OCR A-Level Chemistry AS Breadth in chemistry (01), June 2023: Question 3
1 mark · Medium difficulty · Multiple Choice
Calculate the atom economy of hydrogen for the industrial preparation of hydrogen from methane and steam.
Practise this questionQuestion
Question text
3 Hydrogen can be prepared industrially by the reaction of methane with steam.
The equation is shown below.
CH4(g) + 2H2O(g) 4H2(g) + CO2(g)
What is the atom economy of hydrogen for this process?
A 3.8%
B 4.3%
C 15.4%
D 17.4%
Your answer [1]
Mark scheme
Show the mark scheme
3 C 1 AO1.2
How to answer it
Calculating Atom Economy in Industrial Processes
This question assesses your understanding of quantitative chemistry, specifically the application of the atom economy formula to a balanced chemical equation. It tests your ability to account for stoichiometric coefficients (moles) when calculating total molar masses of reactants and desired products.
Question 3 (Multiple Choice)
Reaction of Methane with Steam
✅ Correct Answer: C (15.4%)
Option C is the correct choice based on applying the stoichiometric atom economy formula correctly.
💡 Key Knowledge
- Atom Economy Formula: (Mass of desired product / Total mass of all reactants) × 100
- Always multiply individual molar masses by their balancing numbers (stoichiometric coefficients) from the equation.
🧠 Exam Technique
For multiple-choice questions involving calculations, double-check whether you remembered to multiply the molar mass of water by 2 and hydrogen by 4 before dividing!
❌ Common Errors
- Omitting the stoichiometric coefficients (e.g., using Mr of H₂ as 2 instead of 4 × 2 = 8).
- Including all products in the denominator instead of all reactants.
📐 Step-by-Step Calculation
Equation: CH₄(g) + 2H₂O(g) → 4H₂(g) + CO₂(g)
- Find the molar mass of the desired product (H₂):
Desired product is 4 moles of H₂.
Mass = 4 × (2 × 1.0) = 8.0 g mol⁻¹ - Find the total molar mass of all reactants:
Reactants: 1 mole of CH₄ and 2 moles of H₂O.
Mr of CH₄ = 12.0 + (4 × 1.0) = 16.0 g mol⁻¹
Mr of H₂O = (2 × 1.0) + 16.0 = 18.0 g mol⁻¹
Total reactant mass = 16.0 + (2 × 18.0) = 16.0 + 36.0 = 52.0 g mol⁻¹ - Calculate the Atom Economy:
Atom Economy = (8.0 / 52.0) × 100 = 15.384...% = 15.4% (to 3 sig figs)
Topics
Module 2: Foundations in chemistry · 2.1 Atoms and reactions
Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.