AQA AS Level Biology Paper 1, November 2020: Question 5
9 marks · Medium difficulty · Short Answer
Describe and explain lung ventilation, identify tissue structures, explain staining choice, and evaluate statistical conclusions regarding asthma risk factors.
Practise this questionQuestion
Question text
05.1 Describe and explain the mechanism that causes lungs to fill with air.
[3 marks]
A scientist observed sections of lung tissue using an optical microscope.
Figure 5 shows one of these sections.
K is an air-filled tube and L is a blood vessel.
This figure has been removed due to third-party copyright restrictions.
05.2 Identify the structures labelled K and L.
[1 mark]
K
L
05.3 Two solutions often used to stain tissues are haematoxylin solution and iodine
solution.
• Haematoxylin solution stains DNA a blue colour.
• Iodine solution stains starch a blue-black colour.
The scientist used haematoxylin solution and not iodine solution to stain the
lung tissue.
Suggest why.
[2 marks]
05.4 Scientists investigated the link between the lung disease asthma and three
risk factors. They studied a large number of people. They recorded if the people had
asthma and if they:
• were obese
• burned wood indoors as a fuel
• lived in a house with a cat or dog.
The scientists used a statistical test to calculate the probability of the link between
asthma and each risk factor being due to chance.
Table 2 shows their results.
Table 2
Probability
Risk Factor
(P value)
Obese < 0.001
Burned wood indoors = 0.06
Lived with a cat or dog < 0.05
A student who looked at these results concluded that all three risk factors are linked
*11* with asthma. Evaluate this conclusion.
[3 marks]
Mark scheme
Show the mark scheme
Question Marking Guidance Mark Comments
05.1 1. Diaphragm (muscle) contracts and external 3 1. Ignore ribs move up
intercostal muscles contract; and out
2. (Causes volume increase and) pressure
decrease;
3. Air moves down a pressure gradient
3. Ignore along
OR
Air enters from higher atmospheric pressure;
05.2 K = Bronchiole and 1 Reject capillary
L = artery/arteriole/vein/venule; Ignore pulmonary
1. This/animal/lung tissue does not contain starch;
05.3 2 1. Accept cell(s) for
‘tissue’
2. (Makes) nucleus visible;
OR
Nucleus contains DNA;
05.4 In support 3 Reject ‘results are
significant’
1. (Link/risk with asthma and) living with cat or
dog is (statistically) significant;
2. (Link with) obesity is most/highly significant;
Accept ‘due to
Not supported chance’ for ‘not
3. (Link/risk with asthma and) burned wood significant’ and
(indoors) is not (statistically) significant; converse
TOTAL 9
How to answer it
Gas Exchange Mechanics, Tissue Histology, and Statistical Evaluation
What this question tests
This study guide covers key AS Level Biology concepts including the mechanics of pulmonary ventilation (inspiration), identification of histological structures in lung tissue, understanding the specific staining properties of biological stains (haematoxylin vs. iodine), and the statistical evaluation of probability (P values) in relation to risk factors and disease.
Mechanism of Pulmonary Ventilation (Inspiration)
Describe and explain the mechanism that causes lungs to fill with air. (3 marks)
✅ Correct Answer (Mark Scheme)
- Diaphragm muscle contracts (and flattens) AND external intercostal muscles contract (ribs move up and out).
- Causes an increase in thoracic volume and a corresponding decrease in thoracic/pulmonary pressure.
- Air moves down a pressure gradient from higher atmospheric pressure outside to lower pressure inside the lungs.
💡 Key Knowledge
Inspiration is an active process requiring ATP. Contraction of the diaphragm and external intercostal muscles alters the volume of the thorax, establishing the pressure gradient necessary for bulk flow of air.
🧠 Exam Technique
A complete 3-mark answer must follow the causal chain: Muscle contraction → Volume increase → Pressure decrease → Air movement down pressure gradient. Never state that "ribs move up and out" as a substitute for muscle contraction unless linked correctly.
❌ Common Errors
- Forgetting to state that both the diaphragm and external intercostal muscles contract.
- Stating that air is "pulled" or "sucked" in rather than explaining movement down a pressure gradient.
- Confusing inspiration with expiration mechanics.
Histological Identification
Identify the structures labelled K and L. (1 mark)
✅ Correct Answer (Mark Scheme)
- K: Bronchiole
- L: Artery / arteriole / vein / venule (Blood vessel types)
💡 Key Knowledge
Bronchioles are small airways characterized by walls of smooth muscle and a lack of cartilage plates/goblet cells in terminal regions. Blood vessels (arteries, veins, capillaries) are identified by their lumen shape and endothelial lining.
❌ Common Errors
- Labelling structure L as a "capillary" (rejected by examiners as capillaries do not appear with distinct muscular wall structures at this magnification scale).
- Adding qualifying terms like "pulmonary" which are unnecessary and can invalidate the answer if incorrect.
Biological Stains and Microscopy
The scientist used haematoxylin solution and not iodine solution to stain the lung tissue. Suggest why. (2 marks)
✅ Correct Answer (Mark Scheme)
- Animal / lung tissue does not contain starch (so iodine would serve no purpose).
- Haematoxylin stains DNA / makes the nucleus visible (allowing cellular structures to be observed).
💡 Key Knowledge
Different stains bind to specific cellular macromolecules. Iodine stains starch (found in plant storage tissues, but absent in mammals), whereas haematoxylin is a basic dye that binds to acidic nucleic acids (DNA/RNA) in cell nuclei, giving them a characteristic blue/purple appearance.
🧠 Exam Technique
This is a "two-part why" question. Make sure you address why iodine was omitted (no starch in animals) and why haematoxylin was chosen (stains nuclei/DNA).
Evaluating Statistical Data and Probability (P values)
A student who looked at these results concluded that all three risk factors are linked with asthma. Evaluate this conclusion. (3 marks)
✅ Correct Answer (Mark Scheme)
- In support: Living with a cat or dog has a statistically significant link (P < 0.05).
- In support: Obesity has a highly significant link (P < 0.001).
- Not supported: Burning wood indoors is not statistically significant (P = 0.06, which is greater than 0.05).
💡 Key Knowledge
In biology, a probability threshold of P < 0.05 is standard for statistical significance. If P < 0.05, there is less than a 5% probability that the observed result is due to chance, meaning we reject the null hypothesis. If P ≥ 0.05 (like P = 0.06), the result is not statistically significant.
🧠 Exam Technique
When asked to "Evaluate" a statement containing multiple parts, you must provide a balanced argument addressing what data supports the claim and what data refutes it. Always explicitly cite the P values from the table to back up your reasoning.
❌ Common Errors
- Stating "results are significant" without specifying which risk factor you are referring to.
- Failing to recognise that P = 0.06 is greater than 0.05 and therefore not significant.
Topics
Biology · 3.3 Organisms exchange substances with their environment
Question and mark scheme from the AQA AS Level Biology examination, Paper 1, November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.