AQA A-Level Physics Paper 1, June 2024: Question 24

1 mark · Medium difficulty · Multiple Choice

Calculate the mass of air passing through a jet engine in one minute given the average force and change in speed.

Practise this question

Question

Multiple choice question 24. An average force of 42 kN acts on air passing through a jet engine, increasing its speed by 540 m s^-1. Four options for the mass of air passing through the engine in one minute are given: A 7.7 x 10^-2 kg, B 4.7 kg, C 78 kg, D 4700 kg.
Question text

24 An average force of 42 kN acts on the air passing through a jet engine. This force causes

the speed of the air to increase by 540 m s−1.

What mass of air passes through the engine in one minute?

[1 mark]

A 7.7 × 10−2 kg

B 4.7 kg

C 78 kg

D 4700 kg

Mark scheme

Show the mark scheme Mark scheme indicating the correct answer is D with a value of 4700 kg, categorized under AO2.

24 D 4700 kg AO2

How to answer it

Jet Engine Momentum & Force Calculation

Question 2.4 • Multiple Choice • 1 Mark

What this question tests

This question assesses your understanding of Newton's second law in terms of momentum (Force equals rate of change of momentum), unit conversions (kilonewtons to newtons, minutes to seconds), and rearranging equations to solve for mass over a given time interval.

Question Part 2.4

Calculate mass of air passing through a jet engine in one minute

✅ Correct Answer

Option D: 4700 kg

Awarded 1 mark for selecting option D.

💡 Key Knowledge

  • Newton's Second Law: F = d(mv)/dt
  • For a constant mass flow rate, force can be written as F = (Δm/Δt) × Δv or F = (m/t) × v .
  • Prefix conversions: 1 kN = 10³ N
  • Time conversion: 1 minute = 60 s

🧠 Exam Technique

In multiple-choice calculation questions, always write down your rearranged formula before plugging in numbers. Pay careful attention to time units—forgetting to convert minutes into seconds is the #1 trap in rate-of-momentum questions.

📐 Step-by-Step Calculation

  1. State the formula relating force to rate of change of momentum:
    F = (Δm / Δt) × v
  2. Rearrange to make total mass ( Δm ) the subject:
    Δm = (F × Δt) / v
  3. Substitute the values with correct units:
    Force F = 42 kN = 42 × 10³ N
    Time Δt = 1 minute = 60 s
    Velocity change v = 540 m s&sup{-1}
  4. Calculate:
    Δm = (42 × 10³ × 60) / 540
    Δm = 2,520,000 / 540 = 4666.67 kg
  5. Round to appropriate significant figures:
    Given data ( 42 kN , 540 m s&sup{-1} ) are given to 2 sig figs, giving 4700 kg .

❌ Common Errors & Distractor Traps

  • Forgetting to multiply by time (60 s): Calculating just 42000 / 540 yields 77.8 kg (leading students to incorrectly choose Option C, or get 7.7 × 10&sup{-2} kg if mixed up).
  • Power of 10 errors: Forgetting to convert kN to N (omitting the × 10³ factor).

Topics

Physics · 3.4 Mechanics and materials

Question and mark scheme from the AQA A-Level Physics examination, Paper 1, June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.