OCR A-Level Chemistry AS Depth in chemistry (02), June 2023: Question 5

9 marks · Medium difficulty · Structured Questions

Name alcohol A, construct an equation for its dehydration to form an alkene, explain its E/Z isomerism using CIP rules, draw a polymer section from monomer E and explain its water solubility, and outline useful processing methods for waste polymers.

Practise this question

Question

Question 5 about alkenes and polymers. Part (a) shows the skeletal formula of alcohol A and asks for its systematic name, an equation for the formation of alkene D by elimination, and an explanation of E/Z isomerism for alkene B using Cahn-Ingold-Prelog priority rules with a table of skeletal structures for alkenes B and C. Part (b) shows the structure of compound E and asks to draw a section of the polymer formed showing two repeat units, explain why it is soluble in water, and outline two useful ways to process waste hydrocarbon polymers.
Question text

5 This question is about alkenes.

(a) A mixture of alkenes is produced when water is eliminated from alcohol A.

OH

Alcohol A

(i) What is the systematic name of alcohol A?

… [1]

(ii) Alcohol A is refluxed with an acid catalyst.

• A mixture of alkene isomers B, C and D is formed.

• Alkenes B and C show E/Z isomerism but alkene D does not.

Construct the equation for the formation of alkene D from alcohol A.

Show the structure of the organic product.

[2]

(iii) The skeletal formulae of alkenes B and C are shown below.

Alkene B Alkene C

Skeletal formula

Isomer Z E

Use the Cahn-Ingold-Prelog priority rules to explain why alkene B is the Z isomer.

… 15 [2]

(b) A chemistry company is developing water-soluble polymers.

The chemists decide to use compound E, shown below, as the monomer.

H CH2 OH

C C

H H

Compound E

(i) Draw a section of the polymer formed, showing two repeat units, and suggest why this

polymer is likely to be soluble in water.

Section of polymer (two repeat units)

Reason for solubility in water …

[2]

(ii) Outline two ways that waste hydrocarbon polymers can be processed usefully, rather

than being disposed of in landfill sites.

1 …

2 …

[2]

Mark scheme

Show the mark scheme Mark scheme for question 5 showing acceptable answers for naming alcohol A, the dehydration equation and structure, the Cahn-Ingold-Prelog explanation for E/Z isomerism, the polymer repeat unit structure and hydrogen bonding explanation for solubility, and useful waste polymer processing methods.

AO

Question Answer Marks Guidance

element

5 (a) (i) 3-methylpentan-2-ol ✓ 1 AO2.1 IGNORE lack of hyphens or addition of commas

ALLOW 3-methylpentane-2-ol

DO NOT ALLOW

2-methylpentan-3-ol

3-methylpent-2-ol

3-methpentan-2-ol

3-methypentan-2-ol

3-methlypentan-2-ol

(ii) OH 2 AO2.7 ALLOW any combination of skeletal OR

2 structural OR displayed formula as long as

unambiguous

+ H2O

Correct structure of organic product ✓

DO NOT ALLOW additional reactants such as

H+ or [O] in the equation.

Balanced equation ✓

ALLOW incorrect isomer 3-methylpent-2-ene

for balancing mark.

AO

24 element

5 (a) (iii) Priority groups on same side ✓ 2 ALLOW suitable alternatives to ‘priority’

AO3.1 e.g. Groups with highest atomic number or

2 more important groups etc.

ALLOW priority groups are both on the top

High(est) priority groups are CH3CH2 and CH3 IGNORE references to relative mass of

OR groups, Ar, Mr,

Low(est) priority groups are CH3 and H ✓

ALLOW identification by name e.g. ethyl and

methyl, or by circling on the structure.

IF ‘priority’ is not mentioned ALLOW 1

mark for CH3CH2 and CH3 are on same side OR

H and CH3 are on same side

AO

25 element

5 (b) (i) Section of polymer ALLOW correct structural OR displayed OR

OH OH 2 AO2.5 skeletal formula.

ALLOW alternating side chains i.e.

CH2 H CH2 H OH OH

C C C C CH2 H H CH2

H H H H ✓ C C C C

H H H H

IGNORE brackets and use of ‘n’

IGNORE incorrect connectivity for -CH2OH

DO NOT ALLOW -HO

End bonds MUST be shown (solid or dotted)

AO3.1

DO NOT ALLOW one repeat unit

Question asks for 2 repeat units.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Reason for solubility in water

OH/alcohol groups form hydrogen bonds with water ✓ DO NOT ALLOW ‘it forms hydrogen bonds’

(ii) Any two ✓✓ 2 AO1.1 IGNORE Reused

• Recycled (to make other plastic materials) 2

• Combustion to generate energy / electricity ALLOW Used as a fuel to generate energy /

electricity

AO

26 element

• As (organic) feedstock

How to answer it

Alkenes, Isomerism, and Polymers

What this question tests:
This question assesses core organic chemistry competencies: applying IUPAC nomenclature rules to branched alcohols, writing dehydration equations for alkene formation, applying Cahn-Ingold-Prelog (CIP) priority rules to explain E/Z stereoisomerism, drawing addition polymer sections from monomers (paying attention to repeat unit counts), explaining physical properties such as water solubility using intermolecular forces, and outlining sustainable processing methods for waste polymers.
Question 5(a)(i) — IUPAC Nomenclature

Naming Alcohol A

✅ Correct Answer

3-methylpentan-2-ol

Marks: 1

💡 Key Knowledge

  • Find the longest continuous carbon chain containing the principal functional group (the -OH group). Here, it is 5 carbons long (pentan).
  • Number the chain from the end that gives the principal functional group the lowest possible number (carbon 2).
  • Identify substituents and their positions (methyl group at carbon 3).

❌ Common Errors

  • Incorrect numbering giving 2-methylpentan-3-ol or 3-methylpentan-4-ol .
  • Incorrect spelling of prefixes/suffixes (e.g., missing hyphens or commas). Examiners are lenient on hyphens/commas, but strict on number locants.
Question 5(a)(ii) — Dehydration Equation

Formation of Alkene D

✅ Correct Answer

Structural or skeletal equation showing alcohol A losing water ( H₂O ) to form alkene D ( CH₃CH₂CH=CHCH₃ or CH₃CH₂CH₂CH=CH₂ depending on isomer, yielding 3-methylpent-2-ene or 3-methylpent-1-ene ) plus H₂O .

Marks: 2 (1 for correct organic product structure, 1 for balanced equation)

🧠 Exam Technique

  • Ensure formulas represent valid chemical structures. Skeletal, structural, or displayed formulas are all accepted as long as connectivity is unambiguous.
  • Do not include catalysts like H⁺ or [O] inside the balanced equation as reactants unless asked; keep it strictly as reactant yielding organic product + H₂O .
Question 5(a)(iii) — E/Z Isomerism

Explaining CIP Priority Rules

✅ Correct Answer

  • Priority groups are on the same side of the double bond.
  • High(est) priority groups are -CH₂CH₃ (ethyl) and -CH₃ (methyl) [OR low priority groups are -CH₃ and -H ].
Marks: 2

💡 Key Knowledge

  • CIP Rules: Assign priorities based on atomic number attached directly to the carbon atoms of the C=C double bond. Higher atomic number = higher priority.
  • Z (Zusammen): Higher priority groups are on the same side (zame side) of the double bond.
  • E (Entgegen): Higher priority groups are on opposite sides.

❌ Common Errors

  • Vague answers referencing "heavier groups" or "larger molecules" without specifying atoms attached directly to the C=C carbons.
  • Confusing E and Z assignments.
Question 5(b)(i) — Polymers and Solubility

Polymer Structure and Water Solubility

✅ Correct Answer

Polymer section (two repeat units):
A carbon-carbon single bond backbone with alternating side chains containing -CH₂OH and -H groups, with clear, open continuation bonds at both ends.

Reason for solubility:
The -OH (alcohol) groups form hydrogen bonds with water molecules.

Marks: 2 (1 for polymer section showing 2 repeat units with correct end bonds, 1 for hydrogen bonding with water)

🧠 Exam Technique

  • Watch the repeat unit count! The question explicitly asks for two repeat units. Drawing only one unit will lose structural credit.
  • Continuation bonds must extend outside the brackets or past the terminal carbons (solid or dotted lines cutting through the brackets/ends).
  • For intermolecular forces, always state what forms bonds with what (e.g., "-OH groups form hydrogen bonds with water"). Avoid shorthand like "it forms hydrogen bonds" without naming the species involved.

❌ Common Errors

  • Leaving out continuation bonds at the ends of the polymer chain.
  • Writing -HO instead of -OH for the alcohol group connection.
Question 5(b)(ii) — Sustainable Polymer Processing

Useful Processing of Waste Polymers

✅ Correct Answer

Any two of the following:

  • Recycled (to make other plastic materials / melted and reshaped).
  • Combustion to generate energy / electricity (used as a fuel).
  • As an organic feedstock (for cracking / producing chemicals or plastics).
Marks: 2 (1 mark per valid processing method, max 2)

💡 Key Knowledge

  • Disposing of polyalkenes is challenging due to their unreactivity (non-polar C-C and C-H bonds).
  • Useful chemical processing strategies recover value from waste plastics rather than sending them straight to landfill.

Topics

Module 4: Core organic chemistry · Module 6: Organic chemistry and analysis · 4.1 Basic concepts and hydrocarbons · 4.2 Alcohols, haloalkanes and analysis · 6.2 Nitrogen compounds, polymers and synthesis

Question and mark scheme from the OCR A-Level Chemistry examination, AS Depth in chemistry (02), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.