AQA GCSE Biology Biology Paper 2 (Foundation), June 2023: Question 5

10 marks · Low Demand difficulty · Short Answer

Analyze an investigation into the effect of temperature on the decay of milk using pH changes, and calculate the comparative rates of digestion.

Practise this question

Question

Question 5 shows an investigation into the decay of milk. Figure 8 illustrates a beaker with fresh milk, a thermometer, and a pH sensor connected to a pH meter. Figure 9 is a line graph plotting the pH of milk against time in days (from 0 to 7 days) at 5 °C, 20 °C, and 30 °C. Question parts ask to identify decomposers, variables, methods to maintain temperature, products of fat digestion, interpret the graph plateau, explain temperature effects on digestion rate, and calculate the rate of pH decrease and relative rate comparison.
Question text

05 Bacteria are one type of organism that cause decay.

05.1 Which other type of organism causes decay?

[1 mark]

Tick ( ) one box.

Fungi

Plants

Viruses

Students investigated the effect of temperature on the decay of milk.

The decay was caused by bacteria in the milk.

Figure 8 shows the apparatus used.

Figure 8

This is the method used.

1. Set up the apparatus as shown in Figure 8 with the milk at 20°C.

2. Record the pH each day for 7 days.

3. Repeat with more samples of milk at 5°C and at 30°C.

05.2 What was the dependent variable in the investigation?

[1 mark]

Tick ( ) one box.

The pH of the milk

The type of milk

The volume of the milk

05.3 How could the students keep the milk at 30°C for 7 days?

[1 mark]

Tick ( ) one box.

Put a lid on the beaker.

Put the beaker in a water bath.

Stir the milk continuously.

Wrap cloth around the beaker.

05.4 As the milk decays, the bacteria digest fats in the milk.

What type of acid is produced by digestion of fats in the milk?

[1 mark]

Tick ( ) one box.

Amino acid

Fatty acid

Hydrochloric acid 24

Figure 9 shows the results.

Figure 9

05.5 Why did the pH not fall below pH 4.5 at 20°C?

[1 mark]

Tick ( ) one box.

All the fat had been digested.

The reaction was too fast.

The temperature was too low. 25

The digestion of fat was fastest at 30°C and slowest at 5°C.

05.6 Give one reason why the rate of digestion was faster at 30°C than at 5°C.

[1 mark]

05.7 Calculate the rate of digestion at 30 °C from day 2 to day 3.

Complete the following calculation.

Use data from Figure 9.

[2 marks]

At 30°C, the pH at day 2 =

At 30°C, the pH at day 3 =

Therefore the fall in pH at 30°C from day 2 to day 3 = pH units/day

05.8 The rate of digestion at 5°C from day 2 to day 3 is 0.1 pH units/day.

How many times faster is the rate of digestion at 30°C than the rate of digestion at

5°C from day 2 to day 3?

[2 marks]

Use your answer to Question 05.7.

Rate at 30°C is times faster

Mark scheme

Show the mark scheme Mark scheme for Question 5 with answers for parts 05.1 through 05.8. Answers include: 05.1 'fungi' (1 mark); 05.2 'the pH of the milk' (1 mark); 05.3 'put the beaker in a water bath' (1 mark); 05.4 'fatty acid' (1 mark); 05.5 'all the fat had been digested' (1 mark); 05.6 more kinetic energy, higher enzyme activity, or bacteria dividing faster (1 mark); 05.7 readings 6.0 and 4.7, yielding a fall of 1.3 pH units/day (2 marks); 05.8 calculation of 1.3 / 0.1 = 13 times faster (2 marks). Total marks: 10.

Question 5

AO /

Question Answers Extra information Mark

Spec Ref.

05.1 fungi 1 AO1

4.7.2.3

AO /

Spec Ref.

05.2 the pH of the milk 1 AO2

4.7.2.3

RPA10

AO /

Spec Ref.

05.3 put the beaker in a water bath 1 AO2

4.7.2.3

RPA10

AO /

Spec Ref.

05.4 fatty acid 1 AO1

4.2.2.1

4.7.2.3

RPA10

AO /

Spec Ref.

05.5 all the fat had been digested 1 AO2

4.7.2.3

4.2.2.1

RPA10

AO /

Spec Ref.

05.6 any one from: allow converse if clearly 1 AO2

describing 5 °C 4.7.2.3

4.1.1.6

• (there is) more (kinetic) allow particles move faster 4.2.2.1

energy allow more collisions between RPA10

particles

• enzyme activity is higher allow enzymes work faster

ignore enzymes work better

• bacteria / microorganisms are allow number of bacteria /

dividing / reproducing faster 15

microorganisms increasing

faster

allow more bacteria /

microorganisms

ignore bacteria /

microorganisms grow faster

ignore it is warmer

AO /

Spec Ref.

05.7 (30 °C, 2 days) 6(.0) allow a tolerance of ±½ small 1 AO2

and square 4.7.2.3

(30 °C, 3 days) 4.7 4.2.2.1

RPA10

(fall) 1.3 (pH units/day) allow −1.3 (pH units/day) 1

allow correct answer using

student’s incorrect readings in

the range of 5.95 to 6.05 and /

or 4.65 to 4.75

AO /

Spec Ref.

05.8 1.3 allow ecf from answer in 1 AO2

0.1 question 05.7 4.7.2.3

4.2.2.1

13 do not accept if a unit is given 1 RPA10

Total Question 5 10

How to answer it

Investigating Decay: Temperature, Lipids & Reaction Rates

🔍 What this question tests

This question covers Required Practical 10 (Decay) and key concepts in ecology and digestion:

  • Identifying organisms of decay (fungi and bacteria).
  • Scientific variables: identifying the dependent variable in a rate experiment.
  • Experimental control: maintaining constant temperature over several days.
  • Digestion of lipids: products of fat digestion (fatty acids and glycerol).
  • Graph interpretation: understanding plateau regions and enzyme kinetics.
  • Data calculation: calculating fall in pH per day and comparing reaction rates as ratios.
Part 05.1 • 1 Mark

Decomposing Organisms

Which other type of organism causes decay?

✅ Correct Answer

Fungi

💡 Key Knowledge

The two primary groups of decomposers are bacteria and fungi. They break down dead organic matter by secreting digestive enzymes externally and absorbing the broken-down soluble nutrients.

❌ Common Errors

  • Selecting Viruses: Viruses are non-cellular entities that replicate inside living host cells; they do not cause decomposition.
  • Selecting Plants: Plants are primary producers (autotrophs), not decomposers.
Mark allocation: 1 mark for ticking 'Fungi'.
Part 05.2 • 1 Mark

Identifying Variables

What was the dependent variable in the investigation?

✅ Correct Answer

The pH of the milk

🧠 Exam Technique

  • Independent variable: What you intentionally change (here, temperature: 5 °C, 20 °C, 30 °C).
  • Dependent variable: What you measure (here, the pH of the milk).
  • Control variables: What you keep the same (volume of milk, type of milk).

❌ Common Errors

Confusing control variables (like volume of milk) with the dependent variable (the actual reading you record every day).

Mark allocation: 1 mark for ticking 'The pH of the milk'.
Part 05.3 • 1 Mark

Experimental Control

How could the students keep the milk at 30 °C for 7 days?

✅ Correct Answer

Put the beaker in a water bath

💡 Key Knowledge

A thermostatically controlled water bath (or incubator) supplies continuous heat to keep a steady temperature higher than room temperature over long periods.

❌ Common Errors

  • "Wrap cloth around the beaker": Insulation slows down heat loss, but it cannot warm milk up or maintain 30 °C above ambient temperature for 7 days.
  • "Put a lid on": This reduces evaporation, not temperature regulation.
Mark allocation: 1 mark for ticking 'Put the beaker in a water bath'.
Part 05.4 • 1 Mark

Lipid Digestion Products

What type of acid is produced by digestion of fats in the milk?

✅ Correct Answer

Fatty acid

💡 Key Knowledge

Lipids (fats and oils) are broken down by lipase enzymes into:

Lipid → Glycerol + Fatty Acids

The accumulation of free fatty acids causes the pH to decrease (become more acidic).

❌ Common Errors

Selecting Amino acid (the product of protein digestion by proteases) or Hydrochloric acid (produced in the stomach, not by lipase digestion).

Mark allocation: 1 mark for ticking 'Fatty acid'.
Part 05.5 • 1 Mark

Interpreting Plateaus

Why did the pH not fall below pH 4.5 at 20 °C?

✅ Correct Answer

All the fat had been digested.

💡 Key Knowledge

Notice on Figure 9 that both the 20 °C and 30 °C curves flatten out at exactly pH 4.5. Once all substrate (fat/lipid) has been completely hydrolysed, no more fatty acids can form, so the pH stops falling.

❌ Common Errors

Thinking the reaction stopped because it was "too cold" or "too fast". The plateau level is identical at 20 °C and 30 °C because the starting quantity of fat was identical in both samples.

Mark allocation: 1 mark for ticking 'All the fat had been digested.'
Part 05.6 • 1 Mark

Explaining Reaction Rates

Give one reason why the rate of digestion was faster at 30 °C than at 5 °C.

✅ Correct Answers (any one)

  • (There is) more kinetic energy / particles move faster / more frequent collisions.
  • Enzyme activity is higher / enzymes work faster.
  • Bacteria / microorganisms divide / reproduce faster (or there are more bacteria).

🧠 Exam Technique

You can also give the converse for 5 °C (e.g., "at 5 °C particles have less kinetic energy"). Always use precise scientific vocabulary: mention kinetic energy or enzymes.

❌ Common Errors

  • Writing just "it is warmer" — this is an observation, not an explanation!
  • Writing "enzymes work better" — too vague; write faster or have higher activity.
  • Writing "bacteria grow faster" — mark scheme specifies reproduction/division or number of bacteria.
Mark allocation: 1 mark for any valid biological/kinetic reason.
Part 05.7 • 2 Marks

Graph Reading & Rate Calculation

Calculate the rate of digestion at 30 °C from day 2 to day 3.

📐 Step-by-Step Calculation

  1. Read day 2 at 30 °C: Follow Day 2 vertically to the 30 °C curve:
    pH = 6.0 (tolerance ± 0.05).
  2. Read day 3 at 30 °C: Follow Day 3 vertically to the 30 °C curve:
    pH = 4.7 (tolerance ± 0.05).
  3. Calculate the fall per day:
    Rate = (pH at day 2) − (pH at day 3) / 1 day
    Rate = 6.0 − 4.7 = 1.3 pH units/day

🧠 Graph Reading Tip

Check the grid scale carefully before reading:

  • 1 major grid division (10 small squares) = 0.5 pH units.
  • Each small vertical square = 0.05 pH units.
  • At day 3, the cross is 4 small squares above 4.5:
    4.5 + (4 × 0.05) = 4.70.
Mark allocation:
• Mark 1: Both readings correct: 6(.0) and 4.7 (within ± ½ small square).
• Mark 2: 1.3 (or −1.3) pH units/day. (Allow ecf if readings were in range 5.95–6.05 and 4.65–4.75).
Part 05.8 • 2 Marks

Comparing Rates (Ratio Calculation)

How many times faster is the rate of digestion at 30 °C than at 5 °C from day 2 to day 3?

📐 Step-by-Step Calculation

  1. Identify the two rates:
    Rate at 30 °C = 1.3 pH units/day (from 05.7)
    Rate at 5 °C = 0.1 pH units/day (given in question)
  2. Set up the division:
    Ratio = 1.3 / 0.1
  3. Calculate the final value:
    Rate is 13 times faster.

❌ Common Errors

  • Adding a unit: The question asks "how many times faster". This is a pure ratio. The mark scheme explicitly states: "do not accept if a unit is given" (e.g. writing "13 pH/day" will lose Mark 2!).
  • Subtracting instead of dividing (e.g. calculating 1.3 − 0.1 = 1.2).
Mark allocation:
• Mark 1: Working showing 1.3 / 0.1 (or ecf using answer from 05.7 divided by 0.1).
• Mark 2: 13 (must NOT have units attached).

Topics

Biology · Required Practicals · B2: Organisation · B7: Ecology · Required Practicals

Question and mark scheme from the AQA GCSE Biology examination, Biology Paper 2 (Foundation), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.