AQA GCSE Biology Biology Paper 1 (Foundation), June 2022: Question 6

13 marks · Standard Demand difficulty · Extended Answer

Calculate surface area to volume ratio, analyze diffusion factors, and explain how the human breathing system is adapted for gas exchange.

Practise this question

Question

Question 6 begins with Table 4 comparing four jellyfish labeled A to D in order of increasing size, listing their surface area in mm², volume in mm³, and surface area to volume ratio. Sub-question 6.1 asks to calculate value X for jellyfish A (surface area 3600, volume 1200, ratio X:1). Sub-question 6.2 asks for the relationship between jellyfish size and surface area to volume ratio. Sub-question 6.3 asks for another substance entering cells by diffusion other than oxygen. Sub-question 6.4 asks for two factors affecting the rate of diffusion of oxygen into a jellyfish. Sub-question 6.5 asks for the gas exchange organ in fish. Sub-question 6.6 features Figure 8 showing human lungs and a magnified alveolus surrounded by a blood vessel with red blood cells, asking to explain how the human breathing system is adapted to maximise the rate of gas exchange for 6 marks.
Question text

06 Table 4 shows information about four jellyfish.

The jellyfish are listed in order of increasing size.

Table 4

Size of jellyfish Surface area Volume Surface area to

Jellyfish 2 3

in mm in mm volume ratio

A Smallest 3 600 1 200 X:1

B 50 000 25 000 2:1

C 1 800 000 6 000 000 0.3:1

D Largest 7 500 000 125 000 000 0.06:1

06.1 Calculate value X in Table 4.

[2 marks]

X =

06.2 Describe the relationship between the size of a jellyfish and its surface area to

volume ratio.

Use Table 4.

[1 mark]

The jellyfish in Table 4 take oxygen into their cells by diffusion.

06.3 Name one other substance that enters cells by diffusion.

Do not refer to oxygen in your answer.

*24* [1 mark]

06.4 Suggest two factors that affect the rate of diffusion of oxygen into a jellyfish.

[2 marks]

06.5 Some organisms take in oxygen using a respiratory system.

In humans, gas exchange takes place in the lungs.

Name the organs where gas exchange takes place in fish.

[1 mark]

06.6 Figure 8 shows parts of the human breathing system.

Figure 8

Explain how the human breathing system is adapted to maximise the rate of

gas exchange.

[6 marks]

Mark scheme

Show the mark scheme Mark scheme for Question 6 lists the scoring criteria: 06.1 awards 1 mark for 3600 / 1200 and 1 mark for 3; 06.2 awards 1 mark for stating as size increases, surface area to volume ratio decreases; 06.3 awards 1 mark for carbon dioxide, glucose/sugar, water, or ions/minerals/salts; 06.4 awards 2 marks for any two of concentration gradient, surface area, thickness of exchange surface, blood/circulatory system, or temperature; 06.5 awards 1 mark for gills; 06.6 provides a 3-level descriptor table (1-2, 3-4, 5-6 marks) with indicative content covering large number of alveoli/large surface area, thin walls/short diffusion distance, good blood supply/capillaries, and ventilation to maintain steep concentration gradients.

Question 6

AO /

Question Answers Extra information Mark

Spec. Ref.

if no answer in answer space

06.1 allow answer in Table 4 AO2

View with 4.1.3.1

Table 4 3 600 1

1 200

3 allow 3:1 1

do not accept if a unit is given

AO /

Spec. Ref.

06.2 as size increases, (surface area allow as one increases, the 1 AO3

to volume) ratio decreases other decreases 4.1.3.1

allow as size decreases,

(surface area to volume) ratio

increases

AO /

Spec. Ref.

allow a correct chemical formula

06.3 any one from: 1 AO1

4.1.3.2

• carbon dioxide 4.1.3.1

• glucose / sugar

• water

• ions / minerals / salts allow named ions

allow other correct substances

eg amino acids / fatty acids /

glycerol

ignore nutrients / food

AO /

Spec. Ref.

06.4 any two from: 2 AO1

4.1.3.1

• concentration gradient allow description

• surface area allow surface area : volume ratio

ignore size unqualified

• thickness of exchange allow thickness of skin

surface

• presence of a blood /

circulatory system

• temperature

AO /

Spec. Ref.

06.5 gills 1 AO1

4.1.3.1

AO /

Question Answers Mark

Spec. Ref.

06.6 Level 3: Relevant points (reasons / causes) are identified, given in 5−6 AO2

detail and logically linked to form a clear account.

Level 2: Relevant points (reasons / causes) are identified, and 3−4 AO1

there are attempts at logical linking. The resulting account is not

fully clear.

Level 1: Points are identified and stated simply, but their relevance 1−2 AO1

is not clear and there is no attempt at logical linking.

4.1.3.1

No relevant content 0 4.2.2.2

Indicative content

• large number of alveoli

• large surface / area

• alveolus and blood vessel / capillary are in close proximity

• alveoli / capillaries have thin walls or alveoli / capillaries have

walls that are one cell thick

• to reduce diffusion distance

• has a good blood supply or has a capillary network

• to maintain concentration gradient 19

• to remove oxygen quickly or to deliver carbon dioxide quickly

• (capillary network) increases surface area (for diffusion)

• lungs are ventilated or lungs continually move air in and out

• (ventilation) brings in oxygen or removes carbon dioxide

• to maintain concentration gradient

Types of adaptation of the lungs are required for Level 3.

Total Question 6 13

How to answer it

Surface Area to Volume Ratio and Gas Exchange Systems

📌 What this question tests

This question assesses core principles of transport and exchange systems from AQA GCSE Biology (Topic 4.1.3 Transport in cells & Topic 4.2.2 Animal tissues, organs and organ systems):

  • Calculating and interpreting surface area to volume (SA:V) ratios.
  • Understanding factors that determine the rate of diffusion into organisms.
  • Identifying specialized exchange surfaces across organisms (fish gills).
  • Structuring a multi-point explanation of how the human respiratory system (alveoli) is adapted for efficient gas exchange.

Question 06.1

Calculate value X in Table 4 [2 marks]

📐 Step-by-Step Calculation

  1. Identify the formula:
    SA:V ratio = Surface Area ÷ Volume
  2. Extract data from Table 4 for Jellyfish A:
    Surface area = 3 600 mm²
    Volume = 1 200 mm³
  3. Divide to find X (relative to 1):
    X = 3 600 ÷ 1 200 = 3
Mark breakdown: [1 mark] for correct substitution ( 3 600 / 1 200 ), [1 mark] for final answer 3 (or ratio 3:1 ).

❌ Common Errors

  • Adding units: Ratios are unitless comparisons. The mark scheme explicitly states: do not accept if a unit is given (e.g. "3 mm²" scores 0 for the answer mark).
  • Inverting the fraction: Dividing volume by surface area (1 200 ÷ 3 600 = 0.33) rather than surface area by volume.

Question 06.2

Relationship between jellyfish size and SA:V ratio [1 mark]

✅ Correct Answer

As the size of the jellyfish increases, its surface area to volume ratio decreases.

(Alternative accepted: As size decreases, the ratio increases.)

🧠 Exam Technique: Describing Trends

Always use a comparative statement structure: "As [variable X] increases, [variable Y] decreases". Avoid just quoting single figures without describing the overall pattern.

Question 06.3

Other substances entering cells by diffusion [1 mark]

✅ Acceptable Answers (Any One)

  • Carbon dioxide (CO₂)
  • Glucose / sugar
  • Water (H₂O)
  • Ions / mineral salts (e.g. sodium ions, potassium ions)
  • Amino acids / fatty acids / glycerol

❌ Pitfalls & Exclusions

  • Oxygen: The question explicitly says "Do not refer to oxygen in your answer". Mentioning oxygen gains zero.
  • Vague food terms: Words like "nutrients" or "food" are ignored because they are too general. Name the specific molecule.

Question 06.4

Factors affecting the rate of diffusion into a jellyfish [2 marks]

💡 Key Knowledge: Factors Affecting Diffusion

According to Fick's Law and core diffusion principles, the rate is determined by:

  • Concentration gradient (difference in oxygen levels inside vs outside)
  • Surface area (or surface area to volume ratio)
  • Diffusion distance / membrane thickness (thickness of the jellyfish body wall/skin)
  • Temperature (higher temperature = more kinetic energy)

❌ Common Errors

  • Writing simply "size" unqualified. "Size" is not a factor—it must be qualified as surface area, thickness of surface, or surface area to volume ratio.

Question 06.5

Gas exchange organ in fish [1 mark]

✅ Correct Answer

Gills

💡 Context Note

Fish pump water through their mouth and over their gills, where oxygen diffuses into the blood capillaries within gill filaments/lamellae.

Question 06.6

Explain how the human breathing system is adapted to maximise the rate of gas exchange [6 marks]

🧠 How to Score Level 3 (5–6 Marks)

This is a 6-mark banded response. To reach Level 3, you must link each structural feature (cause) directly to its physiological reason/effect on gas exchange. Aim to cover all three fundamental principles of exchange surfaces:

✅ Full-Mark Model Explanation (Feature + Reason)

  • Large Surface Area:
    The lungs contain millions of tiny alveoli, which provide an enormous surface area for faster diffusion of oxygen and carbon dioxide.
  • Short Diffusion Pathway:
    The walls of both the alveoli and the capillaries are extremely thin (one cell thick) and in close contact, meaning gases only diffuse across a tiny distance.
  • Steep Concentration Gradient (Blood Flow):
    There is an extensive network of capillaries (rich blood supply) with constantly flowing blood. This rapidly removes oxygen and continuously delivers carbon dioxide, maintaining a steep concentration gradient.
  • Steep Concentration Gradient (Ventilation):
    Breathing (ventilation) continually brings in fresh air rich in oxygen and expels air with high carbon dioxide levels, maintaining the steep gradient.

❌ Mistakes That Cap Responses at Level 1 or 2

  • "Alveoli have thin cell walls": Animal cells do NOT have cell walls! Say "walls that are one cell thick" or "thin walls". Saying "thin cell wall" loses credit.
  • Listing features without explanations: Saying "it has alveoli, thin walls, and capillaries" without explaining why each feature speeds up diffusion will restrict you to Level 1 (1–2 marks).
  • Confusing respiration and breathing: Ventilation/breathing moves air into the lungs; respiration is the chemical process releasing energy inside mitochondria.

Topics

Biology · B1: Cell Biology · B2: Organisation

Question and mark scheme from the AQA GCSE Biology examination, Biology Paper 1 (Foundation), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.