AQA A-Level Chemistry Paper 3, June 2022: Question 30
1 mark · Easy difficulty · Multiple Choice
Identify which reaction type is not involved in a three-step synthetic sequence from phenylethanone to 1-(3-nitrophenyl)ethyl ethanoate.
Practise this questionQuestion
Question text
Which type of reaction is not involved in this reaction sequence?
[1 mark]
A esterification
B hydrolysis
C nitration
D reduction
Mark scheme
Show the mark scheme
30 B (AO3) 1 hydrolysis
How to answer it
Reaction Types in Aromatic Synthesis
This question assesses your ability to analyze multi-step organic reaction pathways and identify the specific reaction types occurring at each transformation:
- Recognising electrophilic aromatic substitution (specifically, nitration of a benzene ring).
- Identifying the reduction of a carbonyl group (ketone) to a secondary alcohol using reducing agents like NaBH₄.
- Recognising esterification (acylation) of an alcohol using an acyl chloride or acid anhydride.
- Distinguishing between forward synthetic steps (ester formation) and cleavage reactions (hydrolysis).
Identifying the Reaction Type Not Present
Analysis of the 3-step synthesis from phenylethanone
📐 Step-by-Step Pathway Analysis
Trace the functional group changes across each arrow:
- Step 1
C₆H₅COCH₃ → NO₂-C₆H₄COCH₃
An -NO₂ group is introduced onto the benzene ring at position 3. This is nitration (electrophilic substitution). - Step 2
-COCH₃ → -CH(OH)CH₃
The ketone carbonyl group ( C=O ) is converted into a secondary alcohol ( -CH(OH)- ). This is a reduction (nucleophilic addition of hydride). - Step 3
-CH(OH)CH₃ → -CH(OCOCH₃)CH₃
The alcohol group reacts with an acylating agent (e.g., ethanoic anhydride or ethanoyl chloride) to form an ester. This is esterification.
✅ Correct Answer
Option B: hydrolysis
Award 1 mark for selecting B (AO3).
Since nitration (Step 1), reduction (Step 2), and esterification (Step 3) are all present in the sequence, hydrolysis is the reaction type not involved.
💡 Key Knowledge
- Nitration reagents: Concentrated HNO₃ and concentrated H₂SO₄ catalyst below 55 °C. The -COCH₃ group is electron-withdrawing and directs substitution to the 3- (meta-) position.
- Reduction reagents: Aqueous/ethanolic sodium tetrahydridoborate(III), NaBH₄, reduces aldehydes and ketones to alcohols.
- Esterification: Alcohols react with carboxylic acids (acid catalyst), acyl chlorides (room temp, produces HCl), or acid anhydrides (produces ethanoic acid) to form esters.
- Hydrolysis: The chemical breakdown of a compound due to reaction with water (e.g. ester → alcohol + carboxylic acid), which is the reverse of Step 3!
🧠 Exam Technique & Traps
- Spot the negative phrasing: The question asks which reaction is NOT involved. Highlight words like "not", "incorrect", or "least" immediately.
- Do not confuse esterification with hydrolysis: In Step 3, an ester linkage is being created, not broken. Hydrolysis breaks an ester apart using water or hydroxide ions.
- Watch the formula notation: -CH(OCOCH₃)CH₃ denotes an ester group ( -O-CO-CH₃ ) attached to the carbon chain, confirming esterification took place.
❌ Common Misconceptions & Errors
- Confusing reduction with oxidation: Students sometimes see oxygen remaining in the molecule and fail to recognise that adding hydrogen across the C=O double bond decreases the carbon's oxidation state (reduction).
- Misreading the condensed formula in Step 3: Reading -CH(OCOCH₃)CH₃ too quickly and assuming it is an ether or an anhydride rather than an ethanoate ester.
Topics
Organic Chemistry · 3.3.8 Aldehydes and Ketones · 3.3.9 Carboxylic Acids and Derivatives · 3.3.10 Aromatic Chemistry · 3.3.14 Organic Synthesis
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.