OCR A-Level Chemistry Synthesis and analytical techniques (02), November 2020: Question 19

14 marks · Medium difficulty · Structured Questions

Analyze carbonyl compounds F and G regarding homologous series, chemical tests for functional groups, nucleophilic addition mechanism, and heterolytic fission.

Practise this question

Question

Question 19 shows the chemical structures of two carbonyl compounds, F and G. Part (a) asks to explain a homologous series and predict a molecular formula. Part (b) requires describing chemical tests and observations for functional groups in F and G. Part (c) asks to outline the nucleophilic addition mechanism for compound F reacting with HCN, and explain heterolytic fission.
Question text

19 The carbonyl compounds, F and G, shown below, contribute to the flavour of coffee.

O

CH3 H

CH C

H C C O

3 H

F G

(a) Compound F is a member of a homologous series.

(i) Explain the term homologous series.

… [2]

(ii) Predict the molecular formula for the member of this homologous series containing

24 carbon atoms.

… [1]

(b) Describe suitable chemical tests, with observations, that would confirm the presence of the

functional groups in F and G.

… [4]

(c) Compound F reacts with HCN using NaCN(aq) and H+(aq).

(i) Outline the mechanism for the reaction of F with NaCN(aq) and H+(aq) and state the

name of the mechanism. The structure of F has been provided.

Include relevant dipoles, lone pairs and the structure of the organic product.

CH3 H

CH C

H C C O

3 H

Name of mechanism: … [5]

(ii) Explain why the mechanism in (c)(i) involves heterolytic fission.

… [2]

Mark scheme

Show the mark scheme The mark scheme provides answers for question 19, including definitions for a homologous series, molecular formula C24H48O, specific reagents and observations for functional group tests (Tollens', bromine, 2,4-DNP), the full curly-arrow mechanism for nucleophilic addition with dipoles and intermediates, and explanations for heterolytic fission.

AO

Question Answer Marks Guidance

element

19 (a) (i) (series of organic compounds with the) same functional 2 1.1 IGNORE reference to physical properties

group OR same/similar chemical properties/reactions ×2 IGNORE same general formula

DO NOT ALLOW same empirical OR

molecular formula

each successive/subsequent member differs by CH2 Differs by CH2 is not sufficient (no successive)

(ii) C24H48O 1 2.1

(b) F/aldehyde 4 IGNORE use of 2,4-DNP with F

AND

Tollens’ (reagent)

AND ALLOW ammoniacal silver nitrate OR Ag+/NH

Silver (mirror/precipitate/ppt/solid) 2.3 ALLOW black ppt OR grey ppt

G/alkene/C=C

AND

Bromine/Br2 ALLOW bromine water/ Br2(aq)

AND

goes colourless/decolourised 3.3

G/ketone ALLOW errors in spelling for 2,4-DNP

AND ALLOW 2,4(-)DNP OR 2,4(-)DNPH

2,4-dinitrophenylhydrazine ALLOW Brady’s reagent or Brady’s Test

AND ALLOW solid OR crystals OR ppt as

orange/yellow/red precipitate 3.3 alternatives for precipitate

G/ketone ALLOW ammoniacal silver nitrate OR Ag+/NH

AND ALLOW black ppt OR grey ppt

Tollens’ (reagent)

AND ALLOW alterative approach using acidified

no silver mirror/no change/no reaction 3.3 potassium dichromate for tests with F and/or G,

with correct observations, alongside use of 2,4-

DNP

AO

Question Answer 15 Marks Guidance

element

(c) (i) Mechanism 3 marks 5 ANNOTATE ANSWER WITH TICKS AND

CROSSES

Curly arrow must come from lone pair on C

of –CN OR CN–

OR from minus sign on C of –CN ion (then lone

pair on CN– does not need to be shown)

Curly arrow from C=O bond must start from,

Curly arrow from –CN to C atom of C=O

1.2 OR be traced back to, any part of C=O bond

and go to O

Dipole shown on C=O bond, Cδ+ and O δ−,

AND curly arrow from C=O bond to O atom 1.2

Curly arrow from lone pair OR – charge on O– of -------------------------------------------------------------

correct intermediate to H+ 2.5 ALLOW curly arrow to H atom of H2O, i.e.

-----------------------------------------------------------

Product 1 mark

IGNORE attempt to draw curly arrow showing

2.5 breaking of H–O in H2O

--------------------------------------------------------

Name of mechanism 1 mark IGNORE lack of dipole on H2O

Nucleophilic addition 1.1

AO

16 element

(ii) Heterolytic 2 1.2 ALLOW 2 electrons go to one (bonded)

One (bonded) atom/O receives both/2 electrons atom/O

DO NOT ALLOW both pairs of electrons go to

Fission O

Breaking of a covalent bond

IGNORE formation of ions/radicals

For O atom,

ALLOW species

DO NOT ALLOW element or molecule

ALLOW π bond in C=O breaks

IGNORE breaking of C=O bond (no reference

to only one bond breaking)

‘Bond breaking’ is not sufficient

(no reference to covalent)

How to answer it

Carbonyl Compounds, Homologous Series & Mechanisms

What this question tests

This question assesses core organic chemistry knowledge including definitions of a homologous series, predicting molecular formulas, functional group identification tests (Tollens', bromine water, 2,4-DNP), curly arrow mechanisms for nucleophilic addition of HCN to carbonyls, and definitions of heterolytic fission.

Part (a)(i)

Homologous Series Definition

✅ Correct Answer

  • Series of organic compounds with the same functional group AND similar chemical properties.
  • Each successive/subsequent member differs by CH₂ .

❌ Common Errors

  • Stating "differs by CH₂ " without the word successive loses a mark.
  • Mentioning "same general formula" or "same empirical/molecular formula" is ignored or disallowed.
  • Reference to physical properties is ignored by examiners.
Total: 2 marks
Part (a)(ii)

Predicting Molecular Formula

✅ Correct Answer

C₂₄H₄₈O

💡 Key Knowledge

Compound F is an aldehyde with formula C₅H₁₀O . Adding 19 more CH₂ units to reach 24 carbon atoms yields C₅₊₁₉H₁₀₊₃₈O = C₂₄H₄₈O .

Total: 1 mark
Part (b)

Functional Group Chemical Tests

✅ Correct Answers

  • For aldehyde (F): Tollens' reagent ➔ Silver mirror (or black/grey precipitate).
  • For alkene (G): Bromine / Br₂(aq) ➔ Goes colourless / decolourized.
  • For ketone (G): 2,4-dinitrophenylhydrazine (Brady's reagent) ➔ Orange/yellow/red precipitate.
  • Alternative for ketone (G): Tollens' reagent ➔ No silver mirror / no change / no reaction.

🧠 Exam Technique

To score all 4 marks, you must state the reagent AND the specific observation for the targeted functional groups present in F and G. Note that compound G contains both an alkene and a ketone group, while F is an aldehyde.

Total: 4 marks
Part (c)(i)

Nucleophilic Addition Mechanism

✅ Correct Answer & Mechanism Steps

  • Name of mechanism: Nucleophilic addition.
  • Step 1: Curly arrow from lone pair on :CN⁻ to the C atom of C=O .
  • Dipole & Arrow 2: Delta plus ( C δ+ ) and delta minus ( O δ- ) clearly shown on C=O , with a curly arrow starting from the C=O bond going to the O atom.
  • Step 3: Curly arrow from lone pair (or minus charge on O⁻ ) of the intermediate to an H⁺ ion.
  • Product: Correct cyanohydrin structure drawn with -OH and -CN groups attached.

❌ Common Errors

  • Starting curly arrows from the wrong place (e.g., arrow starting from a minus sign rather than the lone pair, or double bonds drawn incorrectly).
  • Omitting partial charges ( δ⁺ / δ⁻ ) on the carbonyl group.
  • Failing to show the lone pair on the cyanide ion attacking the carbon.
Total: 5 marks (3 for mechanism steps, 1 for product, 1 for mechanism name)
Part (c)(ii)

Heterolytic Fission Explanation

✅ Correct Answer

  • Heterolytic: One (bonded) atom / Oxygen receives both / 2 electrons.
  • Fission: Breaking of a covalent bond.

❌ Common Errors

  • Writing "bond breaking" without specifying that it is a covalent bond.
  • Stating "both pairs of electrons go to O" instead of "both/two electrons go to one atom/O".
Total: 2 marks

Topics

Module 4: Core organic chemistry · Module 6: Organic chemistry and analysis · 6.1 Aromatic compounds, carbonyls and acids · 4.1 Basic concepts and hydrocarbons · 4.2 Alcohols, haloalkanes and analysis

Question and mark scheme from the OCR A-Level Chemistry examination, Synthesis and analytical techniques (02), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.