OCR A-Level Chemistry Periodic table, elements and physical chemistry (01), November 2020: Question 14
1 mark · Hard difficulty · Multiple Choice
Identify the correct statements concerning Group 2 elements regarding ionisation energy, electron configuration of ions, and reactions with water.
Practise this questionQuestion
Question text
14 Which statement(s) for Group 2 elements is/are correct?
1 The 2nd ionisation energy of magnesium is greater than the 2nd ionisation energy of
calcium.
2 A strontium ion, Sr2+, contains a total of 6 electrons in s orbitals.
3 The equation for the reaction of barium with water is:
2Ba + 2H2O 2BaOH + H2.
A 1, 2 and 3
B Only 1 and 2
C Only 2 and 3
D Only 1
Your answer [1]
Mark scheme
Show the mark scheme
14 D 1 1.2 ALLOW 1 in the answer box
How to answer it
Group 2 Elements Properties and Reactions
What this question tests
This multi-statement question tests your deep understanding of Group 2 trends, specifically successive ionisation energies down a group, electronic configurations of ions, and equations for chemical reactions between Group 2 metals and water.
Question Breakdown & Analysis
✅ Correct Answer: D (Only 1)
Statement 1 is the only correct statement among the three options provided.
🧠 Exam Technique
Evaluate each numbered statement independently as true or false. Cross out options that contain incorrect statements to rapidly narrow down to the correct multiple-choice letter.
Detailed Statement Analysis
Statement 1: The 2nd ionisation energy of magnesium is greater than the 2nd ionisation energy of calcium. (TRUE)
- Reasoning: Removing a 2nd electron from magnesium involves an ion with a smaller ionic radius and less shielding than calcium (Mg⁺ vs Ca⁺).
- Furthermore, the 2nd electron removed from magnesium is from the 2s subshell (closer to the nucleus), whereas for calcium it is from the 4s subshell. This leads to a much stronger nuclear attraction for magnesium, making its 2nd ionisation energy higher.
Statement 2: A strontium ion, Sr²⁺, contains a total of 6 electrons in s orbitals. (FALSE)
- Full electron configuration of Strontium (Sr): 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s²
- Configuration of Sr²⁺ ion: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ (losing the two 5s electrons).
- Counting s-electrons: Look at all the s orbitals (1s², 2s², 3s², 4s²). There are 4 energy levels with full s orbitals, giving 2 + 2 + 2 + 2 = 8 electrons in s orbitals, not 6.
Statement 3: The equation for the reaction of barium with water is 2Ba + 2H₂O → 2BaOH + H₂ (FALSE)
- The Trap: The formula given for barium hydroxide is incorrect ( BaOH instead of Ba(OH)₂ ). Barium is in Group 2, so it forms a 2+ ion, requiring two hydroxide ions ( OH⁻ ) for electrical neutrality.
- Correct balanced equation: Ba + 2H₂O → Ba(OH)₂ + H₂
Topics
Module 3: Periodic table and energy · Module 2: Foundations in chemistry · 3.1 The periodic table · 2.2 Electrons, bonding and structure
Question and mark scheme from the OCR A-Level Chemistry examination, Periodic table, elements and physical chemistry (01), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.