OCR A-Level Chemistry Unified chemistry (03), June 2022: Question 4
8 marks · Hard difficulty · Structured Questions
Explain the effect of temperature and silver nitrate addition on the cobalt complex equilibrium, including rates and enthalpy changes.
Practise this questionQuestion
Question text
4 Two students plan to investigate Equilibrium 4.1, shown below.
CoCl 2−(aq) + 6H O(l) [Co(H O) ]2+(aq) + 4Cl −(aq) Equilibrium 4.1
42 2 6
blue pink
(a) The students are supplied with the equilibrium mixture in Equilibrium 4.1 at room
temperature.
• One student heats 20 cm3 of the mixture to 50 °C.
• The other student heats 20 cm3 of the mixture to 90 °C.
The students use colorimetry to observe how the colour of the equilibrium mixture changes
over time.
• The colorimeter is set up so that the greater the absorbance, the greater the
concentration of [Co(H O) ]2+.
• The initial absorbance is set to zero.
• The absorbance is recorded every 30 seconds.
The students plot the graph below from the results of the experiment.
50°C
90°C
Absorbance
0,0 Time/s
Use the graph and relevant chemical theory to answer the following. Include all reasoning:
• Explain the different initial rates at 50 °C and 90 °C.
• Predict the sign of ∆H for the forward reaction in Equilibrium 4.1.
… [4]
(b) The students investigate how addition of aqueous silver nitrate, AgNO3(aq), affects the
equilibrium position in Equilibrium 4.1.
The graph shows the changes in the equilibrium concentrations of CoCl 2–, Cl – and
[Co(H O) ]2+ after addition of the AgNO (aq).
26 3
The AgNO3(aq) is added at time = t1.
CoCl 2–
Cl –
Concentration
[Co(H O) ]2+
0 t Time
(i) Explain why the Cl – concentration drops sharply at time = t .
… [1]
(ii) Explain the changes in concentration of CoCl 2–, Cl – and [Co(H O) ]2+ after time = t .
42 6 1
Refer to Equilibrium 4.1 in your answer.
… [3]
Mark scheme
Show the mark scheme
Question Answer Marks AO Guidance
element
4 (a) 4
ORA for 50 ºC
At 90 ºC/higher temperature
• Faster rate AND more frequent collisions AO2.7 IGNORE more successful collisions
×1
• More particles have the activation energy/Ea or
AO1.2 ALLOW more molecules have enough
greater energy to react
×1
ALLOW atoms/molecules/ions
• [Co(H O) ]2+ is lower
26 AO2.3 ALLOW decreases
×1
• (forward reaction) ∆H –ve OR exothermic
AO1.2
×1
(b) (i) Cl– /It/They react with AgNO / Ag+ /silver ions 1 AO3.2 IGNORE chlorine/Cl for chloride ion
OR
AgCl formed IGNORE AgCl2
OR
Ag+ + Cl– → AgCl
22 element
(ii) 3 AO3.1
[CoCl 2–] decreases AND [Co(H O) ]2+ increases ×2
42 6
IGNORE missing charges and small slips in
formulae, e.g. CoCl4 missing bracket, etc
Cl– increase is 4 × change in [CoCl 2–] / [Co(H O) ]2+ IGNORE Cl– for changes in concentration
42 6
Equilibrium shifts to right AO3.2 ALLOW suitable alternatives for ‘shifts to
×1 right’, e.g. towards products
OR in forward direction OR ‘favours the right’
How to answer it
Transition Metal Equilibria & Kinetics
This question assesses your understanding of transition metal complex equilibria, the kinetics of temperature changes on initial rates (Maxwell-Boltzmann distribution), enthalpy changes in reversible reactions, and Le Chatelier's principle involving precipitation reactions (ionic equations and stoichiometry).
Part (a): Initial Rates & Enthalpy Change
Investigating the effect of temperature on Equilibrium 4.1
✅ Correct Answer Breakdown (4 Marks)
- Initial rate: At 90 °C, the initial rate is faster due to more frequent collisions.
- Activation Energy: More particles have energy greater than or equal to the activation energy (Ea).
- Extent of reaction: At 90 °C, the final equilibrium absorbance is lower, meaning the equilibrium concentration of [Co(H₂O)₆]²⁺ is lower.
- Enthalpy sign: The forward reaction is exothermic, so ΔH is negative (-ve). Raising temperature shifts equilibrium in the endothermic direction (backwards).
💡 Key Knowledge
- Rate vs Position: Higher temperature always increases rate (faster initial gradient), but shifts the position of equilibrium depending on the sign of ΔH.
- Colorimetry link: The question states higher absorbance equals higher [[Co(H₂O)₆]²⁺]. Looking at the graph, 50 °C gives a higher final plateau than 90 °C.
🧠 Exam Technique
- Structure your answer clearly: split it into a kinetic argument (rate & temperature) and a thermodynamic argument (equilibrium yield & enthalpy).
- Use comparative language ("more frequent", "higher proportion"). Avoid vague terms like "particles move faster" without linking to collision frequency.
❌ Common Errors
- Stating that "more successful collisions" happen because particles collide harder (Examiners specifically penalise or ignore "successful" unless tied to Ea).
- Confusing the effect of temperature on rate with its effect on equilibrium yield.
Part (b)(i): Precipitation & Chloride Concentration
Effect of adding aqueous silver nitrate
✅ Correct Answer (1 Mark)
Chloride ions (Cl⁻) react with added silver ions (Ag⁺) to form a silver chloride precipitate (AgCl).
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
🧠 Exam Technique & Guidance
- A simple ionic equation or clear statement that Cl⁻ is removed by forming AgCl(s) secures the mark instantly.
- Note: Examiners accept "react with Ag⁺ / silver ions" or "AgCl formed". Ignore references to spelling variations like "chlorine" instead of chloride ion.
Part (b)(ii): Le Chatelier's Principle & Stoichiometry
Explaining concentration changes after time t₁
✅ Correct Answer Breakdown (3 Marks)
- Concentration shifts: [CoCl₄]²⁻ decreases AND [Co(H₂O)₆]²⁺ increases.
- Stoichiometric ratio: The increase in [Co(H₂O)₆]²⁺ (and decrease in [CoCl₄]²⁻) is accompanied by a 4× larger drop in [Cl⁻] concentration, reflecting the stoichiometric coefficient of 4Cl⁻ in the equation.
- Equilibrium shift: Equilibrium shifts to the right (towards products) to replace the removed Cl⁻ ions.
📐 Stoichiometry & Ratio Check
Look closely at the equation coefficients:
CoCl₄²⁻(aq) + 6H₂O(l) ⇌ [Co(H₂O)₆]²⁺(aq) + 4Cl⁻(aq)
Because 4 moles of Cl⁻ are produced for every 1 mole of [CoCl₄]²⁻ reacted, the vertical drop on the graph for Cl⁻ must be precisely 4 times steeper/larger than the changes in the complex ions.
❌ Common Errors
- Failing to link the magnitude of the concentration changes to the stoichiometric balancing numbers in Equilibrium 4.1.
- Stating the equilibrium shifts left instead of right when Cl⁻ is removed. (Remember Le Chatelier: system opposes the change by trying to produce more Cl⁻, shifting forward).
Topics
Module 5: Physical chemistry and transition elements · Module 3: Periodic table and energy · 5.1 Rates, equilibrium and pH · 5.3 Transition elements · 3.2 Physical chemistry
Question and mark scheme from the OCR A-Level Chemistry examination, Unified chemistry (03), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.