AQA A-Level Chemistry AS Paper 1, November 2021: Question 3
4 marks · Medium difficulty · State/Explain/Describe
State the meaning of an oxidising agent and deduce half-equations and the overall redox equation for the oxidation of sulfite ions by dichromate ions in acidic conditions.
Practise this questionQuestion
Question text
03 This question is about redox reactions.
03.1 State, in terms of electrons, the meaning of the term oxidising agent.
[1 mark]
03.2 Cr O 2– can oxidise SO 2– in acidic conditions to form Cr3+ and SO 2–
27 3 4
Deduce a half-equation for the oxidation of SO 2– to SO 2–
Deduce a half-equation for the reduction of Cr O 2– to Cr3+
Deduce the overall equation for the oxidation of SO 2– by Cr O 2–
32 7
[3 marks]
Half-equation for the oxidation of SO 2– to SO 2–
Half-equation for the reduction of Cr O 2– to Cr3+
Overall equation
Mark scheme
Show the mark scheme
Question Marking guidance Additional Comments/Guidelines Mark
03.1 Electron acceptor Do not allow electron pair acceptor 1
SO 2– + H O → SO 2– + 2H+ + 2e– Allow multiples in each case 1
32 4
03.2 Cr O 2– + 14H+ + 6e– → 2Cr3+ + 7H O 1
27 2
3SO 2– + Cr O 2– + 8H+ → 3SO 2– + 2Cr3+ + 4H O 1
32 7 4 2
How to answer it
Redox Reactions & Half-Equations Study Guide
What this question tests
This question assesses your fundamental understanding of redox terminology and your ability to construct complex ion-electron half-equations in acidic conditions, culminating in combining them into a balanced overall redox equation.
Defining an Oxidising Agent
State, in terms of electrons, the meaning of the term oxidising agent.
✅ Correct Answer
Electron acceptor
❌ Common Errors
- Writing "electron pair acceptor" (this refers to Lewis acids/coordinate bonding, not redox).
- Stating that it "loses electrons" or "donates oxygen" (must strictly refer to electrons for this command term).
Constructing Half-Equations & Overall Redox Equations
Deduce half-equations and combine them for the oxidation of SO₃²⁻ by Cr₂O₇²⁻ in acidic conditions.
✅ Correct Answers
- Oxidation half-equation: SO₃²⁻ + H₂O → SO₄²⁻ + 2H⁺ + 2e⁻
- Reduction half-equation: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O
- Overall equation: 3SO₃²⁻ + Cr₂O₇²⁻ + 8H⁺ → 3SO₄²⁻ + 2Cr³⁺ + 4H₂O
🧠 Exam Technique (The Ion-Electron Method)
- Balance main elements: Balance atoms other than O and H first.
- Balance Oxygen: Add H₂O to the side deficient in oxygen.
- Balance Hydrogen: Add H⁺ ions to the opposite side to balance the hydrogens introduced by water.
- Balance Charge: Add electrons ( e⁻ ) to make the total charge equal on both sides.
- Scale and Combine: Multiply half-equations so electron numbers match, then cancel out electrons and simplify common species ( H⁺ and H₂O ).
❌ Common Errors & Examiner Pitfalls
- Failing to multiply the sulfite oxidation half-equation by 3 before combining, leaving uncancelled electrons in the final equation.
- Incorrectly adding OH⁻ instead of H⁺ despite the question explicitly stating "acidic conditions".
- Algebraic slip-ups when cancelling out excess H⁺ and H₂O on opposite sides of the overall equation.
Topics
Physical Chemistry · 3.1.7 Oxidation, Reduction and Redox Equations
Question and mark scheme from the AQA A-Level Chemistry examination, AS Paper 1, November 2021. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.