AQA A-Level Chemistry Paper 3, June 2025: Question 30
1 mark · Easy difficulty · Multiple Choice
Identify the correct order of decreasing pH for solutions formed when equal amounts of sodium, magnesium, and chlorine are added separately to water.
Practise this questionQuestion
Question text
30 Equal amounts of three Period 3 elements are added to separate 100 cm3 samples
of water.
Which list is correct when the solutions formed from these elements are arranged in
order of decreasing pH?
[1 mark]
A chlorine magnesium sodium
B chlorine sodium magnesium
C magnesium sodium chlorine
D sodium magnesium chlorine
Mark scheme
Show the mark scheme
30 D 1 (AO1) sodium magnesium chlorine
How to answer it
Period 3 Elements: Reactions with Water & Solution pH
This question assesses knowledge of AQA A-Level Chemistry Section 3.2.4 (Period 3 Elements):
- The redox reactions of sodium, magnesium, and chlorine with liquid water.
- The relative solubilities of the resulting hydroxides and the acidity/alkalinity of the resulting solutions.
- Understanding pH trends across the period (from strongly alkaline to acidic).
- Careful interpretation of ordered data: specifically, decreasing order (highest pH → lowest pH).
Multiple Choice Analysis
Identifying the correct sequence of decreasing pH
✅ Correct Answer
D | sodium → magnesium → chlorine
"Decreasing pH" means starting at the highest pH (most alkaline) and ending at the lowest pH (most acidic):
Sodium (pH 13–14) > Magnesium (pH ~9) > Chlorine (pH 1–2)
💡 Key Knowledge: Reactions with Water
| Element | Equation with H₂O(l) | Approx. pH |
|---|---|---|
| Sodium | 2Na + 2H₂O → 2NaOH + H₂ | 13 – 14 (Strong alkali, fully soluble) |
| Magnesium | Mg + 2H₂O → Mg(OH)₂ + H₂ | ~9 (Weak alkali, sparingly soluble) |
| Chlorine | Cl₂ + H₂O ⇌ HCl + HClO | 1 – 2 (Acidic, forms HCl and HClO) |
🧠 Exam Technique: Two-Step Elimination
- Define the direction first: "Decreasing pH" = High pH → Low pH. Annotate the question with an arrow pointing from 14 down to 1.
- Find the extremes:
- Sodium forms NaOH, which is a strong, completely soluble base (pH ~13–14). The list must start with sodium. This immediately eliminates A, B, and C!
- Chlorine forms hydrochloric acid (strong) and chloric(I) acid (weak), giving an acidic solution (pH < 7). It must be at the end of the decreasing list.
- Verify the middle element: Mg(OH)₂ is only sparingly soluble, releasing fewer OH⁻ ions into solution than NaOH, meaning pH ~9. This sits correctly between sodium and chlorine.
❌ Common Traps & Examiner Commentary
- Selecting Option A (Inverted Order): The most common error in this question is reading "decreasing pH" as "increasing acidity" or simply confusing the direction. Option A arranges the elements in order of increasing pH (lowest to highest).
- Confusing Mg with water vs Mg with steam:
- With cold water (very slow): Mg + 2H₂O(l) → Mg(OH)₂ + H₂
- With steam (vigorous): Mg + H₂O(g) → MgO + H₂
- Forgetting Chlorine's Disproportionation: Cl₂ reacts reversibly with water to form two acids: HCl (hydrochloric acid) and HClO (chloric(I) acid). Students sometimes mistakenly think chlorine forms a neutral dissolved molecular solution like O₂ or N₂.
Topics
Inorganic Chemistry · 3.2.4 Properties of Period 3 Elements and Their Oxides · 3.2.3 Group 7(17), The Halogens
Question and mark scheme from the AQA A-Level Chemistry examination, Paper 3, June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.