OCR A-Level Chemistry AS Breadth in chemistry (01), November 2020: Question 13
1 mark · Easy difficulty · Multiple Choice
Calculate the numerical value of the equilibrium constant Kc for the reversible reaction between sulfur dioxide and oxygen given their equilibrium concentrations.
Practise this questionQuestion
Question text
13 The reversible reaction below is in equilibrium.
2SO2(g) + O2(g) 2SO3(g)
The equilibrium concentrations are shown in the table.
Substance SO2(g) O2(g) SO3(g)
Equilibrium concentration
−3 4.00 2.40 1.44
/ mol dm
What is the numerical value of Kc?
A 0.0375
B 0.0540
C 0.150
D 18.5
Your answer [1]
Mark scheme
Show the mark scheme
13 B 1 1.2 ALLOW 0.054(0)
How to answer it
Calculating the Equilibrium Constant (Kc)
This question assesses your ability to construct an equilibrium constant expression (Kc) from a balanced chemical equation, substitute equilibrium concentrations correctly, account for stoichiometric balancing numbers as powers, and calculate the final numerical value.
Question 13 Multiple Choice Analysis
Equilibrium Constant Calculation
✅ Correct Answer
B (0.0540)
The correct calculation yields approximately 0.0540 dm³ mol⁻¹ based on the equilibrium concentrations provided.
💡 Key Knowledge
- Products are always on the numerator, reactants on the denominator.
- Stoichiometric coefficients from the balanced equation become powers in the Kc expression.
- Ensure you extract values designated for equilibrium concentrations, not initial amounts.
🧠 Exam Technique
- Write out the general Kc expression explicitly before plugging in numbers to avoid transposition errors.
- Double-check bracket positions and squaring functions on your calculator, particularly for terms with a coefficient of 2.
❌ Common Errors
- Forgetting to square: Leaving out the squared term for SO₂(g) or SO₃(g) .
- Inverting the expression: Putting reactants on top and products on the bottom.
📐 Step-by-Step Calculation Guide
- Write the balanced equation:
2SO₂(g) + O₂(g) ⇌ 2SO₃(g) - Construct the Kc expression:
Kc = [SO₃]² / ([SO₂]² × [O₂]) - Substitute the equilibrium values from the table:
[SO₂] = 4.00 mol dm⁻³
[O₂] = 2.40 mol dm⁻³
[SO₃] = 1.44 mol dm⁻³ - Perform the math:
Numerator: 1.44² = 2.0736
Denominator: 4.00² × 2.40 = 16.0 × 2.40 = 38.4
Kc = 2.0736 / 38.4 = 0.0540 mol⁻¹ dm³
Topics
Module 5: Physical chemistry and transition elements · 5.1 Rates, equilibrium and pH
Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.