AQA A-Level Chemistry Paper 3, June 2025: Question 13
1 mark · Medium difficulty · Multiple Choice
Identify which compound reacts with concentrated sulfuric acid to form an intermediate that reacts with excess water to produce an alcohol.
Practise this questionQuestion
Question text
13 Compound X reacts with concentrated sulfuric acid to produce compound Y.
Compound Y reacts with an excess of water to produce an alcohol.
Which compound could be X?
[1 mark]
A Ethanoyl chloride
B Methylbenzene
C Propanone
D Propene
Mark scheme
Show the mark scheme
13 D 1 (AO2) Propene
How to answer it
Electrophilic Addition & Hydrolysis of Alkenes
This question assesses knowledge of organic reaction pathways from the AQA specification, specifically:
- The electrophilic addition reaction of alkenes with concentrated sulfuric acid (H₂SO₄).
- The structure and formula of alkyl hydrogen sulfates (intermediate compound Y).
- The subsequent hydrolysis of alkyl hydrogen sulfates by warming with excess water to form an alcohol and regenerate H₂SO₄.
Compound Identification via Two-Step Synthesis
Multiple Choice [1 Mark]
✅ Correct Answer
D: Propene
Summary of the pathway:
CH₃CH=CH₂ (X) + H₂SO₄ → CH₃CH(OSO₂OH)CH₃ (Y)
CH₃CH(OSO₂OH)CH₃ + H₂O → CH₃CH(OH)CH₃ + H₂SO₄
Compound Y is isopropyl hydrogen sulfate (or propyl hydrogen sulfate), which hydrolyses to produce propan-2-ol (an alcohol).
💡 Key Knowledge
- Step 1 (Electrophilic Addition): Alkenes react with cold concentrated H₂SO₄. The electrophile is the partially positive hydrogen atom in H-OSO₃H . Addition follows Markovnikov's rule, producing a secondary alkyl hydrogen sulfate as the major product.
- Step 2 (Hydrolysis): When water is added and the mixture is warmed, the -OSO₂OH (hydrogen sulfate) group is substituted by an -OH group.
- Catalytic Role: Because H₂SO₄ is regenerated at the end, the overall process is the acid-catalysed hydration of an alkene:
Alkene + H₂O → Alcohol
📐 Detailed Two-Stage Chemistry
Concentrated sulfuric acid acts as an electrophile:
CH₃-CH=CH₂ + H₂SO₄ → CH₃-CH(OSO₂OH)-CH₃
Mechanism note: The C=C double bond attacks the electrophilic H atom of H-OSO₃H. A secondary carbocation intermediate ( CH₃-CH⁺-CH₃ ) forms preferentially over the primary carbocation due to inductive stabilisation by two alkyl groups. The ⁻OSO₃H ion then attacks the carbocation.
Hydrolysis with excess warm water:
CH₃-CH(OSO₂OH)-CH₃ + H₂O → CH₃-CH(OH)-CH₃ + H₂SO₄
The sulfate group leaves, yielding the secondary alcohol propan-2-ol and regenerating sulfuric acid.
❌ Analysis of Incorrect Distractors
- A: Ethanoyl chloride — Reacts vigorously directly with water to produce ethanoic acid ( CH₃COOH ) and HCl, not an alcohol. Concentrated H₂SO₄ does not yield an alcohol intermediate.
- B: Methylbenzene — Undergoes electrophilic substitution (sulfonation) with concentrated/fuming H₂SO₄ to form methylbenzenesulfonic acid. Hydrolysis with water does not yield an alcohol.
- C: Propanone — A ketone does not react with concentrated H₂SO₄ followed by water to yield an alcohol. Concentrated acid can act as a catalyst for aldol condensation, not alcohol production.
🧠 Exam Technique & Examiner Insights
- Look for the "Two-Step Hydration": In Year 12 alkene chemistry, industrial hydration uses steam and an acid catalyst ( H₃PO₄ ), but the laboratory method uses concentrated H₂SO₄ followed by excess water. Recognising this laboratory sequence immediately points to an alkene.
- Identify Functional Groups Fast: When an exam question specifies a sequence like X + conc. H₂SO₄ → Y and Y + H₂O → alcohol , mentally replace X with every homologous series. Only alkenes form alkyl hydrogen sulfates that hydrolyse to alcohols.
Topics
Organic Chemistry · 3.3.4 Alkenes · 3.3.5 Alcohols
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.