AQA A-Level Physics Paper 1, June 2024: Question 25
1 mark · Medium difficulty · Multiple Choice
Calculate the increase in elastic strain energy stored in a wire when the load is increased from F to 2F.
Practise this questionQuestion
Question text
25 A uniform wire is stretched by a load F.
The elastic strain energy stored in the wire is E.
The load is increased from F to 2F.
The wire obeys Hooke’s law.
What is the increase in the elastic strain energy stored in the wire?
[1 mark]
A E
B 2E
C 3E
D 4E
Mark scheme
Show the mark scheme
25 C 3E AO2
How to answer it
Question 25: Elastic Strain Energy in a Stretched Wire
What this question tests
This question assesses your understanding of Hooke's law, elastic strain energy, and proportional reasoning (AO2). Specifically, it tests whether you can recognise the non-linear (squared) relationship between force/extension and stored energy, rather than assuming a simple linear doubling.
Multiple Choice Question (1 Mark)
✅ Correct Answer: C (3E)
When the load increases from F to 2F , the final elastic strain energy is 4E . The increase in energy is 4E - E = 3E .
💡 Key Knowledge
- Hooke's Law: F = kx (Force is directly proportional to extension).
- Elastic Strain Energy ( E ) is given by the area under a force-extension graph: E = 0.5 × F × x .
- Substituting x = F / k gives the alternative formula: E = 0.5 × F² / k , showing that E is proportional to F² .
🧠 Exam Technique
Read the question carefully: it asks for the increase in energy ( Final - Initial ), not just the final total energy. Many students spot 4E and immediately select option D without checking what is actually being asked.
❌ Common Errors
- Option D (4E): Failing to calculate the increase. 4E is the total final energy, not the change in energy.
- Option B (2E): Treating elastic strain energy as directly proportional to force ( E ∝ F ) instead of proportional to force squared ( E ∝ F² ).
📐 Step-by-Step Calculation Breakdown
- Initial State: Initial force = F , Initial energy E₁ = E = 0.5 × F² / k .
- Final State: Final force = 2F . Final energy E₂ = 0.5 × (2F)² / k = 0.5 × 4F² / k = 4 × (0.5 × F² / k) = 4E .
- Calculate Increase: Increase = E₂ - E₁ = 4E - E = 3E .
Topics
Physics · 3.4 Mechanics and materials
Question and mark scheme from the AQA A-Level Physics examination, Paper 1, June 2024. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.