WJEC A-Level Chemistry AS Unit 1, June 2025: Question 1
1 mark · Easy difficulty · Short Answer
Draw a dot and cross diagram using outer electrons only to show the bonding in a diatomic molecule of oxygen.
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How to answer it
Dot and Cross Diagram: Diatomic Oxygen (O₂)
What this question tests
This question assesses your fundamental understanding of covalent bonding in simple diatomic molecules, the application of the octet rule, and your ability to accurately construct dot-and-cross diagrams showing only outer-shell electrons.
Drawing the Covalent Bonding in O₂
Outer-shell representation of a diatomic molecule
✅ Correct Representation
The diagram must clearly show a double covalent bond (4 shared electrons) and two lone pairs (4 unshared electrons) on each oxygen atom:
Overlap Region: 2 dots and 2 crosses ( •• ×× )
Right O Atom: 4 non-bonding crosses (×× ××)
- Total outer electrons: 12 valence electrons in total (6 dots + 6 crosses).
- Bonding region: Exactly 4 electrons shared between the two nuclei (2 shared pairs = double bond).
- Octet verification: Each atom has access to 8 electrons (4 shared + 4 non-bonding).
• 4 shared electrons in the overlap (2 from each atom).
• 4 non-bonding electrons on each oxygen atom.
• Outer electrons only (no inner 1s² electrons shown).
💡 Key Chemical Knowledge
- Electronic Configuration: Oxygen has an atomic number of 8: 1s² 2s² 2p⁴ . It has 6 valence electrons (Group 16 / Group 6).
- Covalent Bond Definition: An electrostatic attraction between a shared pair of electrons and the positively charged nuclei of the bonded atoms.
- Octet Requirement: Each oxygen needs 2 more electrons to achieve a stable noble gas configuration (like Neon, 2s² 2p⁶ ).
- Double Bond Formation: To gain 2 electrons, each oxygen atom must contribute 2 electrons to form two shared pairs (an O=O double bond).
🧠 Step-by-Step Drawing Technique
- Count valence electrons: Each O has 6 outer electrons. Total = 6 + 6 = 12 electrons.
- Draw overlapping circles: Sketch two intersecting circles and label the centres with an "O" or place an "O" in each circle.
- Insert the shared pairs: Place 2 dots and 2 crosses in the intersection region (representing the double bond).
- Distribute the remaining electrons: Each oxygen atom has 4 remaining outer electrons. Place them in pairs around the non-overlapping part of each circle (dots on the left O, crosses on the right O).
- Double-check: Count each circle individually to confirm both contain exactly 8 electrons.
❌ Common Errors & Pitfalls
- Drawing a single bond: Showing only 1 pair (1 dot, 1 cross) in the middle, leaving atoms with incomplete octets (7 electrons each).
- Forgetting lone pairs: Drawing the 4 bonding electrons but forgetting the 4 non-bonding electrons on each atom. In dot-and-cross diagrams, all outer shell electrons must be accounted for.
- Including inner-shell electrons: Drawing the full atom with an inner circle of 2 electrons. The question explicitly stated: "Using outer electrons only".
- Unequal electron contribution: Putting 3 dots and 1 cross in the overlap. A standard double bond requires 2 electrons from each identical atom.
Topics
Physical Chemistry · 1.4 Bonding
Question and mark scheme from the WJEC A-Level Chemistry examination, AS Unit 1, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.