AQA AS Level Biology Paper 1, November 2020: Question 4
9 marks · Medium difficulty · Short Answer
Outline the role of organelles in protein production and transport, suggest why a nucleus is not visible in a TEM micrograph, identify organelles S and T, give an advantage of TEM over SEM, and calculate the number of cells in a leaf surface in standard form.
Practise this questionQuestion
Question text
04.1 Eukaryotic cells produce and release proteins.
Outline the role of organelles in the production, transport and release of proteins from
eukaryotic cells.
Do not include details of transcription and translation in your answer.
[4 marks]
Figure 3 is a transmission electron micrograph of a plant cell.
Figure 3
04.2 Suggest why a nucleus is not visible in Figure 3.
[1 mark]
04.3 Name the organelles labelled S and T in Figure 3.
[1 mark]
Organelle S
Organelle T
04.4 Give one advantage of viewing a biological specimen using a transmission electron
microscope compared with using a scanning electron microscope.
[1 mark]
04.5 The cells in Figure 4 are part of a continuous layer of cells forming the upper surface
of a leaf.
The shaded area of cell U is 150 μm2
The total area of the upper surface of the leaf is 70.65 cm2
Figure 4
Calculate the number of cells in the upper surface of the leaf.
Give the answer in standard form.
Assume that all these cells are identical in size.
Show your working.
[2 marks]
Number of cells
Mark scheme
Show the mark scheme
Question Marking Guidance Mark Comments
04.1 4 max
1. DNA in nucleus is code (for protein);
2. and 5. Accept rER
2. Ribosomes/rough endoplasmic reticulum
for ‘rough
produce (protein);
endoplasmic
3. Mitochondria produce ATP (for protein reticulum’
synthesis);
4 Golgi apparatus package/modify; 4. Accept body for
‘apparatus’
OR
Carbohydrate added/glycoprotein produced by
Golgi apparatus;
5 Vesicles transport
OR
Rough endoplasmic reticulum transports;
6. (Vesicles) fuse with cell(-surface) membrane; 6. Accept exocytosis
at cell membrane
04.2 A section/slice (so nucleus in another part of cell) 1
OR
(Nucleus) not stained;
04.3 1 Reject
thylakoid/granum
S = Vacuole
Reject incorrect
T = Chloroplast; spelling
04.4 Higher resolution 1
OR
– LOGY – – JUNE 2020
View internal structures;
04.5 Correct answer of 4.71 x 107 for 2 marks;; 2
Accept for 1 mark
Any answer showing conversion factor of
100 000 000 / 108
OR
Correct answer for any number divided by 150 eg
70.65 ÷ 150 / 0.471
OR
Any answer including digits 471 in this order,
irrespective of position of decimal place
TOTAL 9
How to answer it
Eukaryotic Cells, Organelles, and Microscopy Study Guide
What this question tests
This assessment evaluates your understanding of eukaryotic ultrastructure, the precise functional roles of organelles in protein synthesis and transport, cell ultrastructure identification from electron micrographs, microscope capabilities (TEM vs SEM), and multi-step unit conversion calculations involving standard form.
Protein Production and Organelle Roles
Outline the role of organelles in the production, transport and release of proteins from eukaryotic cells (excluding transcription and translation). [4 marks]
✅ Correct Answer / Mark Scheme
- DNA/Nucleus: Contains the genetic code for the protein.
- Ribosomes / Rough Endoplasmic Reticulum (rER): Synthesise/produce the protein.
- Mitochondria: Produce ATP required for protein synthesis and transport.
- Golgi apparatus: Packages, modifies, and adds carbohydrates to proteins (forms glycoproteins).
- Vesicles / rER: Transport the proteins through the cytoplasm.
- Cell-surface membrane: (Vesicles) fuse with the membrane to release proteins via exocytosis.
💡 Key Knowledge
This is the classic "protein journey" through a eukaryotic cell. You must link the structural organelle directly to its precise dynamic function in secretory pathways.
🧠 Exam Technique
This is a "4 max" question. You need to write coherent, point-to-point statements connecting organelle to function. Do not waste time writing about transcription or translation, as the question explicitly forbids it.
❌ Common Errors
Students often lose marks by stating mitochondria "make energy" (violating the conservation of energy principle—they produce ATP) or by confusing the roles of vesicles and the Golgi apparatus.
Missing Nucleus in Transmission Electron Micrograph
Suggest why a nucleus is not visible in Figure 3. [1 mark]
✅ Correct Answer
The cell was sectioned/sliced, so the nucleus is located in another part (another slice) of the cell, OR the nucleus was not stained.
🧠 Exam Technique
For 1-mark "suggest why" questions regarding 2D micrographs, always consider tissue preparation artifacts: thin sectioning means structures present in 3D might be entirely missed in a 2D plane.
Organelle Identification
Name the organelles labelled S and T in Figure 3. [1 mark]
✅ Correct Answers
- Organelle S: Vacuole
- Organelle T: Chloroplast
❌ Common Errors
Reject answers like "thylakoid" or "granum" for organelle T—these are internal structures within the chloroplast, not the organelle itself. Ensure correct biological spelling.
Microscopy Comparison
Give one advantage of viewing a biological specimen using a transmission electron microscope (TEM) compared with using a scanning electron microscope (SEM). [1 mark]
✅ Correct Answer
Higher resolution OR ability to view internal structures (such as chloroplast grana or mitochondrial cristae).
💡 Key Knowledge
TEM transmits electrons through a very thin specimen, giving 2D internal details at a higher resolution than SEM, which bounces electrons off the surface to generate 3D topography images.
Multi-Step Calculation & Standard Form
Calculate the number of cells in the upper surface of the leaf. Give the answer in standard form. Assume that all these cells are identical in size. [2 marks]
📐 Step-by-Step Calculation
- Convert units to match: Area of cell U = 150 um². Total area = 70.65 cm². Convert cm² to um².
1 cm = 10,000 um (10⁴ um).
1 cm² = (10⁴)² um² = 10⁸ um². - Calculate total leaf surface area in um²:
70.65 cm² × 10⁸ = 7,065,000,000 um² (or 7.065 × 10⁹ um²). - Divide total area by single cell area:
7,065,000,000 um² ÷ 150 um² = 47,100,000 cells. - Convert to standard form:
4.71 × 10⁷
❌ Common Calculation Traps
The most frequent error is squaring the conversion factor incorrectly. Remember that converting cm to um is multiplying by 10⁴, but converting cm² to um² requires multiplying by ( 10⁴ )² = 10⁸ !
Topics
Biology · Practical skills · 3.2 Cells · Data analysis
Question and mark scheme from the AQA AS Level Biology examination, Paper 1, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.