OCR A-Level Chemistry Synthesis and analytical techniques (02), June 2024: Question 18
14 marks · Medium difficulty · Structured Questions
Write the equation, mechanism, and limitations for the free radical substitution of alkanes, and complete a reaction flowchart for haloalkane conversions involving amines, alcohols, nitriles, and carboxylic acids.
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Question text
18 This question is about haloalkanes.
(a) Haloalkanes can be synthesised by reacting alkanes with halogens in the presence of ultraviolet
radiation.
An alkane reacts with bromine to form 2-bromo-2-methylpropane.
(i) Write the equation for this reaction, showing the structures of the organic compounds.
Name the reaction mechanism and the type of bond fission that occurs.
Equation
Name of reaction mechanism …
Type of bond fission …
[3]
(ii) Describe two limitations of the synthesis of 2-bromo-2-methylpropane from an alkane and
bromine.
1 …
2 …
[2]
(b) Complete the flowchart by filling in each box.
amine
reagent(s)
reagent(s)
H
H3C C Br
H
bromoethane alcohol
reagent(s)
H
H3C C C N
H
nitrile
reagent(s) reagent(s)
carboxylic acid amine
[9]
Mark scheme
Show the mark scheme
Question Answer Marks Guidance
18 (a) (i) Equation 3 ALLOW any combination of skeletal OR structural OR
displayed formula as long as unambiguous
H H H H Br H
H C C C H + Br2 H C C C H + HBr IGNORE mechanism, need overall equation
H CH3 H H CH3 H
Name
Radical substitution
Bond fission
homolytic (fission)
18 (a) (ii) Further substitution/s 2 ALLOW dibromo/multibromo compounds formed
OR OR example of further substitution product e.g
Different termination products CH2BrCBr(CH3)2 / C4H8Br2 / 1,2-dibromo-2-methylpropane
OR OR example of different organic termination product
More than one termination step e.g.C8H18
ALLOW more than one H (atom) can be replaced
ALLOW radicals react with each other to form other
Substitution at different positions along (carbon) chain ✓ products
ALLOW a hydrogen (atom) on a different carbon (atom) can
be replaced
ALLOW Substitutions can occur at other carbons (along the
chain)
ALLOW example of substitution at different position on
chain e.g. CH2BrCH(CH3)2 / 1-bromo-2-methylpropane
IGNORE references to separation of products
IGNORE references to atom economy or yield
18 (b) 9 ALLOW any combination of skeletal OR structural OR
displayed formula as long as unambiguous
H
H3C C NH2 DO NOT ALLOW structure if H(s) are missing from ONE
structural/displayed formula…
H
amine BUT ALLOW any further omissions as ECF
Reagent(s) ALLOW any vertical bond to the OH OR NH2
NH3 AND ethanol Reagent(s)
OR excess NH3 –
OH (aq)
OR NaOH H
H
OR KOH
H C C OH DO NOT ALLOW OH–, OR NH2– but ALLOW ECF for
H C C Br 3
3 subsequent use in this part
H H
bromoethane alcohol ALLOW names of reagents e.g. ethanolic ammonia, if no
formulae given
Reagent(s) DO NOT ALLOW other additional reagents
CN– (/ethanol)
ORKCN (/ethanol) IGNORE Conditions
OR NaCN (/ethanol)
H For bromoethane to amine:
H3C C C N IF a secondary / tertiary amine is given ALLOW one mark for a
correct structure AND one mark for an appropriate reagent to
H produce the amine shown.
nitrile
Reagent(s)
Aqueous acid For bromoethane to alcohol:
+ Reagent(s) ALLOW H O
OR H /H2O 2
OR H+(aq) H AND Ni
2 IGNORE ethanol (as a solvent)
For bromoethane to nitrile:
DO NOT ALLOW HCN OR CN- / H+
H H H
H C C COOH DO NOT ALLOW H2O / (aq)
3 H C C C NH
H For nitrile to carboxylic acid:
H H ALLOW any mineral acid
carboxylic acid amine IGNORE dilute/concentrated
Check has 3C not 2C
For nitrile to amine:
ALLOW suitable non-specification alternative e.g. LiAlH4,
H2 with Pd or Pt
How to answer it
Haloalkanes: Synthesis, Limitations, and Organic Synthesis Pathways
This question assesses your knowledge of radical substitution mechanisms involving alkanes and halogens, the inherent limitations of free radical halogenation, and nucleophilic substitution/reduction pathways for converting haloalkanes into alcohols, amines, nitriles, and carboxylic acids.
Free Radical Halogenation Equation & Mechanism
Writing equations, naming mechanisms, and bond fission types
✅ Correct Answer
- Equation: CH₃CH(CH₃)CH₃ + Br₂ → CH₃C(Br)(CH₃)CH₃ + HBr (or structural/displayed equivalent showing 2-methylpropane reacting to form 2-bromo-2-methylpropane).
- Name of mechanism: Radical substitution (or free radical substitution).
- Type of bond fission: Homolytic (fission).
💡 Key Knowledge
- Homolytic fission: Each bonding atom receives one electron from the shared pair, forming free radicals.
- Alkanes require UV light to provide energy to break the halogen bond homolytically.
🧠 Exam Technique
- Make sure you draw out unambiguous structural or displayed formulas when requested.
- Do not confuse homolytic fission with heterolytic fission (which occurs in polar nucleophilic substitutions).
❌ Common Errors
- Writing "homolytic substitution" instead of "radical substitution".
- Writing "heterolytic" due to mixing up free radical mechanisms with nucleophilic substitution.
Limitations of Alkane Halogenation
Explaining why free radical substitution is poor for specific synthesis
✅ Correct Answers (Any two)
- Further substitution (formation of dibromo- or multibromo-compounds).
- Substitution occurring at different positions along the carbon chain (yielding structural isomers like 1-bromo-2-methylpropane).
- Different termination products / side products formed when radicals combine (e.g., C₈H₁₈).
💡 Key Knowledge
- Free radical substitution is notoriously unselective because propagation steps can happen repeatedly on the same molecule or at different carbon environments.
- This leads to low atom economy and difficult separation processes.
🧠 Exam Technique
- Keep your bullet points concise and chemically precise. Use terms like "further substitution" or "isomers".
- Examiners ignore vague mentions of "poor yield" unless backed up by a chemical reason like side-products or isomer formation.
❌ Common Errors
- Stating "low atom economy" — halogenation involves substitution, but the key limitation tested here is the lack of control over position and extent of substitution.
Organic Synthesis Flowchart: Haloalkane Reactions
Reagents and structural formulas for functional group interconversions
✅ Correct Pathway Answers
- Bromoethane to Amine: Reagents: NH₃ and ethanol (or excess NH₃). Structure: CH₃CH₂NH₂ (ethylamine).
- Bromoethane to Alcohol: Reagents: OH⁻(aq) or NaOH(aq) / KOH(aq) . Structure: CH₃CH₂OH (ethanol).
- Bromoethane to Nitrile: Reagents: CN⁻ / ethanol or KCN / ethanol .
- Nitrile to Carboxylic Acid: Reagents: Aqueous acid or H⁺/H₂O . Structure: CH₃CH₂COOH (propanoic acid - note the 3-carbon chain!).
- Nitrile to Amine (Reduction): Reagents: H₂ and Ni (or LiAlH₄). Structure: CH₃CH₂CH₂NH₂ (propylamine - 3 carbons).
💡 Key Knowledge & Traps
- Chain lengthening: Converting bromoethane (2 carbons) to a nitrile introduces an extra carbon, yielding a 3-carbon chain (propanoic acid and propylamine downstream).
- Amine synthesis conditions: Requires ethanolic ammonia under pressure to prevent further substitution into secondary/tertiary amines, though the primary amine structure is expected here.
🧠 Exam Technique
- Always double-check carbon chain lengths when nitriles are involved! Examiners specifically penalise students who accidentally drop or add carbons during hydrolysis or reduction steps.
- Check if specific state symbols or solvent conditions are requested (e.g., aqueous vs. ethanolic).
❌ Common Errors
- Using aqueous ammonia instead of ethanolic ammonia for making amines from haloalkanes.
- Using HCN instead of KCN/ethanol for nitrile formation.
- Forgetting that nitrile reduction or hydrolysis products retain the extra carbon from the nitrile group ( -C≡N ).
Topics
Module 4: Core organic chemistry · Module 6: Organic chemistry and analysis · 6.2 Nitrogen compounds, polymers and synthesis · 4.1 Basic concepts and hydrocarbons · 4.2 Alcohols, haloalkanes and analysis
Question and mark scheme from the OCR A-Level Chemistry examination, Synthesis and analytical techniques (02), June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.