AQA GCSE Biology Biology Paper 1 (Foundation), June 2022: Question 5

14 marks · Low Demand difficulty · Short Answer

Complete the word equation for photosynthesis, identify plant transport structures, calculate relative transpiration rates, and explain adaptations of plants and animals for survival.

Practise this question

Question

Question 5 consists of eight parts spanning plant biology, transport, and adaptations. Part 05.1 asks to complete the word equation for photosynthesis using given words. Part 05.2 requires completing sentences about xylem, stomata, and phloem using words from a box. A table follows showing the rate of transpiration in arbitrary units for four plant species: A (310), B (254), C (87), and D (192). Part 05.3 asks to calculate how many times greater species A's transpiration rate is than species B's, to 2 significant figures. Parts 05.4 and 05.5 are tick-box questions about factors affecting transpiration rate. Part 05.6 asks to select which species from the table is most likely to live in a desert. Part 05.7 shows an image of a gorse plant with sharp spines and asks how spines help it survive. Part 05.8 shows pictures of a hornet and a hornet moth, explaining hornets sting but hornet moths do not, asking why animals avoid eating the hornet moth.
Question text

05.1 Plants take up water from the soil through their roots.

Some of the water is used for photosynthesis.

Complete the word equation for photosynthesis.

Choose answers from the box.

[2 marks]

fat glucose nitrogen oxygen protein

carbon dioxide + water → +

05.2 Water and dissolved substances are transported through a plant.

Complete the sentences.

Choose answers from the box.

[3 marks]

epidermis guard cells palisade cells

phloem stomata xylem

Water moves from the roots to the leaves in the .

Water is lost from leaves through pores called .

Dissolved sugars are transported in the .

Table 3 shows the rate of transpiration in four different plant species.

Table 3

Rate of transpiration in

Plant species

*19* arbitrary units

A 310

B 254

C 87

D 192

05.3 Calculate how many times greater the rate of transpiration of species A is than

the rate of transpiration of species B.

Give your answer to 2 significant figures.

[3 marks]

Number of times greater (2 significant figures) =21

05.4 Which factor could cause species A to have a higher rate of transpiration than

species B?

[1 mark]

Tick ( ) one box.

Each flower of species A has more petals.

Each leaf of species A has more stomata.

Each plant of species A has shorter roots.

05.5 Which environmental change would cause an increase in the rate of transpiration?

[1 mark]

Tick ( ) one box.

Decreased light intensity

Decreased wind speed

Increased humidity

Increased temperature

05.6 Which plant species in Table 3 is most likely to live in a dry desert?

[1 mark]

Tick ( ) one box.

A B 22 C D

05.7 Some plants have adaptations that help them survive.

Figure 6 shows part of a gorse plant.

Figure 6

How will the sharp spines help the gorse plant survive?

[1 mark]

05.8 Animals also have adaptations to help them survive.

Figure 7 shows two insects.

Figure 7

Hornet Hornet Moth

Hornets are insects that sting other animals and cause pain.

*22* Hornet moths do not sting other animals.

Explain why animals avoid eating the hornet moth.

[2 marks]

Mark scheme

Show the mark scheme Mark scheme for Question 5 lists answers and marking criteria: 05.1 awards 1 mark for oxygen and 1 mark for glucose. 05.2 awards 1 mark each for xylem, stomata, and phloem in order. 05.3 awards 1 mark for 310 / 254, 1 mark for 1.22..., and 1 mark for 1.2. 05.4 awards 1 mark for 'each leaf of species A has more stomata'. 05.5 awards 1 mark for 'increased temperature'. 05.6 awards 1 mark for C. 05.7 awards 1 mark for stopping the plant being eaten, damaged, or reducing water loss. 05.8 awards 1 mark for looking like a hornet and 1 mark for animals avoiding the risk of being stung or pain. Total marks: 14.

Question 5

AO /

Question Answers Extra information Mark

Spec. Ref.

05.1 in either order AO1

4.4.1.1

oxygen allow O2 1

glucose allow C6H12O6 1

AO /

Spec. Ref.

05.2 must be in this order AO1

xylem 1 4.1.1.3

4.2.3.1

stomata 1 4.2.3.2

phloem 1

AO /

Spec. Ref.

05.3 310 AO2

254 1 4.2.3.2

1.22047… 1

1.2 allow an answer of 0.82 if 1

numerator and denominator

reversed

AO /

Spec. Ref.

05.4 each leaf of species A has more 1 AO3

stomata 4.2.3.2

AO /

Spec. Ref.

05.5 increased temperature 1 AO1

4.2.3.2

AO /

Spec. Ref.

05.6 C 1 AO2

4.2.3.2

AO /

Spec. Ref.

05.7 (spines) stop the plant being 1 AO2

eaten 4.3.3.2

or

(spines) prevent animals allow any named animal

damaging the plant

allow to reduce water loss

AO /

Spec. Ref.

05.8 it looks like the hornet allow animals think it is a hornet 1 AO3

(so) animals avoid the risk of allow (so) animals avoid the risk 1 AO2

being stung of pain

4.3.3.2

Total Question 5 14

How to answer it

Plant Transport, Transpiration & Survival Adaptations

📋 What this question tests

This question assesses core recall, data analysis, and application across key plant and animal biology topics:

  • Photosynthesis: The word equation and chemical products.
  • Plant Transport Systems: Functions of xylem, phloem, and leaf stomata.
  • Transpiration: Factors affecting the rate of water loss and interpreting experimental data.
  • Mathematical Skills: Calculating comparative factors and rounding to significant figures.
  • Adaptations: Mechanical plant defences (spines) and Batesian mimicry in animals (hornet moth).
Question 05.1

Word Equation for Photosynthesis

Completing products from a given word bank [2 marks]

✅ Correct Answer

carbon dioxide + water → glucose + oxygen

(Products can be written in either order. Chemical formulas C₆H₁₂O₆ and O₂ are also credited.)

💡 Key Knowledge

  • Reactants: Taken in from the air (carbon dioxide) and soil (water).
  • Energy source: Light absorbed by chlorophyll in chloroplasts.
  • Main product: Glucose (sugar used for respiration or stored as starch).
  • By-product: Oxygen gas released via stomata.
Mark Breakdown: 1 mark for glucose , 1 mark for oxygen .
Question 05.2

Plant Transport Tissues & Structures

Completing transport statements from a word bank [3 marks]

✅ Correct Answer

  • Water moves from the roots to the leaves in the xylem.
  • Water is lost from leaves through pores called stomata.
  • Dissolved sugars are transported in the phloem.

🧠 Exam Technique: Memory Hooks

  • Xylem: Carries water and mineral ions upwards in the transpiration stream (dead, hollow tubes).
  • Phloem: Carries food (dissolved sugars/sucrose) by translocation (living cells). Sound link: Phloem = Food.
  • Stomata: Small openings controlled by guard cells for gas exchange and transpiration.

❌ Common Errors

Mixing up stomata and guard cells. Stomata are the actual pores; guard cells are the cells flanking the pore that control its opening and closing.

Mark Breakdown: 1 mark for each correctly identified term in the exact order requested.
Question 05.3

Calculation: Comparing Rates of Transpiration

Calculating how many times greater species A is than B [3 marks]

📐 Step-by-Step Calculation

  1. Identify values from Table 3:
    Species A = 310
    Species B = 254
  2. Set up the division (A ÷ B):
    310 ÷ 254 = 1.220472...
  3. Round to 2 significant figures:
    First two significant figures: 1 and 2.
    Look at the 3rd figure (2) → round down.
    Final answer = 1.2

❌ Common Calculation Traps

  • Inverting the division: Doing 254 ÷ 310 gives 0.82 (the mark scheme gives partial credit, but you lose the full mark). Always do "target ÷ comparison".
  • Incorrect rounding: Writing 1.22 (3 s.f.) or 1 (1 s.f.) loses the final mark. Always re-read the required significant figures!
Mark Breakdown: [1] Correct fraction setup (310 / 254) • [1] Unrounded answer (1.22047...) • [1] Correctly rounded to 2 s.f. (1.2).
Question 05.4

Structural Factors Affecting Transpiration

Selecting the factor that causes species A to have higher transpiration [1 mark]

✅ Correct Answer

☑ Each leaf of species A has more stomata.

💡 Key Knowledge

Water vapour diffuses out of the leaf mainly through open stomata. More stomata mean a greater total surface area available for diffusion, leading to higher rates of transpiration.

Mark Breakdown: 1 mark for ticking the middle box only.
Question 05.5

Environmental Factors and Transpiration

Selecting the environmental change that increases transpiration [1 mark]

✅ Correct Answer

☑ Increased temperature

💡 Why Higher Temperature Increases Transpiration

  • Water particles have more kinetic energy, meaning they evaporate and diffuse faster out of the stomata.
  • Why other options are wrong: Decreased light closes stomata; decreased wind speed allows humid air to accumulate, reducing the concentration gradient; increased humidity decreases the concentration gradient.
Mark Breakdown: 1 mark for ticking the bottom box only.
Question 05.6

Adapting to Arid Environments

Identifying the plant species most likely to live in a dry desert [1 mark]

✅ Correct Answer

☑ C

🧠 Exam Technique: Interpreting Data

Deserts have very low water availability. A desert plant must conserve water and minimise water loss. Species C has the lowest transpiration rate (87 arbitrary units) in Table 3, making it the best adapted to conserve water.

Mark Breakdown: 1 mark for ticking box C only.
Question 05.7

Plant Adaptations: Spines

Function of sharp spines in gorse survival [1 mark]

✅ Correct Answer

Any one from:

  • Stops the plant being eaten / grazed (by herbivores).
  • Prevents animals from damaging the plant.
  • Reduces water loss (allowable as spines have reduced surface area compared to broad leaves).

🧠 Exam Technique

State a clear biological purpose: say "stops animals eating it" rather than just "protects the plant". Be specific about what it is being protected from.

Mark Breakdown: 1 mark for clear reference to deterring herbivores/damage or reducing transpiration.
Question 05.8

Animal Adaptations: Batesian Mimicry

Explaining why predators avoid the harmless hornet moth [2 marks]

✅ Correct Answer

  • Mark 1: It looks like / mimics a hornet (predators mistake it for a hornet).
  • Mark 2: Animals avoid it to avoid the risk of being stung / experiencing pain.

💡 Key Knowledge: Mimicry

The hornet moth displays Batesian mimicry: a harmless species evolves warning coloration resembling a harmful species (the hornet). Predators have learned from past experience that hornets sting, so they avoid anything that shares the hornet's yellow-and-black appearance.

❌ Common Errors

Saying "the moth stings the predator". The question clearly stated that hornet moths do not sting. The survival benefit comes entirely from deception!

Mark Breakdown: 1 mark for visual mimicry / resemblance • 1 mark for predator avoidance of pain/sting.

Topics

Biology · B2: Organisation · B4: Bioenergetics · B7: Ecology

Question and mark scheme from the AQA GCSE Biology examination, Biology Paper 1 (Foundation), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.