OCR A-Level Chemistry AS Breadth in chemistry (01), June 2025: Question 20
1 mark · Easy difficulty · Multiple Choice
Identify which compound corresponds to the given infrared spectrum showing a strong absorption around 1720–1740 cm⁻¹ and no broad O–H peak.
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Question text
20 The IR spectrum of a compound is shown below.
transmittance
(%)
4000 3000 2000 1500 1000 400
wavenumber / cm–1
Which compound could have produced the IR spectrum?
A CH3CH=CH2
B CH3CH2CHO
C CH3CH2CH2OH
D CH3CH2COOH
Your answer [1]
SECTION B
Mark scheme
Show the mark scheme
20 B 1
How to answer it
Identifying Carbonyl Compounds Using Infrared Spectroscopy
This question assesses your ability to deduce the functional group of an organic molecule from an infrared (IR) spectrum using characteristic absorption bands:
- Recognising the sharp, prominent carbonyl ( C=O ) absorption stretch at ~1630–1820 cm⁻¹.
- Distinguishing carbonyl compounds (aldehydes/ketones) from alcohols and carboxylic acids by noting the complete absence of broad O-H absorption bands.
- Eliminating alkenes based on peak intensity, shape, and characteristic wavenumber values.
IR Spectrum Analysis & Identification
Deducing the unknown organic structure from characteristic wavenumber peaks
✅ Correct Answer
B — CH₃CH₂CHO (Propanal)
• 1 mark for letter B in the answer box.
📐 Spectral Analysis (Step-by-Step)
- Strong, sharp peak at ~1730 cm⁻¹: Unambiguously indicates a carbonyl group, C=O (aldehyde or ketone). This immediately rules out A ( CH₃CH=CH₂ ) and C ( CH₃CH₂CH₂OH ).
- No broad peak between 2500–3300 cm⁻¹: Carboxylic acid O-H stretches form a distinctive, very broad "trough" that overlaps the C-H region. Its complete absence rules out D ( CH₃CH₂COOH ).
- Peaks around 2700–2900 cm⁻¹: Characteristic C-H stretching vibrations, including the aldehyde C-H doublet around 2720 cm⁻¹ and 2820 cm⁻¹.
💡 Key Knowledge: Data Sheet Values
Always reference standard OCR Data Sheet values when solving IR questions:
- C=O (aldehydes, ketones, acids): 1630–1820 cm⁻¹ (very strong, sharp)
- O-H (alcohols): 3200–3600 cm⁻¹ (broad, rounded)
- O-H (carboxylic acids): 2500–3300 cm⁻¹ (very broad, jagged baseline)
- C=C (alkenes): 1620–1680 cm⁻¹ (often weak or medium intensity)
- C-H (alkyl): 2850–3100 cm⁻¹
🧠 Exam Technique: Elimination Strategy
In Section A multiple-choice IR questions, negative evidence is just as powerful as positive evidence:
- Look for the presence of C=O: The deep "spike" at ~1730 cm⁻¹ dropping down to ~20% transmittance instantly confirms a carbonyl group is present.
- Look for the absence of O-H: The baseline above 3100 cm⁻¹ is virtually flat (~95–100% transmittance). If an -OH group were present, transmittance would drop drastically in this region.
❌ Common Errors & Pitfalls
- Confusing Propanal (B) with Propanoic Acid (D): Both contain a C=O peak at ~1700 cm⁻¹, but students often forget that propanoic acid must also feature a massive, broad carboxylic O-H absorption spanning 2500–3300 cm⁻¹.
- Mistaking C-H peaks for O-H peaks: The sharp spikes just under 3000 cm⁻¹ are standard aliphatic C-H bonds, not an alcohol O-H (which is broad and located further left between 3200–3600 cm⁻¹).
- Confusing C=C with C=O: Alkene C=C stretches appear at a slightly lower wavenumber (1620–1680 cm⁻¹) and are substantially weaker in transmittance than a C=O stretch.
Topics
Module 4: Core organic chemistry · 4.2 Alcohols, haloalkanes and analysis
Question and mark scheme from the OCR A-Level Chemistry examination, AS Breadth in chemistry (01), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.