OCR A-Level Chemistry AS Breadth in chemistry (01), June 2022: Question 19

1 mark · Medium difficulty · Multiple Choice

Identify the organic compound that produced the given infrared spectrum from four structural formula options.

Practise this question

Question

A multiple-choice question showing an infrared spectrum with transmittance percentage on the vertical axis and wavenumber in cm^-1 on the horizontal axis ranging from 4000 to 500. The spectrum shows a strong, sharp absorption peak around 1700 cm^-1 and C-H stretching peaks around 3000 cm^-1, with no broad O-H absorption above 3200 cm^-1. Four options are provided: A, CH3COCH2CH3; B, CH3CH2CHOHCH3; C, CH3COCH2CH2OH; and D, CH3CH2COOH.
Question text

19 Which organic compound could have produced the infrared spectrum below?

transmittance

(%)

4000 3000 2000 1500 1000 500

wavenumber / cm–1

A CH3COCH2CH3

B CH3CH2CHOHCH3

C CH3COCH2CH2OH

D CH3CH2COOH

Your answer [1]

Mark scheme

Show the mark scheme The mark scheme indicates that the correct answer for question 19 is A.

19 A 1 AO2.5

How to answer it

Identifying Organic Compounds Using Infrared Spectroscopy

What this question tests

This question assesses your ability to interpret infrared (IR) spectra by matching characteristic absorption peaks (wavenumbers) to specific functional groups, allowing you to correctly identify an unknown organic molecule from a given list of isomers and homologues.

Question 19 (Multiple Choice)

Identifying the Organic Compound from its IR Spectrum

✅ Correct Answer

A: CH₃COCH₂CH₃ (Butan-2-one)

Mark Awarded: 1 / 1 (AO2.5 - Applying chemical knowledge)

💡 Key Knowledge

  • C=O peak: Strong, sharp absorption trough found around 1680–1750 cm⁻¹ (present in ketones, aldehydes, carboxylic acids).
  • C-H stretch: Strong absorption just below 3000 cm⁻¹ representing aliphatic C-H bonds.
  • O-H stretch (alcohol): Broad absorption around 3200–3600 cm⁻¹ (absent here).
  • O-H stretch (acid): Very broad 'broad beard' absorption spanning 2500–3300 cm⁻¹ (absent here).

🧠 Exam Technique

  1. Scan the high wavenumber region ( 3200–4000 cm⁻¹ ) first. Look for a broad OH peak. There is none, so instantly rule out alcohols and carboxylic acids (compounds B, C, and D).
  2. Check the region around 1700 cm⁻¹ . Notice the very intense, sharp trough characteristic of a carbonyl group ( C=O ).
  3. Match remaining options against your findings. Both A and C contain carbonyl groups, but option C also contains an alcohol group ( -OH ) which is missing from the spectrum. Thus, A is the only possible correct structure.

❌ Common Errors

  • Failing to check the 3000+ region: Students often rush straight to the fingerprint region or look only at the carbonyl trough without confirming the absence of O-H groups.
  • Confusing compound types: Confusing the sharp ketone C=O stretch with the very broad carboxylic acid O-H stretch overlapping the C-H region.

Topics

Module 4: Core organic chemistry · Module 6: Organic chemistry and analysis · 4.2 Alcohols, haloalkanes and analysis · 6.3 Analysis

Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.