AQA GCSE Biology Biology Paper 1 (Foundation), June 2022: Question 6
13 marks · Standard Demand difficulty · Extended Answer
Calculate surface area to volume ratio, analyze diffusion factors, and explain how the human breathing system is adapted for gas exchange.
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Question text
06 Table 4 shows information about four jellyfish.
The jellyfish are listed in order of increasing size.
Table 4
Size of jellyfish Surface area Volume Surface area to
Jellyfish 2 3
in mm in mm volume ratio
A Smallest 3 600 1 200 X:1
B 50 000 25 000 2:1
C 1 800 000 6 000 000 0.3:1
D Largest 7 500 000 125 000 000 0.06:1
06.1 Calculate value X in Table 4.
[2 marks]
X =
06.2 Describe the relationship between the size of a jellyfish and its surface area to
volume ratio.
Use Table 4.
[1 mark]
The jellyfish in Table 4 take oxygen into their cells by diffusion.
06.3 Name one other substance that enters cells by diffusion.
Do not refer to oxygen in your answer.
*24* [1 mark]
06.4 Suggest two factors that affect the rate of diffusion of oxygen into a jellyfish.
[2 marks]
06.5 Some organisms take in oxygen using a respiratory system.
In humans, gas exchange takes place in the lungs.
Name the organs where gas exchange takes place in fish.
[1 mark]
06.6 Figure 8 shows parts of the human breathing system.
Figure 8
Explain how the human breathing system is adapted to maximise the rate of
gas exchange.
[6 marks]
Mark scheme
Show the mark scheme
Question 6
AO /
Question Answers Extra information Mark
Spec. Ref.
if no answer in answer space
06.1 allow answer in Table 4 AO2
View with 4.1.3.1
Table 4 3 600 1
1 200
3 allow 3:1 1
do not accept if a unit is given
AO /
Spec. Ref.
06.2 as size increases, (surface area allow as one increases, the 1 AO3
to volume) ratio decreases other decreases 4.1.3.1
allow as size decreases,
(surface area to volume) ratio
increases
AO /
Spec. Ref.
allow a correct chemical formula
06.3 any one from: 1 AO1
4.1.3.2
• carbon dioxide 4.1.3.1
• glucose / sugar
• water
• ions / minerals / salts allow named ions
allow other correct substances
eg amino acids / fatty acids /
glycerol
ignore nutrients / food
AO /
Spec. Ref.
06.4 any two from: 2 AO1
4.1.3.1
• concentration gradient allow description
• surface area allow surface area : volume ratio
ignore size unqualified
• thickness of exchange allow thickness of skin
surface
• presence of a blood /
circulatory system
• temperature
AO /
Spec. Ref.
06.5 gills 1 AO1
4.1.3.1
AO /
Question Answers Mark
Spec. Ref.
06.6 Level 3: Relevant points (reasons / causes) are identified, given in 5−6 AO2
detail and logically linked to form a clear account.
Level 2: Relevant points (reasons / causes) are identified, and 3−4 AO1
there are attempts at logical linking. The resulting account is not
fully clear.
Level 1: Points are identified and stated simply, but their relevance 1−2 AO1
is not clear and there is no attempt at logical linking.
4.1.3.1
No relevant content 0 4.2.2.2
Indicative content
• large number of alveoli
• large surface / area
• alveolus and blood vessel / capillary are in close proximity
• alveoli / capillaries have thin walls or alveoli / capillaries have
walls that are one cell thick
• to reduce diffusion distance
• has a good blood supply or has a capillary network
• to maintain concentration gradient 19
• to remove oxygen quickly or to deliver carbon dioxide quickly
• (capillary network) increases surface area (for diffusion)
• lungs are ventilated or lungs continually move air in and out
• (ventilation) brings in oxygen or removes carbon dioxide
• to maintain concentration gradient
Types of adaptation of the lungs are required for Level 3.
Total Question 6 13
How to answer it
Surface Area to Volume Ratio and Gas Exchange Systems
This question assesses core principles of transport and exchange systems from AQA GCSE Biology (Topic 4.1.3 Transport in cells & Topic 4.2.2 Animal tissues, organs and organ systems):
- Calculating and interpreting surface area to volume (SA:V) ratios.
- Understanding factors that determine the rate of diffusion into organisms.
- Identifying specialized exchange surfaces across organisms (fish gills).
- Structuring a multi-point explanation of how the human respiratory system (alveoli) is adapted for efficient gas exchange.
Question 06.1
Calculate value X in Table 4 [2 marks]
📐 Step-by-Step Calculation
- Identify the formula:
SA:V ratio = Surface Area ÷ Volume - Extract data from Table 4 for Jellyfish A:
Surface area = 3 600 mm²
Volume = 1 200 mm³ - Divide to find X (relative to 1):
X = 3 600 ÷ 1 200 = 3
❌ Common Errors
- Adding units: Ratios are unitless comparisons. The mark scheme explicitly states: do not accept if a unit is given (e.g. "3 mm²" scores 0 for the answer mark).
- Inverting the fraction: Dividing volume by surface area (1 200 ÷ 3 600 = 0.33) rather than surface area by volume.
Question 06.2
Relationship between jellyfish size and SA:V ratio [1 mark]
✅ Correct Answer
As the size of the jellyfish increases, its surface area to volume ratio decreases.
(Alternative accepted: As size decreases, the ratio increases.)
🧠 Exam Technique: Describing Trends
Always use a comparative statement structure: "As [variable X] increases, [variable Y] decreases". Avoid just quoting single figures without describing the overall pattern.
Question 06.3
Other substances entering cells by diffusion [1 mark]
✅ Acceptable Answers (Any One)
- Carbon dioxide (CO₂)
- Glucose / sugar
- Water (H₂O)
- Ions / mineral salts (e.g. sodium ions, potassium ions)
- Amino acids / fatty acids / glycerol
❌ Pitfalls & Exclusions
- Oxygen: The question explicitly says "Do not refer to oxygen in your answer". Mentioning oxygen gains zero.
- Vague food terms: Words like "nutrients" or "food" are ignored because they are too general. Name the specific molecule.
Question 06.4
Factors affecting the rate of diffusion into a jellyfish [2 marks]
💡 Key Knowledge: Factors Affecting Diffusion
According to Fick's Law and core diffusion principles, the rate is determined by:
- Concentration gradient (difference in oxygen levels inside vs outside)
- Surface area (or surface area to volume ratio)
- Diffusion distance / membrane thickness (thickness of the jellyfish body wall/skin)
- Temperature (higher temperature = more kinetic energy)
❌ Common Errors
- Writing simply "size" unqualified. "Size" is not a factor—it must be qualified as surface area, thickness of surface, or surface area to volume ratio.
Question 06.5
Gas exchange organ in fish [1 mark]
✅ Correct Answer
Gills
💡 Context Note
Fish pump water through their mouth and over their gills, where oxygen diffuses into the blood capillaries within gill filaments/lamellae.
Question 06.6
Explain how the human breathing system is adapted to maximise the rate of gas exchange [6 marks]
🧠 How to Score Level 3 (5–6 Marks)
This is a 6-mark banded response. To reach Level 3, you must link each structural feature (cause) directly to its physiological reason/effect on gas exchange. Aim to cover all three fundamental principles of exchange surfaces:
✅ Full-Mark Model Explanation (Feature + Reason)
- Large Surface Area:
The lungs contain millions of tiny alveoli, which provide an enormous surface area for faster diffusion of oxygen and carbon dioxide. - Short Diffusion Pathway:
The walls of both the alveoli and the capillaries are extremely thin (one cell thick) and in close contact, meaning gases only diffuse across a tiny distance. - Steep Concentration Gradient (Blood Flow):
There is an extensive network of capillaries (rich blood supply) with constantly flowing blood. This rapidly removes oxygen and continuously delivers carbon dioxide, maintaining a steep concentration gradient. - Steep Concentration Gradient (Ventilation):
Breathing (ventilation) continually brings in fresh air rich in oxygen and expels air with high carbon dioxide levels, maintaining the steep gradient.
❌ Mistakes That Cap Responses at Level 1 or 2
- "Alveoli have thin cell walls": Animal cells do NOT have cell walls! Say "walls that are one cell thick" or "thin walls". Saying "thin cell wall" loses credit.
- Listing features without explanations: Saying "it has alveoli, thin walls, and capillaries" without explaining why each feature speeds up diffusion will restrict you to Level 1 (1–2 marks).
- Confusing respiration and breathing: Ventilation/breathing moves air into the lungs; respiration is the chemical process releasing energy inside mitochondria.
Topics
Biology · B1: Cell Biology · B2: Organisation
Question and mark scheme from the AQA GCSE Biology examination, Biology Paper 1 (Foundation), June 2022. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.