OCR A-Level Chemistry AS Breadth in chemistry (01), June 2022: Question 6

1 mark · Medium difficulty · Multiple Choice

Deduce the formula of the chloride formed when a Period 3 element X reacts with chlorine, using the given successive ionisation energies.

Practise this question

Question

Multiple choice question showing a table of the first four ionisation energies for a Period 3 element X: 1st is 738, 2nd is 1451, 3rd is 7733, and 4th is 10541 kJ mol^-1. Below the table, it asks for the formula of the chloride formed when X reacts with chlorine, with four options: A (XCl), B (XCl2), C (XCl3), and D (XCl4).
Question text

6 The first four ionisation energies of a Period 3 element X are shown in the table.

Ionisation energy / kJ mol–1

1st 2nd 3rd 4th

738 1451 7733 10 541

Element X is reacted with chlorine.

What is the formula of the chloride formed?

A XCl

B XCl2

C XCl3

D XCl4

Your answer [1]

Mark scheme

Show the mark scheme Mark scheme indicating the correct answer is B for question 6, worth 1 mark.

6 B 1 AO2.1

How to answer it

Determining Element Formula from Successive Ionisation Energies

What this question tests

This question assesses your ability to interpret successive ionisation energy data to identify the group number of a Period 3 element, deduce its stable oxidation state/valency, and predict the chemical formula of its chloride.

Question 6

Analysing Successive Ionisation Energies & Chloride Formula

✅ Correct Answer

B ( XCl₂ )

Element X has 2 valence electrons, meaning it belongs to Group 2 (magnesium, Mg). When reacting with chlorine (Group 17), it forms an ionic compound with a 2+ metal ion and 1- chloride ions, resulting in the formula XCl₂ .

💡 Key Knowledge

  • Successive Ionisation Energies: Values increase as each electron is removed due to a decreasing shielding effect and increasing net positive charge.
  • Finding Shell/Group: A huge, sharp jump in ionisation energy indicates that an electron is being removed from a new, inner principal quantum shell closer to the nucleus.
  • Group 2 Behaviour: Element X shows a massive jump between the 2nd and 3rd ionisation energies (1451 to 7733 kJ mol⁻¹), proving there are 2 electrons in the outer shell.

🧠 Exam Technique

  • Scan the data horizontally from left to right looking for the largest proportional difference between consecutive values.
  • Count how many ionisation energies come before the huge jump. That number equals the group number for main-group elements.
  • Link the identified group number directly to its typical ionic charge (+2 for Group 2) to deduce the formula with chlorine (-1).

❌ Common Errors

  • Counting the wrong side: Students sometimes count the number of ionisation energies after the jump instead of before it.
  • Confusing Period and Group: The question states it is a Period 3 element (so it is Mg), but answering requires knowing its Group number (Group 2), not its period.
  • Incorrect valency translation: Mismatching charges when writing the ionic formula, leading to incorrect guesses like XCl or XCl₃ .
Mark Scheme Allocation: 1 mark total for selecting option B. Assessed under Assessment Objective 2.1 (Applying knowledge of ionisation energies to a novel context).

Topics

Module 2: Foundations in chemistry · Module 3: Periodic table and energy · 2.1 Atoms and reactions · 2.2 Electrons, bonding and structure · 3.1 The periodic table

Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.