OCR A-Level Chemistry AS Depth in chemistry (02), June 2025: Question 2

12 marks · Medium difficulty · Structured Questions

Explain the trends and reactions of Group 2 elements, and calculate and evaluate the volume of carbon dioxide produced from barium carbonate and nitric acid.

Practise this question

Question

Question 2 begins with a table of first and second ionisation energies of Mg and Ca. Part (a)(i) asks for an equation with state symbols representing the second ionisation energy of calcium. Part (a)(ii) is a 6-mark extended-response question asking for a balanced equation, observations, and redox explanation for calcium reacting with water, as well as an explanation for the difference in reactivity between magnesium and calcium. Part (b) provides an equation for the reaction of 1.51 g of barium carbonate with excess dilute nitric acid and shows a diagram of a conical flask with a stopper and delivery tube collecting gas over water in an inverted 250 cm³ measuring cylinder. Sub-questions ask to calculate the expected gas volume at RTP to 3 significant figures, suggest two reasons why the collected volume is less than calculated, and suggest one modification to the apparatus.
Question text

2 This question is about reactions of some Group 2 elements and their compounds.

(a) The table below shows the first and second ionisation energies of magnesium and calcium.

1st Ionisation energy 2nd Ionisation energy

Group 2 element –1 –1

/ kJ mol / kJ mol

Mg 738 1451

Ca 590 1145

(i) Write an equation to represent the second ionisation energy of calcium.

Include state symbols.

… [1]

(ii)* Magnesium and calcium differ in their reactivity.

Give a balanced equation for the reaction of calcium with water and describe what would be

observed. Explain why this is a redox reaction.

Explain the difference in reactivity of magnesium and calcium.

… [6]

Extra answer space if required.

(b) A student adds 1.51 g of barium carbonate, BaCO (molar mass 197.3 g mol–1), to an excess of

dilute nitric acid. The equation is shown below.

BaCO3(s) + 2HNO3(aq) Ba(NO3)2(aq) + H2O(l) + CO2(g)

The student uses the following apparatus.

250 cm3 measuring cylinder

Stopper

Barium carbonate

and dilute nitric acid Water

(i) Calculate the volume, in cm3, of gas the student expects to be produced at room temperature

and pressure (RTP).

Give your answer to 3 significant figures.

Volume of gas … cm3 [2]

(ii) The volume of gas collected is less than the calculated volume.

Suggest two reasons for this difference.

1 …

2 …

[2]

(iii) Suggest one way in which the student could modify the apparatus to produce a volume closer to

the calculated volume.

… [1]

Mark scheme

Show the mark scheme Mark scheme for Question 2 provides: (a)(i) Ca+(g) -> Ca2+(g) + e- (1 mark); (a)(ii) Level-of-response grid up to 6 marks covering reactivity/explanation (atomic radius, shielding, nuclear attraction), observations and equation (effervescence, Ca dissolving, Ca + 2H2O -> Ca(OH)2 + H2), and redox explanation (changes in oxidation states); (b)(i) n(BaCO3) = 1.51/197.3 = 7.65 x 10^-3 mol, Volume = 7.65 x 10^-3 x 24000 = 184 cm³ (2 marks); (b)(ii) Gas lost when bung replaced, CO2 dissolves in water, or non-RTP conditions (any two, 2 marks); (b)(iii) Use a gas syringe or release barium carbonate from a small tube inside without removing the stopper (1 mark).

Question Answer Mark Guidance

2 (a) (i) Ca+(g) → Ca2+(g) + e– 1 ALLOW Ca+(g) – e– →Ca2+(g)

ALLOW e for electron (i.e. charge omitted)

IGNORE states on the electron

2 (a) (ii) Please refer to the marking instructions on page 5 of the mark 6 Mark additional answer space P5 as SEEN

scheme for guidance on how to mark this question. Indicative scientific points may include:

Level 3 (5-6 marks) A Difference in Reactivity and Explanation

Covers all 3 areas A, B and C in detail with very few omissions ORA is allowed for the following:

or errors • Ca more reactive than Mg.

• Atomic radius of Ca is greater or more shells/shielding.

There is a well-developed line of reasoning which is clear and • Attraction of outer electrons to the nucleus is less.

logically structured. The information presented is relevant and • Ionisation energies of Ca are less.

substantiated. OR Easier to remove Ca outer electrons.

Level 2 (3–4 marks) B Observations and equation

Covers at least 2 areas in detail with very few omissions or • Effervescence/fizzing/bubbles

errors • Ca/solid disappears/dissolves

OR OR

Covers all 3 areas in some detail Forms a white ppt/solid

• Ca + 2H2O → Ca(OH)2 + H2 (IGNORE state symbols)

There is a line of reasoning presented with some structure.

The information presented is relevant and supported by some C Redox

evidence. • Both oxidation and reduction take place.

• Ca is oxidised

Level 1 (1–2 marks) • Oxidation number of Ca increases from 0 to +2

Covers 1 area in detail with very few omissions or errors OR

OR Ca loses 2 electrons (to form Ca2+ ions)

Covers 2 areas in some detail • H is reduced

• Oxidation number of H decreases from +1 to 0

There is an attempt at a logical structure with a line of

OR

reasoning. The information is in the most part relevant.

H gains 1 electron (per H atom)

Aspects of the communication statement might typically have

0 marks No response or no response worthy of credit

been met for all levels when:

Question Answer 11 Mark Guidance

• All information given is correct using appropriate

scientific language, for example (in A) comparison of

Mg and Ca not just trend down group and (in C) directly

links redox to oxidation and reduction.

• There are no errors, for example incorrect balancing,

using +2 as initial oxidation state for H.

2 (b) (i) FIRST CHECK THE ANSWER ON ANSWER LINE 2

IF vol = 184 cm3 award 2 marks

How to answer it

Group 2 Elements, Trends & Gas Collection Techniques

📋 What this question tests

This question assesses fundamental Periodic Table principles and practical analytical skills from Module 2 & Module 3:

  • Ionisation energy definitions: Constructing accurate equations representing successive ionisation energies with correct state symbols.
  • Group 2 reactivity trends (Extended Response): Explaining reactivity down Group 2 using shielding, atomic radius, and nuclear attraction alongside balanced equations, redox terms, and observational details.
  • Stoichiometry & gas volumes: Calculating theoretical gaseous products using molar mass and molar gas volume at room temperature and pressure (RTP).
  • Practical experimental evaluation: Identifying procedural and physical errors in collecting gases over water and suggesting targeted apparatus modifications.
Part (a)(i) · 1 Mark

Second Ionisation Energy of Calcium

Writing correct state symbols and ionisation equations

✅ Correct Answer

Ca⁺(g) → Ca²⁺(g) + e⁻

Also allowed: Ca⁺(g) - e⁻ → Ca²⁺(g) . State symbols on the electron are not required.

❌ Common Errors

  • Writing the first ionisation energy: Ca(g) → Ca⁺(g) + e⁻
  • Writing the two-electron ionisation: Ca(g) → Ca²⁺(g) + 2e⁻
  • Omitting state symbols or writing solid (s) instead of gaseous state (g) .
Mark Breakdown: 1 mark for correct species, charges, and gaseous state symbols (g) on both calcium ions.
Part (a)(ii)* · 6 Marks (Level of Response)

Reactivity Trend, Observations & Redox Explanation

Comparing Calcium and Magnesium with Water

💡 3 Core Themes Needed for Level 3 (5–6 Marks)

A. Trend & Explanation:

  • Calcium is more reactive than magnesium.
  • Ca has a larger atomic radius / more electron shells / more shielding than Mg.
  • Nuclear attraction to the outer electrons is weaker in Ca.
  • Outer electrons are lost more easily (first & second ionisation energies of Ca are lower).

B. Equation & Observations:

  • Ca + 2H₂O → Ca(OH)₂ + H₂
  • Effervescence / fizzing / bubbles of gas.
  • Calcium metal dissolves / disappears, or a white precipitate / cloudy suspension forms.

C. Redox Explanation:

  • Both oxidation and reduction occur simultaneously.
  • Ca is oxidised: oxidation number increases from 0 in Ca to +2 in Ca(OH)₂ (loss of 2 electrons).
  • H is reduced: oxidation number decreases from +1 in H₂O to 0 in H₂ (gain of 1 electron per H atom).

🧠 Exam Technique & Structure

To secure a Level 3 (6 marks), structure your answer clearly under three distinct headings:

  1. Equation & Observations: Give the balanced symbol equation first, followed by at least two distinct sensory observations.
  2. Redox: Define oxidation and reduction specifically using oxidation numbers for both Ca and H. Avoid vague statements like "water is reduced".
  3. Reactivity comparison: Directly compare Ca with Mg. Do not just quote a general group trend; state specifically why calcium's outer electrons feel less pull to the nucleus despite higher nuclear charge.

❌ Common Pitfalls

  • Incorrect formula for calcium hydroxide: Writing CaOH instead of Ca(OH)₂ .
  • Confusing water with steam: Magnesium reacts vigorously with steam to form MgO, but this question specifies calcium with water, which yields the metal hydroxide.
  • Incomplete redox reasoning: Stating that "calcium is oxidised" without explaining what happens to hydrogen, or quoting hydrogen's initial oxidation state incorrectly as +2.
Level Boundaries:
• Level 3 (5–6 marks): Covers all 3 areas (A, B, C) in detail with a clear, logical structure and accurate chemical terminology.
• Level 2 (3–4 marks): Covers at least 2 areas in detail, or all 3 in some detail.
• Level 1 (1–2 marks): Covers 1 area in detail or 2 in outline.
Part (b)(i) · 2 Marks

Calculation of Theoretical Gas Volume

Molar gas volume at Room Temperature and Pressure (RTP)

📐 Step-by-Step Calculation

Step 1: Calculate amount in moles of BaCO₃

n(BaCO₃) = mass / M = 1.51 / 197.3 = 0.0076533... mol (7.6533 × 10⁻³ mol)

Step 2: Use stoichiometry to find moles of CO₂

From the balanced equation, ratio is 1:1, so:

n(CO₂) = 7.6533 × 10⁻³ mol

Step 3: Calculate volume of gas in cm³

At RTP, 1 mol of gas = 24 000 cm³ (or 24.0 dm³):

Volume = 7.6533 × 10⁻³ × 24 000 = 183.68 cm³

Step 4: Round to 3 significant figures

Volume = 184 cm³

🧠 Calculation Tips & Guidance

  • Full Marks Shortcut: If the final answer on the line is 184 cm³, both marks are awarded automatically.
  • Unit Consistency: The question specifies cm³. If you use 24 dm³, you get 0.184 dm³ — remember to multiply by 1000!
  • Error-Carried-Forward (ECF): If you miscalculate the moles of BaCO₃, you can still gain the second mark by multiplying your value by 24 000 and rounding to 3 SF.
  • Ideal Gas Equation: Alternatively, using pV = nRT at 293 K and 100 kPa gives 186 cm³, which is also fully credited.
Mark Breakdown:
• Mark 1: Moles of BaCO₃ = 7.65 × 10⁻³ mol.
• Mark 2: Volume of CO₂ = 184 cm³ (must be to 3 significant figures).
Part (b)(ii) · 2 Marks

Reasons for Lower Measured Volume

Evaluating practical gas collection over water

✅ Any Two Valid Reasons (1 Mark Each)

  • Gas escape: Gas escapes before the stopper / bung can be inserted into the conical flask after adding the carbonate.
  • Gas solubility: Carbon dioxide dissolves in the water inside the trough/measuring cylinder.
  • Non-standard conditions: Laboratory temperature was lower than 20 °C (293 K) OR pressure was higher than 101 kPa (conditions not at RTP).

❌ Ignored & Rejected Answers

  • "Incomplete reaction" — rejected because nitric acid was specified as being in excess.
  • "Human errors" (e.g. faulty apparatus, misreading the scale, gas leaking around the delivery tube).
  • "Impurities in the solid" without experimental justification.
Mark Breakdown: 1 mark for each valid point up to a maximum of 2 marks.
Part (b)(iii) · 1 Mark

Apparatus Modifications

Improving accuracy in reaction stoichiometry practicals

✅ Acceptable Modifications (Choose One)

  • Use a gas syringe instead of collecting the gas over water (directly solves the issue of CO₂ dissolving in water).
  • Place the barium carbonate in a small ignition tube / suspended container inside the conical flask and tip it into the acid after sealing with the stopper (prevents gas escape when replacing the bung).
  • Use a water bath set to room temperature (20 °C / 293 K) to control temperature conditions.

🧠 Examiner Trap

Writing simply "use a gas syringe" without specifying replacing the water collection is sometimes penalised if not distinct. Clearly state: "Collect the gas in a gas syringe instead of an upturned measuring cylinder over water".

Mark Breakdown: 1 mark for any single viable modification targeted at solving a reason identified in part (b)(ii).

Topics

Module 1: Development of practical skills in chemistry · Module 2: Foundations in chemistry · Module 3: Periodic table and energy · Practical Activity Groups · 1.1 Practical skills assessed in a written examination · PAG 1: Moles determination · 2.1 Atoms and reactions · 2.2 Electrons, bonding and structure · 3.1 The periodic table

Question and mark scheme from the OCR A-Level Chemistry examination, AS Depth in chemistry (02), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.