipitate.
❌ Common Errors
Using acidified potassium dichromate(VI) is incorrect here because both molecules contain functional groups that react with it (geraniol is an alcohol, citronellal is an aldehyde), so it would not distinguish between them.
What is the molecular formula of geraniol?
✅ Correct Answer
C₁₀H₁₈O
Structural Isomerism & Stereoisomerism
💡 (iii) Structural Isomers
Compounds with the same molecular formula but different structural formulae (different arrangement of atoms).
💡 (iv) Stereoisomerism
Compounds with the same structural formula but with a different arrangement (or spatial orientation) of atoms in space.
Explain the types of stereoisomerism shown by geraniol and citronellal.
✅ Correct Answer & Features
- Geraniol: Shows E/Z isomerism (or geometric isomerism) due to restricted rotation around the carbon-carbon double bond at carbon-2 (,3).
- Citronellal: Shows optical isomerism due to a chiral/asymmetric carbon atom at carbon-3 (bonded to 4 different groups).
- Drawings: Must clearly show 3D structures (using wedge-dash bonds for optical isomers, or correct spatial geometry around the C=C double bond for E/Z isomers).
🧠 Exam Technique
When asked to refer to numbered carbon atoms, explicitly mention carbon-2 or carbon-3 in your written response to secure communication marks.
Topics
Module 4: Core organic chemistry · Module 6: Organic chemistry and analysis · 6.1 Aromatic compounds, carbonyls and acids · 4.1 Basic concepts and hydrocarbons · 4.2 Alcohols, haloalkanes and analysis
Question and mark scheme from the OCR A-Level Chemistry examination, Synthesis and analytical techniques (02), June 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.