OCR A-Level Chemistry Synthesis and analytical techniques (02), June 2023: Question 11

1 mark · Medium difficulty · Multiple Choice

Identify the organic compound that produced the given infrared spectrum from four given structural formulae.

Practise this question

Question

An infrared spectrum showing transmittance percentage against wavenumber from 4000 to 500 cm-1. Below the spectrum, a multiple-choice table presents four organic structures labeled A, B, C, and D containing benzene rings with various functional groups (A: benzoic acid, B: 4-methylphenyl acetate, C: 4-hydroxybenzaldehyde, D: 4-methoxybenzyl alcohol), with a box below to write the answer.
Question text

11 The infrared spectrum of an organic compound is shown below.

transmittance (%) 50

4000 3000 2000 1500 1000 500

wavenumber / cm–1

Which compound could have produced this spectrum?

A COOH

B H C OCOCH

C HO CHO

D HOCH OCH

Your answer

[1]

Mark scheme

Show the mark scheme The mark scheme table shows question number 11 with the correct answer C, worth 1 mark under assessment objective AO2.1.

11 C 1 AO2.1

How to answer it

Identifying Organic Structures Using Infrared (IR) Spectroscopy

What this question tests

This question assesses your ability to interpret an infrared (IR) spectrum by identifying characteristic absorption peaks for specific functional groups (such as O–H, C=O, and C–H stretches) and matching those diagnostic frequencies to the correct molecular structure from a given set of options.

Question 11 (Multiple Choice)

Analysis & Solution

✅ Correct Answer: C

Compound C contains a phenol group (aromatic O–H) and an aldehyde group (–CHO), both of which account for the key diagnostic absorbances seen in the spectrum.

Mark Awarded: 1 / 1 for selecting C

💡 Key Knowledge (Diagnostic Peaks)

  • Broad peak around 3200–3600 cm⁻¹: Indicates hydrogen-bonded O–H stretching (present in phenols/alcohols/carboxylic acids).
  • Sharp, deep peak around 1650–1750 cm⁻¹: Indicates C=O stretching (carbonyl group).
  • Peaks just below 3000 cm⁻¹: C–H aliphatic stretching.

🧠 Exam Technique

Process of elimination is your best tool here:

  • Look at the very broad absorption stretching from ~3200 cm⁻¹ downwards. This rules out options lacking an O–H group.
  • Check for the sharp carbonyl (C=O) peak around 1700 cm⁻¹. Compound A has a carboxylic acid (broad O–H from 2500–3300 cm⁻¹ which is not present here), whereas C has an aldehyde C=O and a clean phenolic O–H.

❌ Common Errors

  • Confusing O–H types: Mistaking the very wide carboxylic acid O–H absorption envelope (which spreads heavily across 2500–3300 cm⁻¹) for a standard alcohol/phenol O–H peak.
  • Ignoring the fingerprint region: Spending too much time below 1500 cm⁻¹ instead of focusing on the diagnostic functional group region above 1500 cm⁻¹.

Topics

Module 6: Organic chemistry and analysis · Module 4: Core organic chemistry · 6.3 Analysis · 4.2 Alcohols, haloalkanes and analysis

Question and mark scheme from the OCR A-Level Chemistry examination, Synthesis and analytical techniques (02), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.