AQA A-Level Chemistry Paper 1, 2019: Question 3
7 marks · Medium difficulty · State/Explain/Describe
Define periodicity, identify Period 4 elements by electronegativity and atomic radius trends with explanation, name the property of arsenic(III) oxide, and balance a chemical equation.
Practise this questionQuestion
Question text
03 This question is about periodicity, the Period 4 elements and their compounds.
03.1 State the meaning of the term periodicity.
[1 mark]
03.2 Identify the element in Period 4 with the highest electronegativity value.
[1 mark]
03.3 Identify the element in Period 4 with the largest atomic radius.
Explain your answer.
[3 marks]
Element
Explanation
03.4 The equations for two reactions of arsenic(III) oxide are shown.
As2O3 + 6HCl → 2AsCl3 + 3H2O
As2O3 + 6NaOH → 2Na3AsO3 + 3H2O
Name the property of arsenic(III) oxide that describes its ability to react in these two
ways.
[1 mark]
03.5 Complete the equation for the formation of arsenic hydride.
[1 mark]
As2O3 + Zn + HNO3 → AsH3 + Zn(NO3)2 + H2O
Mark scheme
Show the mark scheme
Question Answers Additional Comments/Guidelines Mark
Repeating pattern/trends (of physical or chemical Allow named property 1
03.1
properties/reactions) Penalise groups
Bromine/Br Not Br2
03.2 1
Accept Kr or Krypton
Potassium /K If Na or Rb lose M1 but allow access to M2 and M3 1
If other incorrect elements 0/3
03.3 Smallest number of protons/smallest nuclear charge
Similar shielding / same number of shells (as other elements in Allow same shielding 1
period 4)
03.4 Amphoteric 1
03.5 As2O3 + 6Zn + 12HNO3 → 2AsH3 + 6Zn(NO3)2 + 3H2O Accept multiples 1
How to answer it
Periodicity, Trends & Reactions of Period 4 Elements
What this question tests
This question evaluates your foundational knowledge of Periodicity, atomic trends across Period 4, and applying chemical principles to unfamiliar elements:
- Recalling the formal definition of periodicity.
- Identifying trends across Period 4: electronegativity and atomic radius.
- Explaining atomic radius using nuclear charge and electron shielding.
- Recognising amphoteric oxide behaviour from dual acid-base reactions.
- Balancing complex multi-reactant redox equations systematically.
Definition of Periodicity
State the meaning of the term periodicity
✅ Correct Answer
Repeating pattern (or trend) of physical or chemical properties across different periods.
💡 Key Knowledge
Periodicity refers to trends that recur at regular intervals across the Periodic Table as atomic number increases (e.g., repeating peaks in first ionisation energy or repeating trends in atomic radii across Periods 2, 3, and 4).
❌ Common Errors
- Omitting the word repeating (simply stating "a pattern of properties" gets 0 marks).
- Referring to trends down a group instead of across periods (penalised by examiners).
🧠 Exam Technique
Memorise the exact phrasing: "A repeating pattern or trend of physical or chemical properties." You may mention a named property (e.g., repeating pattern of ionisation energies), which is also accepted.
Period 4 Electronegativity
Identify the element in Period 4 with the highest electronegativity value
✅ Correct Answer
Bromine (or Br )
Note: Krypton / Kr is also accepted on the mark scheme.
💡 Key Knowledge
Electronegativity increases across a period because the nuclear charge increases while electron shielding remains approximately constant, creating a stronger attraction for a bonding pair of electrons.
❌ Common Errors
- Writing the molecular formula Br₂ instead of the element symbol Br or name Bromine (explicitly rejected in the mark scheme).
- Naming an element from Period 2 or 3 (such as Fluorine or Chlorine) by failing to read "Period 4".
🧠 Exam Technique
When asked to identify an element, give the single symbol (e.g., Br ) or write the full elemental name. Diatomic formulas ( Br₂ , Cl₂ , O₂ ) describe molecules, not the elemental identity, and will lose you the mark.
Atomic Radius Across Period 4
Identify the element with the largest atomic radius and explain your answer
✅ Correct Answer & Marks
- Element: Potassium (or K ) [1 mark]
- Explanation:
- Has the smallest number of protons / smallest nuclear charge (in Period 4) [1 mark]
- Has similar shielding / same number of electron shells (as other Period 4 elements) [1 mark]
💡 Key Knowledge
Atomic radius decreases across any period:
- Electrons are added to the same shell, so shielding remains similar.
- Nuclear charge increases (more protons), pulling the electron cloud closer to the nucleus.
- Therefore, Group 1 elements (leftmost) always possess the largest atomic radius in their period.
❌ Common Errors
- Naming an element in the wrong period: Selecting Na (Period 3) or Rb (Period 5) loses M1, though you can still get M2 and M3. Choosing any other wrong Period 4 element results in 0/3.
- Stating "potassium has no shielding" or "less shielding" — all Period 4 elements have three inner shielding shells!
- Failing to mention shielding altogether.
🧠 Exam Technique: The Three-Part Shielding Structure
Whenever explaining periodic size trends, always cover these three pillars:
- Nuclear charge: Count of protons.
- Shielding: Same or different number of inner shells.
- Net electrostatic attraction: Pull on outermost electrons.
Acid-Base Character of Oxides
Name the property of arsenic(III) oxide shown by reacting with both HCl and NaOH
✅ Correct Answer
Amphoteric
💡 Key Knowledge
Look at how As₂O₃ behaves in each reaction:
- As₂O₃ + 6HCl → 2AsCl₃ + 3H₂O : Reacts with an acid → acting as a base.
- As₂O₃ + 6NaOH → 2Na₃AsO₃ + 3H₂O : Reacts with a base → acting as an acid.
A substance that reacts with both acids and bases is defined as amphoteric (compare with Al₂O₃ in Period 3).
❌ Common Errors
- Confusing amphoteric with amphiprotic (amphiprotic specifically means donating/accepting H⁺ ions).
- Writing "neutralisation" (this describes the reaction type, not the property of the oxide).
Balancing Redox Equations
Complete the equation for the formation of arsenic hydride
📐 Step-by-Step Balancing Method
Unbalanced skeleton: _ As₂O₃ + _ Zn + _ HNO₃ → _ AsH₃ + _ Zn(NO₃)₂ + _ H₂O
- Balance Arsenic (As):
LHS has 2 As in As₂O₃ ⇒ Need 2 AsH₃ on RHS. - Balance Oxygen (O) not in nitrate:
LHS has 3 O in As₂O₃ ⇒ Need 3 H₂O on RHS. - Balance Hydrogen (H):
RHS total H = (2 × 3 in AsH₃) + (3 × 2 in H₂O) = 6 + 6 = 12 H.
Therefore, we need 12 HNO₃ on LHS. - Balance Nitrate ( NO₃⁻ ) and Zinc (Zn):
12 HNO₃ provides 12 nitrate groups.
Each Zn(NO₃)₂ contains 2 nitrates ⇒ 12 / 2 = 6 Zn(NO₃)₂ .
To balance Zn ⇒ Need 6 Zn on LHS.
✅ Final Balanced Equation
As₂O₃ + 6Zn + 12HNO₃ → 2AsH₃ + 6Zn(NO₃)₂ + 3H₂O
❌ Common Errors
- Forgetting that Hydrogen atoms appear in two products ( AsH₃ and H₂O ), leading to an incorrect coefficient for HNO₃ .
- Balancing oxygen by counting all nitrate oxygens individually, increasing the risk of arithmetic slips. Keep polyatomic ions like NO₃⁻ as single units!
Topics
Inorganic Chemistry · Physical Chemistry · 3.2.1 Periodicity · 3.1.2 Amount of Substance · 3.1.3 Bonding · 3.2.4 Properties of Period 3 Elements and Their Oxides
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 1, 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.