WJEC A-Level Chemistry Unit 4, June 2025: Question 4

2 marks · Medium difficulty · Structured Questions

Explain why 4-bromophenol reacts with sodium hydroxide and why the bromine atom is not replaced by a hydroxyl group.

Practise this question

Question

Question 4 displays an organic equation: 4-bromophenol reacts with sodium hydroxide to form sodium 4-bromophenolate and water. Part (a) asks to explain why 4-bromophenol reacts with alkalis like sodium hydroxide, for 1 mark. Part (b) shows the structure of a disubstituted phenolate ion (4-hydroxyphenolate sodium salt) where the bromine is replaced by an OH group, and asks to explain why this is not the product of the reaction, for 1 mark.
Question text

4. 4-Bromophenol reacts with aqueous sodium hydroxide to give the products shown in the

equation.

O– +

Br OH + NaOH Br Na + H2O

(a) Explain why 4-bromophenol reacts with alkalis like sodium hydroxide. [1]

(b) Explain why the organic product from this reaction is not the compound shown below.

[1]

HO O– Na+

Mark scheme

Show the mark scheme Mark scheme for Question 4: (a) 4-bromophenol is reacting as an acid or proton donor (1 mark, AO1). (b) Award 1 mark (AO1) for any of: aromatic compounds are not susceptible to attack by nucleophiles; aromatic compounds do not undergo nucleophilic substitution; or the aromatic C–Br bond is too strong.

Marks available

Question Marking details

AO1 AO2 AO3 Total Maths Prac

4 (a) 4-bromophenol is reacting as an acid / proton donor

(b) award (1) for any of following

• aromatic compounds are not susceptible to attack by

nucleophiles 1 1

• aromatic compounds do not undergo nucleophilic substitution

• the aromatic C—Br bond is too strong

Section A total 7 2 1 10 1 3

How to answer it

Reactions of Phenols & Inertness of Halogenoarenes

📋 What this question tests

This question assesses your understanding of aromatic functional group reactivity:

  • Acidic behaviour of phenols: Why phenols react with strong bases like aqueous NaOH, unlike aliphatic alcohols.
  • Inertness of halogenoarenes: Why halogen atoms directly bonded to a benzene ring do not undergo nucleophilic substitution (hydrolysis) under standard conditions.

Question 4 (a)

Explain why 4-bromophenol reacts with alkalis like sodium hydroxide. [1 Mark]

✅ Mark Scheme Answer

Any one of the following statements:

  • 4-Bromophenol acts/reacts as an acid.
  • It acts as a proton donor (donates H⁺ to OH⁻).
Mark allocation: 1 mark (AO1) for stating acidic nature or proton donation.

💡 Key Knowledge

  • Phenols are weak acids (pKa ~ 10). They are acidic enough to react with strong bases like aqueous NaOH to form water-soluble phenoxide salts and H₂O .
  • In contrast, standard aliphatic alcohols (e.g. ethanol, pKa ~ 16) are not acidic enough to react with aqueous NaOH .
  • Phenol's acidity arises because the lone pair of electrons on oxygen delocalises into the benzene π-ring, stabilising the phenoxide anion ( C₆H₅O⁻ ).

🧠 Exam Technique

The question asks why it reacts with an alkali. Alkalis are bases/proton acceptors, so the most direct chemical reasoning is to identify the complementary role of the organic reactant: it is an acid or a proton donor.

❌ Common Errors

  • Writing simply that "it has an —OH group" (aliphatic alcohols also have —OH groups, but they do not react with aqueous NaOH).
  • Calling the reaction "electrophilic substitution" instead of an acid-base neutralization.

Question 4 (b)

Explain why the organic product from this reaction is not the compound shown below: HO—C₆H₄—O⁻Na⁺. [1 Mark]

✅ Mark Scheme Answer

Award 1 mark for any one of the following points:

  • Aromatic compounds / benzene rings are not susceptible to attack by nucleophiles (or repel nucleophiles due to high π-electron density).
  • Aromatic compounds / halogenoarenes do not undergo nucleophilic substitution.
  • The aromatic C—Br bond is too strong (stronger than in a haloalkane).
Mark allocation: 1 mark (AO1) for identifying nucleophilic resistance or bond strength.

💡 Key Knowledge

In haloalkanes (aliphatic), OH⁻ easily displaces Br⁻ via nucleophilic substitution (hydrolysis). However, in bromobenzene derivatives:

  • Partial double bond character: One of the p-orbital lone pairs on the bromine atom delocalises into the aromatic π-system, shortening and strengthening the C—Br bond.
  • Electron repulsion: The electron-rich π-cloud of the benzene ring repels approaching nucleophiles (such as OH⁻ ).

🧠 Exam Technique

Notice what changed in the incorrect molecule: the —Br group was substituted by an —OH group. Immediately recognise this as attempted nucleophilic substitution of a halogen on an aromatic ring, which is generally not feasible under room conditions.

❌ Common Errors

  • Saying "bromine is not reactive" (too vague; bromine in 1-bromobutane is readily substituted). Specify the aromatic C—Br bond.
  • Stating that "NaOH is an electrophile" (hydroxide ion, OH⁻, is negatively charged and therefore a nucleophile).
  • Failing to mention the word nucleophile or substitution when discussing the mechanism.

Topics

Organic Chemistry · 4.3 Alcohols and phenols · 4.2 Aromaticity · 2.6 Halogenoalkanes

Question and mark scheme from the WJEC A-Level Chemistry examination, Unit 4, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.