AQA A-Level Chemistry Paper 3, June 2018: Question 3

13 marks · Medium difficulty · Practical Techniques & Data Analysis

Calculate the percentage yield of cyclohexene from the dehydration of cyclohexanol, and explain the purification, chromatography, and spectroscopy techniques used in the preparation.

Practise this question

Question

Question 03 details the preparation of cyclohexene by dehydration of cyclohexanol using concentrated phosphoric acid. It provides chemical equations, reaction conditions, and a diagram of distillation apparatus (Figure 3). Eight sub-questions follow: 03.1 calculates percentage yield from 10 cm³ cyclohexanol to 5.97 g cyclohexene; 03.2 describes a test for the alkene product; 03.3 to 03.6 ask about purification steps including sodium carbonate washing, separating funnel pressure release, drying agents, and reduced pressure filtration apparatus; 03.7 explains retention time differences in silica gel/hexane column chromatography; and 03.8 asks how infrared spectroscopy confirms absence of cyclohexanol.
Question text

03 Cyclohexene (boiling point = 83°C) can be prepared by the dehydration of

cyclohexanol (boiling point = 161°C) using concentrated phosphoric acid.

A student prepared cyclohexene by placing 10 cm3 of cyclohexanol

(density = 0.96 g cm–3) into a round-bottomed flask.

3 cm3 of concentrated phosphoric acid were then carefully added to the flask.

The student added a few anti-bumping granules and set up the apparatus shown in

Figure 3.

Figure 3

• The student heated the mixture and collected the liquid that distilled at

temperatures below 100°C

• The distillate was poured into a separating funnel and washed by shaking with

sodium carbonate solution.

• Periodically, the separating funnel was inverted and the tap opened.

• The aqueous layer was discarded and the final organic product was dried

using anhydrous calcium chloride.

• After the product was dried, the drying agent was removed by filtration under11

reduced pressure.

03.1 The student collected 5.97 g of cyclohexene in the experiment.

Calculate the percentage yield of cyclohexene.

[3 marks]

Percentage yield %

03.2 Describe a test-tube reaction, on the product, to show that the cyclohexanol had been

dehydrated.

State what you would observe.

[2 marks]

03.3 Suggest why sodium carbonate solution was used to wash the distillate.

[1 mark]

03.4 Explain why it is important to open the tap of the separating funnel periodically.

[1 mark]

03.5 Give a property of anhydrous calcium chloride, other than its ability to absorb water,

that makes it suitable as a drying agent in this preparation.

[1 mark]

*0113.*6 Describe the apparatus used to remove the drying agent by filtration under reduced

pressure. Your description of the apparatus can be either a labelled diagram or a

description in words. 13

[2 marks]

03.7 A sample of cyclohexene has been contaminated with cyclohexanol. The

cyclohexene can be separated from the cyclohexanol by column chromatography.

Silica gel is used as the stationary phase and hexane as the mobile phase.

Explain why cyclohexene has a shorter retention time than cyclohexanol.

[2 marks]

03.8 Explain how an infrared spectrum would confirm that the cyclohexene obtained from

the chromatography column did not contain any cyclohexanol.

[1 mark]

Mark scheme

Show the mark scheme Mark scheme for Question 03 showing marking points for 03.1 to 03.8. 03.1 awards 3 marks for calculating percentage yield (76%, accepted 75.8-76%). 03.2 awards 2 marks for bromine water decolourising. 03.3 awards 1 mark for neutralising phosphoric acid. 03.4 awards 1 mark for releasing pressure from gas build-up. 03.5 awards 1 mark for not reacting with or dissolving in cyclohexene. 03.6 awards 2 marks for a diagram or description of Buchner filtration. 03.7 awards 2 marks for cyclohexene being less polar and having greater affinity for the mobile phase. 03.8 awards 1 mark for absence of an alcohol O-H absorption at 3230-3550 cm⁻¹ or matching fingerprint region. Total 13 marks.

Question Answers Additional Comments/Guidelines Mark

M1: Moles of cyclohexanol = (10 x 0.96)/100.0 = 0.096 Correct answer scores all 3 marks

M2: Max mass of cyclohexene = 0.096 x 82.0 = 7.87(2) = M1 x 82.0 (process mark)

M3: % yield = (5.97 / 7.87) x 100 = 76% (Allow range 75.8 – 76) = (5.97 / M2) x 100 (process mark)

Alternative method

03.1 M1: Moles of cyclohexanol = (10 x 0.96)/100.0 = 0.096 1

M2: Moles of cyclohexene = 5.97/82.0 = 0.0728 1

M3: % yield = 0.0728 / 0.096 x 100 = 76% (allow range 75.8 – 76) = (M2 / M1) x 100

Allow 1/3 for 62(.2)%

Add bromine (water) If M1 not correct then only allow M2 if reagent

involves bromine (water)

03.2 Would turn (from orange to) colourless / decolourise Do not allow incorrect starting colour, but allow

brown/red/yellow 1

Not discolour.

Ignore clear

03.3 Na CO would neutralise/react with/remove (phosphoric) acid/H PO /H+ 1

23 3 4

avoid pressure build-up / release pressure / release CO2/air/gas / Ignore explosion

prevent stopper blowing out Do not allow an incorrect named gas

03.4 1

Allow idea that build-up of gas/CO2 would lead to

increased pressure/stated effect of increased

pressure – – –

18 Does not dissolve in/react with the cyclohexene Allow remains a solid/is inert in cyclohexene

Allow organic product/organic compound formed/

organic layer/distillate instead of cyclohexene

Do not allow if answer implies cyclohexanol

03.5 Do not allow if answer says does not react with 1

products

Ignore references to filtration

Do not allow insoluble/unreactive unless qualified

by implied reference to cyclohexene

If diagram drawn: Do not allow “standard” Y-shaped funnel

M1: diagram of basic set up to include flask or tube with side-

arm/Buchner flask, flat-bottomed funnel/Buchner funnel, filter paper

M2: apparatus should work, flow through, air-tight connection between 1

03.6 flask and funnel, arrow/label/description (to vacuum pump)

If description given: Do not allow just “funnel”

M1: Buchner funnel/flat-bottomed funnel containing filter paper

Penalise M2 if described apparatus would not

M2: Buchner flask/side-arm flask connected to vacuum pump actually work.

Cyclohexene is less polar than cyclohexanol / cyclohexanol is more It = cylcohexene

polar than cyclohexene Allow cyclohexene is non-polar and cyclohexanol

is polar

Cyclohexene has a greater affinity/attraction for the mobile 1

03.7 phase/hexane / cyclohexanol has a greater affinity/attraction for the Allow cyclohexanol held in the stationary phase

stationary phase/silica for longer 1

Allow cyclohexene is more soluble in the mobile

phase/hexane or converse for cyclohexanol

Allow references to hydrogen bonds between–– –

cylcohexanol and silica

Would be no peak at 3230 – 3550 cm–1 due to O—H((alcohol)) Need wavenumber and bond for mark

OR

03.8 1

There would be no additional peaks in the fingerprint region

compared to a pure sample / fingerprint region exactly matches

cylcohexene

Total 13

How to answer it

Preparation, Purification & Analysis of Cyclohexene

📌 What this question tests

This multi-step organic practical question assesses core synoptic lab and analytical skills:

  • Percentage Yield Calculations: Converting liquid reactant volume to mass using density, calculating molar masses, and finding percentage yield.
  • Qualitative Organic Tests: Identifying functional groups using specific test-tube reagents and accurate observations.
  • Practical Purification Techniques: Role of washing reagents, separating funnel operation, selecting suitable drying agents, and vacuum filtration setup.
  • Chromatography & Spectroscopy: Principles of column chromatography based on relative intermolecular forces/polarity and using Infrared (IR) spectra to detect impurities.

Question 03.1: Percentage Yield Calculation

Calculate the percentage yield of cyclohexene from 10 cm³ of cyclohexanol

📐 Step-by-Step Calculation

  1. Mass of cyclohexanol:
    Mass = volume × density = 10 cm³ × 0.96 g cm⁻³ = 9.60 g
  2. Molar masses (Mr):
    Cyclohexanol (C₆H₁₁OH): (6 × 12.0) + (12 × 1.0) + 16.0 = 100.0 g mol⁻¹
    Cyclohexene (C₆H₁₀): (6 × 12.0) + (10 × 1.0) = 82.0 g mol⁻¹
  3. Moles of cyclohexanol (reactant):
    Moles = 9.60 g / 100.0 g mol⁻¹ = 0.0960 mol [Mark 1]
  4. Theoretical mass of cyclohexene (1:1 ratio):
    Theoretical moles = 0.0960 mol
    Theoretical mass = 0.0960 mol × 82.0 g mol⁻¹ = 7.872 g [Mark 2]
  5. Percentage Yield:
    % yield = (actual mass / theoretical mass) × 100
    % yield = (5.97 g / 7.872 g) × 100 = 75.8% to 76% [Mark 3]

❌ Common Errors & Traps

  • Forgetting density: Assuming 10 cm³ = 10 g gives a yield of 62.2%. This is a frequent error and only scores a maximum of 1 mark out of 3.
  • Incorrect Mr: Counting 12 hydrogens for cyclohexanol without the OH gives C₆H₁₂O (correct: C₆H₁₂O, Mr = 100.0). For cyclohexene, remember the double bond removes two hydrogens (C₆H₁₀, Mr = 82.0).
Mark allocation: M1: Moles reactant (0.096 mol) | M2: Theoretical mass (7.87 g) or actual moles (0.0728 mol) | M3: 76% (allow 75.8 – 76%)

Question 03.2: Test for Dehydration (Alkene Test)

Test-tube reaction and observation to confirm an alkene was formed

✅ Correct Answer

  • Reagent: Add bromine water (or bromine). [1 mark]
  • Observation: Turns from orange/brown to colourless OR decolourises. [1 mark]

🧠 Exam Technique

  • Always state both the initial colour and the final colour ("orange to colourless"), or explicitly use the term "decolourises".
  • Do NOT write "turns clear" — "clear" means transparent, not colourless! Orange bromine water is already clear (not cloudy).
  • Do not write "discolours" (spelling and meaning error).

Questions 03.3 & 03.4: Separating Funnel Operations

💡 03.3: Washing with Na₂CO₃ Solution

Answer: To neutralise / react with / remove residual acid (conc. H₃PO₄ / H⁺).

Examiner note: Phosphoric acid has distilled over in trace amounts or carried over mechanically. Na₂CO₃ is a base used to neutralise and wash it out into the aqueous layer.

💡 03.4: Inverting and Opening the Tap

Answer: To release pressure / release built-up CO₂ gas / prevent the stopper blowing out.

Examiner note: The acid-carbonate neutralisation produces CO₂ gas:
2H⁺ + CO₃²⁻ → H₂O + CO₂ . Ignore "prevent explosion" (too dramatic). Mention pressure release or CO₂ gas release.

Question 03.5: Choice of Drying Agent

Property of anhydrous CaCl₂ other than absorbing water

✅ Correct Answer

It does not dissolve in and does not react with cyclohexene (it is inert towards the organic product).

❌ Common Errors

  • Saying simply "it is insoluble" without specifying what it is insoluble in (it must be insoluble in the organic layer / cyclohexene).
  • Stating "it does not react with cyclohexanol" — the primary compound you are drying is the product, cyclohexene.
  • Writing "it can be filtered off easily" — while true, the question asks for a property of the chemical agent in this reaction system.

Question 03.6: Filtration under Reduced Pressure (Vacuum Filtration)

Describe or sketch the apparatus used to remove the drying agent

✅ Required Apparatus Description

  • Funnel: Büchner funnel (or flat-bottomed funnel) containing filter paper. [Mark 1]
  • Flask & Connection: Büchner flask (side-arm flask) sealed with a rubber bung/gasket, connected via tubing to a vacuum pump / water aspirator. [Mark 2]

🧠 Diagram / Description Details

  • If you draw a diagram, ensure the connection between funnel and flask shows an airtight seal (rubber bung).
  • Do not draw a standard conical gravity funnel (Y-shaped filter funnel) — standard funnels fail under vacuum and will lose both marks.
  • Remember to clearly show or label the filter paper lying flat covering the holes in the Büchner plate.

Question 03.7: Column Chromatography Separation

Stationary phase: polar silica gel | Mobile phase: non-polar hexane

💡 Why Cyclohexene Elutes Faster (Shorter Retention Time)

  1. Relative Polarity: Cyclohexene is less polar / non-polar, whereas cyclohexanol is more polar (capable of hydrogen bonding via –OH group). [Mark 1]
  2. Relative Affinities: Cyclohexene has a greater affinity/attraction for the mobile phase (hexane) OR cyclohexanol has a greater affinity for the stationary phase (silica) and is held longer. [Mark 2]

🧠 Linking Polarity to Phases

Always state the "like dissolves like" principle explicitly:

  • Silica = polar stationary phase → holds strongly to polar molecules via dipole-dipole / H-bonds.
  • Hexane = non-polar mobile phase → dissolves and carries non-polar molecules quickly down the column.

Question 03.8: Infrared (IR) Spectroscopy Confirmation

Explain how an IR spectrum confirms no cyclohexanol remains

✅ Correct Answer (Either option accepted)

  • There would be no peak/absorption at 3230 – 3550 cm⁻¹ corresponding to the O–H (alcohol) bond. [1 mark]
  • Alternative: The spectrum matches a pure reference sample of cyclohexene exactly, with no extra peaks in the fingerprint region (< 1500 cm⁻¹). [1 mark]

❌ Common Errors

  • Quoting an incorrect wavenumber range (must be 3230 – 3550 cm⁻¹ from the AQA Data Sheet for an alcohol O–H, not 2500 – 3000 cm⁻¹ which is for carboxylic acids).
  • Naming only the bond or only the wavenumber: both the wavenumber range and the O–H bond must be stated to secure the mark.

Topics

Physical Chemistry · Organic Chemistry · Required Practicals · 3.1.2 Amount of Substance · 3.3.4 Alkenes · 3.3.5 Alcohols · 3.3.6 Organic Analysis · 3.3.16 Chromatography · Required Practical 5: Distillation of a product from a reaction · Required Practical 10: Preparation of a pure organic liquid

Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2018. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.