AQA A-Level Chemistry Paper 1, 2019: Question 4
14 marks · Medium difficulty · Long Answer
Identify reaction products, colours, and equations for aqueous iron complexes, suggest a reducing agent, and describe the shapes and isomerism of transition metal complexes with drawn examples.
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Question text
04 Figure 3 shows some reactions of aqueous iron ions.
Figure 3
04.1 Give the formula of Precipitate J and state its colour.
Give an equation for Reaction 1.
[3 marks]
Formula of J
Colour
Equation
04.2 Give the formula of L and an equation for Reaction 2.
[2 marks]
Formula of L
Equation
04.3 Suggest a reagent for Reaction 3.
[1 mark]
04.4 Give the formula of Precipitate M and state its colour.
[2 marks]
*07* Formula of M
Colour
04.5 Transition metal complexes have different shapes and many show isomerism.
Describe the different shapes of complexes and show how they lead to different
types of isomerism.
Use examples of complexes of cobalt(II) and platinum(II).
You should draw the structures of the examples chosen.
[6 marks]
Mark scheme
Show the mark scheme
Question Answers Additional Comments/Guidelines Mark
[Fe(OH)3(H2O)3] 1
M2: Allow red-brown
04.1 Brown 1
M3: Allow correct equations with Na2CO3
2 [Fe(H O) ]3+ + 3 CO 2– 2 [Fe(OH) (H O) ] + 3 CO + 3 H O M3: Ignore state symbols 1
26 3 3 2 3 2 2
[FeCl ]− 1
04.2 – −
[Fe(H O) ]3+ + 4 Cl [FeCl ] + 6 H O M2: Allow correct equations with HCl 1
26 4 2
04.3 (XS) Zn (in acid or HCl or H2SO4) Allow KI/potassium iodide 1
[Fe(OH)2(H2O)4] 1
04.4
green 1
This question is marked using levels of response. Refer to the Indicative Chemistry content
Mark Scheme Instructions for Examiners for guidance on how
to mark this question. Stage 1: shapes of complexes
Level 3 1a octahedral or 6 co-ordinate diagram
5–6 marks 1b tetrahedral or square planar or 4 co-ordinate diagram
All stages are covered and the description of each stage is 6
generally correct and virtually complete. Answer is
communicated coherently and shows a logical progression
from stage 1 to stage 2 and stage 3
Stage 2: cis/ trans isomerism (or E-Z or geometric)
Answer is illustrated using diagrams of at least 2 specific
examples of pairs of cobalt or platinum complex isomers. 2a cis/trans isomerism in either square planar and/or
octahedral complexes
Level 2
3–4 marks 2b Diagrams showing cis and trans isomerism in a square
All stages are covered but the description of each stage may planar complex
be incomplete or may contain inaccuracies OR two stages are
covered and the explanations are generally correct and 2c Diagrams showing cis and trans isomerism in both 15
04.5 virtually complete. Answer is mainly coherent and shows
isomers of octahdedral complexes eg draw cis and trans
progression from stage 1 to stage 2 and/or stage 3.
M(H O) (OH) or [M(NH ) (H O) ]2+
24 2 3 4 2 2
Answer is illustrated using diagrams of at least 1 specific
example of a pair of cobalt or platinum complex isomers.
Level 1
1–2 marks Stage 3: optical isomerism
Two stages are covered but the description of each stage may 3a optical isomerism / non superimposable mirror images in
be incomplete or may contain inaccuracies, OR only one stage
is covered but the explanation is generally correct and virtually octahedral complexes
complete. Answer includes isolated statements and these are 2-
presented in a logical order. 3b occurs with a specific bidentate ligands eg.C2O4 or
NH2CH2CH2NH2
Answer is illustrated using at least 1 appropriate diagram or
formula. 3c draw both optical isomers of eg [M(NH CH CH NH ) ]2+
22 2 2 3
Level 0
0 marks Insufficient correct chemistry to gain a mark.
How to answer it
Reactions of Aqueous Iron Ions & Transition Metal Complex Isomerism
This question assesses key Transition Metal chemistry:
- Hydrolysis and acidity differences between 3+ and 2+ aqueous metal-aqua ions with carbonate and ammonia.
- Ligand substitution involving coordination number change (chloride vs water).
- Redox reactions interconverting Fe³⁺ and Fe²⁺.
- 6-mark extended response on shapes of complexes (octahedral, tetrahedral, square planar) and isomerism (cis/trans and optical) with Cobalt(II) and Platinum(II).
Precipitate J and Reaction with Aqueous Sodium Carbonate
Reaction 1: [Fe(H₂O)₆]³⁺ with Na₂CO₃(aq)
✅ Mark Scheme Answers
Formula of J: [Fe(OH)₃(H₂O)₃] (or Fe(OH)₃)
Colour: Brown (allow red-brown)
Equation:
2[Fe(H₂O)₆]³⁺ + 3CO₃²⁻ → 2[Fe(OH)₃(H₂O)₃] + 3CO₂ + 3H₂O
(Equations using full formula Na₂CO₃ are also accepted: 2[Fe(H₂O)₆]³⁺ + 3Na₂CO₃ → 2[Fe(OH)₃(H₂O)₃] + 3CO₂ + 3H₂O + 6Na⁺)
💡 Key Knowledge
- Fe³⁺ has a high charge density, polarising O–H bonds in water ligands strongly. This makes [Fe(H₂O)₆]³⁺ acidic enough to react with weak base CO₃²⁻.
- Instead of forming an insoluble iron(III) carbonate, it undergoes an acid-base reaction yielding a neutral hydroxide precipitate and CO₂ gas (effervescence).
❌ Common Errors
- Writing "Fe₂(CO₃)₃" as the precipitate — iron(III) carbonate does not exist in aqueous solution.
- Forgetting CO₂ gas as a product in the equation.
- Misbalancing the stoichiometry: remember the 2 : 3 ratio (2Fe³⁺ : 3CO₃²⁻ produces 3CO₂ and 3H₂O).
🧠 Exam Technique
Mark Breakdown: 1 mark for correct formula of J; 1 mark for brown/red-brown; 1 mark for balanced equation. State symbols are not required.
Ligand Substitution with Concentrated HCl
Reaction 2: Formation of Complex Ion L
✅ Mark Scheme Answers
Formula of L: [FeCl₄]⁻
Equation:
[Fe(H₂O)₆]³⁺ + 4Cl⁻ → [FeCl₄]⁻ + 6H₂O
(Equation using concentrated HCl directly is also permitted: [Fe(H₂O)₆]³⁺ + 4HCl → [FeCl₄]⁻ + 6H₂O + 4H⁺)
💡 Key Knowledge
- Chloride ions (Cl⁻) are larger than neutral H₂O molecules and bear negative charges, causing electrostatic repulsion.
- Only 4 chloride ligands can coordinate around Fe³⁺, resulting in a change from 6-coordinate octahedral to 4-coordinate tetrahedral.
- Overall charge calculation: Fe³⁺ + 4(Cl⁻) = -1, hence [FeCl₄]⁻ .
❌ Common Errors
- Giving an incorrect charge like [FeCl₄]²⁻ or neutral FeCl₄.
- Assuming substitution is 1-to-1 without changing coordination number (e.g. writing [FeCl₆]³⁻).
- Forgetting to release all 6 H₂O molecules on the right-hand side.
🧠 Exam Technique
Mark Breakdown: 1 mark for correct formula of L (including charge); 1 mark for balanced equation.
Reduction of Iron(III) to Iron(II)
Reaction 3: [Fe(H₂O)₆]³⁺ → [Fe(H₂O)₆]²⁺
✅ Mark Scheme Answers
Acceptable Reagents:
- Zn (in acid, e.g. dilute HCl or H₂SO₄)
- KI / Potassium iodide (or any soluble iodide like NaI / I⁻)
💡 Key Knowledge
Fe³⁺ is reduced to Fe²⁺ (oxidation state drops from +3 to +2). You need a suitable reducing agent whose E° is more negative than E°(Fe³⁺/Fe²⁺ = +0.77 V):
- Zn(s) → Zn²⁺ + 2e⁻ (in dilute acid)
- 2I⁻ → I₂ + 2e⁻ (brown solution of iodine forms)
Precipitate M with Concentrated Ammonia
Reaction 4: [Fe(H₂O)₆]²⁺ with Concentrated NH₃(aq)
✅ Mark Scheme Answers
Formula of M: [Fe(OH)₂(H₂O)₄] (or Fe(OH)₂)
Colour: Green
💡 Key Knowledge
- Aqueous ammonia acts as a Bronsted-Lowry base: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻.
- Unlike Cu²⁺ or Co²⁺, iron(II) does not undergo ligand substitution in excess or concentrated NH₃. It stops at the neutral, insoluble hydroxide precipitate.
- On standing in air, this green precipitate gradually darkens and turns brown at the surface due to aerial oxidation to Fe(OH)₃.
❌ Common Errors
- Writing [Fe(NH₃)₆]²⁺ — expecting ammonia substitution to occur as it does with Cu²⁺ or Cr³⁺.
- Confusing the colour with Fe³⁺ hydroxide: Fe(OH)₂ is green, whereas Fe(OH)₃ is brown.
🧠 Exam Technique
Mark Breakdown: 1 mark for formula [Fe(OH)₂(H₂O)₄]; 1 mark for stating "green".
Shapes and Isomerism of Cobalt(II) and Platinum(II) Complexes
Level-of-Response Breakdown & Required Chemistry Content
📋 Marking Scheme Criteria (Levels of Response)
To access Level 3 (5–6 marks), all 3 stages must be covered, logically structured, and supported by clear 3D/structural diagrams of at least two specific pairs of isomers involving Co and/or Pt complexes.
Stage 1: Shapes of Complexes
- Octahedral: 6 coordinate bonds, bond angles 90° (e.g. Cobalt(II) complexes like [Co(H₂O)₆]²⁺).
- Tetrahedral: 4 coordinate bonds, bond angle 109.5° (e.g. [CoCl₄]²⁻ with large chloride ligands).
- Square Planar: 4 coordinate bonds, bond angles 90°, characteristic of Pt(II) complexes like cisplatin, [Pt(NH₃)₂Cl₂].
Stage 2: Cis/Trans (E-Z / Geometric) Isomerism
- In Square Planar [Pt(NH₃)₂Cl₂]:
• cis-platin: identical ligands (Cl–Cl and NH₃–NH₃) are 90° apart (adjacent).
• trans-platin: identical ligands are 180° apart (opposite each other across the Pt centre). - In Octahedral Complexes (e.g. [Co(H₂O)₄(OH)₂] or [Co(NH₃)₄Cl₂]):
• cis-isomer: the two identical ligands are adjacent (90°).
• trans-isomer: the two identical ligands are opposite (180°).
Stage 3: Optical Isomerism
- Occurs in octahedral complexes with bidentate ligands (e.g. 1,2-diaminoethane: H₂NCH₂CH₂NH₂ / "en", or ethanedioate: C₂O₄²⁻ ).
- Example: [Co(H₂NCH₂CH₂NH₂)₃]²⁺ or [Co(en)₂Cl₂] (specifically the cis isomer).
- Forms non-superimposable mirror images (enantiomers) that rotate the plane of plane-polarised light in opposite directions.
🎨 How to Draw the Isomers in the Exam
Draw a flat cross with Pt in the centre.
• Cis: Cl at top, Cl at left (adjacent); NH₃ at bottom, NH₃ at right.
• Trans: Cl at top, Cl at bottom (180°); NH₃ at left, NH₃ at right (180°).
Draw two octahedral cobalt skeletons separated by a dashed mirror line. Connect adjacent pairs of coordination bonds with curved loops labelled "en" or "NH₂CH₂CH₂NH₂". Show non-superimposable chiral reflection.
Topics
Inorganic Chemistry · 3.2.5 Transition Metals · 3.2.6 Reactions of Ions in Aqueous Solution
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 1, 2019. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.