OCR A-Level Chemistry Periodic table, elements and physical chemistry (01), June 2023: Question 22
14 marks · Hard difficulty · Structured Questions
Explain d-block and transition elements using electron configurations, describe precipitation and ligand substitution reactions for copper or chromium, determine complex ion properties, and construct a redox equation for dichromate and vanadium(III).
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Question text
22 This question is about the d-block elements in Period 4 of the periodic table (Sc to Zn).
(a)* Explain, with examples from Period 4, what is meant by the terms d-block element and
transition element.
Explain why some d-block elements are not transition elements.
Use electron configurations to support your explanations.
… [6]
Additional answer space if required.
(b) (i) Describe precipitation reactions using either copper or chromium ions as examples.
Include equations.
… [2]
(ii) Describe ligand substitution reactions using either copper or chromium ions as
examples.
Include equations.
… [2]
(c) The ethanedioate ion, C O 2–, is a bidentate ligand.
A complex ion of cobalt(III) contains two ethanedioate ligands and two water ligands.
Determine the charge of this complex ion and the coordination number of cobalt in the
complex ion.
Charge of complex ion …
Coordination number of cobalt … [2]
(d) An acidified solution containing Cr O 2– ions reacts with vanadium(III) ions in a redox
reaction to form a solution containing Cr3+ ions and VO + ions.
Construct the overall equation for this reaction.
… [2]
Mark scheme
Show the mark scheme
AO
Question Answer Marks Guidance
element
22 (a) Please refer to the marking instructions on page 5 of this 6 AO1.1 Indicative scientific points may include:
mark scheme for guidance on how to mark this question. 4
Terms
Level 3 (5–6 marks) AO1.2 d-block element: element with highest energy/
Explains the terms ‘d-block element’ AND ‘transition element’ 2 valence electron in d-orbital/sub-shell OR d
AND subshell is being filled
Explains why not all d-block are transition elements DO NOT ALLOW d block for d-subshells
AND
At least THREE correct electron configurations (need to be Transition element: element forming one or
one electron configuration of d block atom, transition element more ions (allow atom and ion - IUPAC definition)
ion and zinc (or scandium) ion with incomplete/partially filled d-subshell/d-
orbitals
There is a well-developed line of reasoning which is clear and DO NOT ALLOW d shell
logically structured. The information presented is relevant and
substantiated. d-block element:
ALLOW examples with an ion with an incomplete
Level 2 (3–4 marks) d-subshell, e.g. Fe2+ - [Ar]4s03d6
Explains both the terms ‘d-block element’ and
‘transition element’ ALLOW examples with highest energy electrons in
AND a d-subshell, e.g. Fe - [Ar]4s23d6
Explains why not all d-block are transition elements
OR Not all d-block are transition elements:
Explains both the terms ‘d-block element’ and Sc and Zn form ions with complete or empty d-
‘transition element’ shells ORA
AND
Links terms to at least TWO correct electron For Sc3+, ALLOW Sc+3 OR Sc forms a 3+ ion
configurations For Zn2+, ALLOW Zn+2 OR Zn forms a 2+ ion
OR
Explains the terms ‘d-block element’ OR ‘transition Sc3+ 1s22s22p63s23p6
element’ Sc3+ AND d subshell empty / d orbital(s) empty
AND Zn2+ 1s22s22p63s23p63d10
Explains why not all d-block are transition elements Zn2+ AND d subshell full / ALL d orbitals full
AND
Links terms to at least ONE correct electron
configuration
28 AO
element
ALLOW minor slips on inner shell electron
There is a line of reasoning presented with some structure. configurations
The information presented is relevant and supported by some -----------------------------------------------------------
evidence.
Level 1 (1–2 marks) NOTE: A clear and logically structured response
would link definitions to electron configurations to
Explains the term ‘d-block element’ OR ‘transition support the explanations. If stated, for the level,
element’ there should be clear indication that the d subshell
AND is full/empty or partially full
Attempts to link terms with ONE correct electron
configuration
OR
Explains the term ‘d-block element’ AND ‘transition
element’
OR
Explains the term ‘d-block element’ OR ‘transition
element’
AND Explains why not all d-block are transition
elements
OR
Any TWO out of THREE correct electron
configurations (one element and one ion that is a
transition element and one ion that is not a transition
element)
There is an attempt at a logical structure with a line of
reasoning. The information is in the most part relevant.
0 marks No response or no response worthy of credit
29 AO
element
(b) (i) 2 ALLOW any one precipitation reaction
any one ligand substitution
AO1.1 ALLOW other correct equations linked to correct
colour change -check with TL
Cu
Precipitation with OH–/NH 2 marks AO1.2 IGNORE state symbols
(Pale) Blue (precipitate) AND Cu(OH)2 (can be seen in DO NOT ALLOW dark/royal blue (complex ion
the equation)✓ colour)
Cu2+ + 2OH– → Cu(OH) ✓ ALLOW Cu(H O) (OH)
22 4 2
ALLOW
[Cu(H O) ]2+ + 2OH– → Cu(OH) (H O) + 2H O
26 2 2 4 2
OR [Cu(H O) ]2+ + 2OH– → Cu(OH) + 6H O
26 2 2
OR [Cu(H O) ]2+ + 2NH → Cu(OH) (H O) + 2NH +
26 3 2 2 4 4
OR
Precipitation with I– 2 marks
White (precipitate) AND CuI ✓
2Cu2+ + 4I- → 2CuI + I ✓ ------------------------------------------------------------------
-------------------------------------------------------------------------------
Cr
Precipitation with OH–/NH 2 marks
(Dark) Grey-Green (precipitate) AND Cr(OH)3 ✓ ALLOW Green
ALLOW Cr(H2O)3(OH)3
ALLOW
[Cr(H O) ]3+ + 3OH– → Cr(OH) (H O) + 3H O
26 3 2 3 2
Cr3+ + 3OH– → Cr(OH) ✓ OR [Cr(H O) ]3+ + 3NH → Cr(OH) (H O) + 3NH +
32 6 3 3 2 3 4
OR [Cr(H O) ]3+ + 3OH– → Cr(OH) + 6H O
26 3 2
30 AO
element
(b) (ii) Cu 2 ALLOW other correct equations linked to correct
Ligand substitution with NH /Cl– 2 marks colour change -check with TL
NH3 Deep/dark/royal blue (solution) AO1.1
AND [Cu(NH ) (H O) ]2+ ✓ ALLOW ECF on any incorrect charges of the
34 2 2
complex ions when linked to colour via an
[Cu(H O) ]2+ + 4NH → [Cu(NH ) (H O) ]2+ + 4H O ✓ AO1.2 equation.
26 3 3 4 2 2 2
OR
Cl – yellow (solution)
AND [CuCl ]2– ✓
[Cu(H O) ]2+ + 4Cl – → [CuCl ]2– + 6H O ✓
26 4 2
-------------------------------------------------------------------------------
Cr
Ligand substitution with NH3 2 marks
NH3
Purple (solution) AND [Cr(NH ) ]3+ ✓
[Cr(H O) ]3+ + 6NH →[Cr(NH ) ]3+ + 6H O ✓
26 3 3 6 2
OR
Dark Green (solution) AND [Cr(OH) ]3- ✓
[Cr(H O) ]3+ + 6OH- →[Cr(OH) ]3- + 6H O ✓
26 6 2
(c) Charge: –1 OR – OR 1– ✓ 2 AO1.2 ALLOW [Co(C O ) (H O) ]–
24 2 2 2
DO NOT ALLOW Co–
Coordination number: 6 ✓ IGNORE sign
AO
31 element
(d) 3V3+ + Cr O 2– + 2H+ → 3 VO + + 2Cr3+ + H O 2
27 2 2
ALL reactant and product species correct ✓ AO2.5 IGNORE Balancing and electrons for first mark
Correct balancing (of correct equation) AND cancelling of AO2.6 DO NOT ALLOW electrons in final answer
species ✓
How to answer it
Transition Metals and Complex Ions Study Guide
This question assesses your understanding of Period 4 d-block elements, the strict chemical definition of transition elements, electron configurations, precipitation reactions, ligand substitution mechanisms, complex ion formulas, coordination numbers, and balancing complex redox equations in acidic conditions.
Part (a): Defining d-Block vs Transition Elements
6-Mark Level of Response Question
💡 Key Knowledge
- d-block element: An element whose highest energy/valence electron is in a d-orbital/subshell.
- Transition element: An element that forms at least one stable ion with an incompletely/partially filled d-subshell/d-orbitals.
- Why Sc and Zn aren't transition elements: Sc³⁺ has an empty d-subshell ([Ar]3d⁰). Zn²⁺ has a completely full d-subshell ([Ar]3d¹⁰). Neither forms stable ions with incomplete d-orbitals.
🧠 Exam Technique
- This is a Level of Response (LoR) question. To hit Level 3 (5–6 marks), you must cover all three pillars: definitions of both terms, why non-transition elements exist, and include at least three correct electron configurations (e.g., a d-block atom, a transition element ion, and Zn or Sc ion).
- Use full subshell notation (e.g., 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹ ) or noble gas shorthand ( [Ar] 4s² 3d¹ ).
❌ Common Errors
- Saying "d-block has incomplete d-subshell" — this is the definition for a transition element, not a d-block element!
- Forgetting to remove 4s electrons first when writing ion configurations (e.g., writing Zn²⁺ as [Ar] 4s² 3d⁸ instead of [Ar] 3d¹⁰ ).
Part (b)(i): Precipitation Reactions of Copper or Chromium
Describing Precipitation with Equations (2 Marks)
✅ Correct Answer Examples
Copper with OH⁻ / NH₃:
Forms a pale blue precipitate of Cu(OH)₂ .
Equation: Cu²⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s)
(Hexa-aquo equations like [Cu(H₂O)₆]²⁺ + 2OH⁻ → Cu(OH)₂(H₂O)₄ + 2H₂O are also fully accepted).
Chromium with OH⁻ / NH₃:
Forms a dark grey-green precipitate of Cr(OH)₃ .
Equation: Cr³⁺(aq) + 3OH⁻(aq) → Cr(OH)₃(s)
🧠 Exam Technique
Always state the colour of the precipitate alongside the balanced chemical equation. Make sure states or correct charge balancing are managed. Equations can be written using simple metal ions ( Cu²⁺ ) or complex aqua ions ( [Cu(H₂O)₆]²⁺ ).
Part (ii): Ligand Substitution Reactions
Describing Ligand Exchange (2 Marks)
✅ Correct Answer Examples
Copper with Excess NH₃:
Observation: Deep/dark royal blue solution.
Equation: [Cu(H₂O)₆]²⁺ + 4NH₃ → [Cu(NH₃)₄(H₂O)₂]²⁺ + 4H₂O
Copper with Excess Cl⁻:
Observation: Yellow solution (or green depending on mixture).
Equation: [Cu(H₂O)₆]²⁺ + 4Cl⁻ → [CuCl₄]²⁻ + 6H₂O
❌ Common Errors
- Confusing precipitation with ligand substitution. Substitution changes the ligand count/identity in solution without necessarily forming a solid.
- Incorrect coordination numbers for chloro complexes (chloride is a large ligand, so only 4 fit around copper: [CuCl₄]²⁻ ).
Part (c): Complex Ion Charge and Coordination Number
Cobalt(III) Complex with Ethanedioate and Water (2 Marks)
📐 Step-by-Step Calculation
- Identify components: Cobalt is in oxidation state +3. It contains two bidentate ethanedioate ligands ( C₂O₄²⁻ ) and two water ligands ( H₂O , which are neutral).
- Calculate total charge:
Co = +3
2 × (C₂O₄²⁻) = 2 × (-2) = -4
2 × (H₂O) = 2 × (0) = 0
Overall charge = (+3) + (-4) + (0) = -1 - Determine coordination number: Each ethanedioate is bidentate (forms 2 coordinate bonds) = 2 × 2 = 4 bonds. Each water is monodentate = 2 × 1 = 2 bonds. Total coordination number = 4 + 2 = 6 .
✅ Final Answers
Charge of complex ion: -1 (or 1-)
Coordination number of cobalt: 6
Part (d): Constructing a Redox Equation
Acidified Dichromate and Vanadium(III) Reaction (2 Marks)
✅ Correct Answer
3V³⁺ + Cr₂O₇²⁻ + 2H⁺ → 3VO²⁺ + 2Cr³⁺ + H₂O
🧠 Exam Technique & Steps
- Write down reactants ( Cr₂O₇²⁻ , V³⁺ , H⁺ ) and products ( VO²⁺ , Cr³⁺ , H₂O ).
- Balance oxidation states: V goes from +3 to +4 (loss of 1 e⁻ per V). Cr goes from +6 to +3 (gain of 3 e⁻ per Cr atom; 6 e⁻ total per Cr₂O₇²⁻ ion).
- Multiply V³⁺ and VO²⁺ by 3 to balance electrons with the dichromate reduction half-equation.
- Balance oxygen using H₂O and hydrogen using H⁺ .
❌ Common Errors
Leaving free electrons in the final equation or failing to scale the vanadium species to match the 6 electrons released by one dichromate ion.
Topics
Module 5: Physical chemistry and transition elements · 5.3 Transition elements
Question and mark scheme from the OCR A-Level Chemistry examination, Periodic table, elements and physical chemistry (01), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.