AQA A-Level Chemistry Paper 3, June 2022: Question 29
1 mark · Medium difficulty · Multiple Choice
Identify the predominant ionic species of aspartic acid present in an aqueous solution at pH = 14.
Practise this questionQuestion
Question text
29 Which is the main species present in an aqueous solution of aspartic acid at pH = 14?
[1 mark]
A
B
C
D
Mark scheme
Show the mark scheme
29 D (AO2) 1
How to answer it
Amino Acids: Ionisation of Aspartic Acid at Extreme pH
📋 What this question tests
This question assesses your ability to apply acid-base principles to multi-functional organic molecules under Section 3.3.13 (Amino acids, proteins and DNA):
- Recognising the acidic and basic functional groups present in an amino acid.
- Predicting the protonation/deprotonation state of carboxylic acid (-COOH) and amino (-NH₂) groups across different pH environments.
- Identifying the specific structure of aspartic acid as an amino acid carrying a carboxylic acid side chain (-CH₂COOH).
Question 29 • Multiple Choice • 1 Mark
Identifying Aspartic Acid Species at pH = 14
Target: AO2 (Application of Knowledge)
✅ Correct Answer: D
Structure: Fully deprotonated dianion
CH₂COO⁻
|
H — C — NH₂
|
COO⁻
|
H — C — NH₂
|
COO⁻
Mark Scheme Breakdown:
• D → 1 mark
• Any other option → 0 marks
• D → 1 mark
• Any other option → 0 marks
💡 Key Knowledge
- At very high pH (pH = 14): The concentration of OH⁻ ions is extremely high (1.0 mol dm⁻³). Strongly alkaline conditions remove all acidic protons.
- Carboxylic acid groups (-COOH): Act as proton donors. Both react with base:
-COOH + OH⁻ → -COO⁻ + H₂O - Amine groups (-NH₂): Basic/neutral. In alkaline solution, they remain unprotonated as -NH₂ .
- Aspartic acid is an acidic amino acid containing two -COOH groups (one on the main chain and one on the -CH₂- side chain). Both are fully deprotonated at pH 14, yielding an overall 2- charge.
📐 Step-by-Step Deduction
- Analyse the environment:
pH = 14 indicates an extremely concentrated alkali solution. - Assess the -NH₂ group:
In base, amines cannot accept protons. It must be uncharged: -NH₂ (Rules out B and C). - Assess both -COOH groups:
Both the α-COOH and side-chain β-COOH have pKₐ values well below 14 (typically around 2.1 and 3.9). Both lose their protons to form -COO⁻ . - Match to options:
Option D shows both carboxyl groups deprotonated ( -COO⁻ ) and the amino group unprotonated ( -NH₂ ).
🧠 Exam Technique: Systematic Elimination
- Rule out B and C immediately: Look at the nitrogen atom. In alkaline solution (pH 14), an amino group can never exist as -NH₃⁺ . Protonation requires excess H⁺ (low pH).
- Compare A and D: Option A shows neither carboxylic acid deprotonated. Fully unionised amino acids do not even exist in neutral aqueous solution (they form zwitterions), and certainly cannot exist in strong alkali.
- Check all functional groups: Always scan the variable R-group. Aspartic acid and glutamic acid have acidic side chains; lysine and arginine have basic side chains.
❌ Common Errors & Examiner Traps
- Choosing C (The Zwitterion): Students remember that amino acids have charges, but forget that the zwitterion ( -NH₃⁺ / -COO⁻ ) only predominates at the isoelectric point (around pH 2.8 for aspartic acid), never at pH 14.
- Choosing A (Standard Lewis Structure): Forgetting that carboxylic acids act as weak acids in water and react completely with strong bases like NaOH at pH 14.
- Deprotonating only one -COOH group: Overlooking that aspartic acid has two carboxylic acid groups that both deprotonate at high pH.
- Confusing high pH with high [H⁺]: Remembering "pH 14 = high number" but confusing it with acidic conditions, leading to selecting protonated forms like B.
Topics
Organic Chemistry · 3.3.13 Amino Acids, Proteins and DNA
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.