AQA A-Level Chemistry Paper 3, June 2025: Question 13

1 mark · Medium difficulty · Multiple Choice

Identify which compound reacts with concentrated sulfuric acid to form an intermediate that reacts with excess water to produce an alcohol.

Practise this question

Question

Question 13 asks: 'Compound X reacts with concentrated sulfuric acid to produce compound Y. Compound Y reacts with an excess of water to produce an alcohol. Which compound could be X?' Four options are given: A Ethanoyl chloride, B Methylbenzene, C Propanone, D Propene.
Question text

13 Compound X reacts with concentrated sulfuric acid to produce compound Y.

Compound Y reacts with an excess of water to produce an alcohol.

Which compound could be X?

[1 mark]

A Ethanoyl chloride

B Methylbenzene

C Propanone

D Propene

Mark scheme

Show the mark scheme Mark scheme table shows for question 13: the correct option is 'D', worth 1 mark (AO2), corresponding to 'Propene'.

13 D 1 (AO2) Propene

How to answer it

Electrophilic Addition & Hydrolysis of Alkenes

📋 What this question tests

This question assesses knowledge of organic reaction pathways from the AQA specification, specifically:

  • The electrophilic addition reaction of alkenes with concentrated sulfuric acid (H₂SO₄).
  • The structure and formula of alkyl hydrogen sulfates (intermediate compound Y).
  • The subsequent hydrolysis of alkyl hydrogen sulfates by warming with excess water to form an alcohol and regenerate H₂SO₄.
Question 13

Compound Identification via Two-Step Synthesis

Multiple Choice [1 Mark]

✅ Correct Answer

D: Propene

Award 1 mark for selecting option D.

Summary of the pathway:

CH₃CH=CH₂ (X) + H₂SO₄ → CH₃CH(OSO₂OH)CH₃ (Y)

CH₃CH(OSO₂OH)CH₃ + H₂O → CH₃CH(OH)CH₃ + H₂SO₄

Compound Y is isopropyl hydrogen sulfate (or propyl hydrogen sulfate), which hydrolyses to produce propan-2-ol (an alcohol).

💡 Key Knowledge

  • Step 1 (Electrophilic Addition): Alkenes react with cold concentrated H₂SO₄. The electrophile is the partially positive hydrogen atom in H-OSO₃H . Addition follows Markovnikov's rule, producing a secondary alkyl hydrogen sulfate as the major product.
  • Step 2 (Hydrolysis): When water is added and the mixture is warmed, the -OSO₂OH (hydrogen sulfate) group is substituted by an -OH group.
  • Catalytic Role: Because H₂SO₄ is regenerated at the end, the overall process is the acid-catalysed hydration of an alkene:
    Alkene + H₂O → Alcohol

📐 Detailed Two-Stage Chemistry

Stage 1: Formation of Compound Y

Concentrated sulfuric acid acts as an electrophile:

CH₃-CH=CH₂ + H₂SO₄ → CH₃-CH(OSO₂OH)-CH₃

Mechanism note: The C=C double bond attacks the electrophilic H atom of H-OSO₃H. A secondary carbocation intermediate ( CH₃-CH⁺-CH₃ ) forms preferentially over the primary carbocation due to inductive stabilisation by two alkyl groups. The ⁻OSO₃H ion then attacks the carbocation.

Stage 2: Reaction with Water

Hydrolysis with excess warm water:

CH₃-CH(OSO₂OH)-CH₃ + H₂O → CH₃-CH(OH)-CH₃ + H₂SO₄

The sulfate group leaves, yielding the secondary alcohol propan-2-ol and regenerating sulfuric acid.

❌ Analysis of Incorrect Distractors

  • A: Ethanoyl chloride — Reacts vigorously directly with water to produce ethanoic acid ( CH₃COOH ) and HCl, not an alcohol. Concentrated H₂SO₄ does not yield an alcohol intermediate.
  • B: Methylbenzene — Undergoes electrophilic substitution (sulfonation) with concentrated/fuming H₂SO₄ to form methylbenzenesulfonic acid. Hydrolysis with water does not yield an alcohol.
  • C: Propanone — A ketone does not react with concentrated H₂SO₄ followed by water to yield an alcohol. Concentrated acid can act as a catalyst for aldol condensation, not alcohol production.

🧠 Exam Technique & Examiner Insights

  • Look for the "Two-Step Hydration": In Year 12 alkene chemistry, industrial hydration uses steam and an acid catalyst ( H₃PO₄ ), but the laboratory method uses concentrated H₂SO₄ followed by excess water. Recognising this laboratory sequence immediately points to an alkene.
  • Identify Functional Groups Fast: When an exam question specifies a sequence like X + conc. H₂SO₄ → Y and Y + H₂O → alcohol , mentally replace X with every homologous series. Only alkenes form alkyl hydrogen sulfates that hydrolyse to alcohols.

Topics

Organic Chemistry · 3.3.4 Alkenes · 3.3.5 Alcohols

Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.