AQA GCSE Biology Biology Paper 2 (Higher), June 2023: Question 8

10 marks · Standard Demand difficulty · Short Answer

Order stages of meiosis, determine chromosome counts and explain their significance, describe genetic variation in meiosis, and identify DNA components from a diagram.

Practise this question

Question

Figure 13 displays six circular stages of meiosis labelled A through F showing chromosome condensation, pairing, division into two cells, and final division into four gametes. Questions 08.1 to 08.4 ask for the correct sequence of stages, the number of chromosomes at start and end, an explanation of the importance of chromosome number reduction, and how meiosis creates genetic variation. Figure 14 illustrates a DNA double helix segment showing alternating sugar-phosphate backbones and complementary base pairs labelled T-A, T-A, C-G, G-C, A-T, and T-A. Questions 08.5 and 08.6 ask what substance type A, C, G, and T represent and the total number of nucleotides shown in the diagram.
Question text

08 Figure 13 shows six stages in the process of meiosis.

Figure 13

08.1 In Figure 13, A is the first stage and F is the final stage.

Stages B to E are not in the correct order.

Give the correct order of stages A to F.

[1 mark]

A → → → → → F

At the end of meiosis the number of chromosomes is different from the number of

chromosomes at the start of meiosis.

08.2 Give the number of chromosomes in one cell in Figure 13:

• at the start of meiosis

• at the end of meiosis.

[2 marks]

Start

End

08.3 Explain why the change in the number of chromosomes is important.

[3 marks]

08.4 Meiosis produces cells that are genetically different.

Describe how meiosis produces cells that are genetically different.

[2 marks]

Chromosomes contain DNA.

Figure 14 shows part of a DNA molecule.

*35* Figure 14

08.5 What type of substances are labelled A, C, G and T in Figure 14?

[1 mark]

08.6 DNA is made of nucleotides.

How many nucleotides are shown in Figure 14?

[1 mark]

Mark scheme

Show the mark scheme Mark scheme table for Question 8 listing answers: 08.1 requires sequence E -> D -> C -> B (1 mark). 08.2 awards 1 mark for start: 16 (or 8 pairs) and 1 mark for end: 8 (half of the start value). 08.3 awards 3 marks for: forms gametes, gametes fuse/fertilise, keeping chromosome number constant/preventing doubling. 08.4 awards 2 marks for: random chromosome from each pair moves to one end of the cell or into each new cell/gamete. 08.5 accepts 'base(s)' or organic/nitrogenous base(s) (1 mark). 08.6 accepts 12 / twelve or 6 pairs (1 mark). Total: 10 marks.

Question 8

AO /

Question Answers Extra information Mark

Spec Ref.

08.1 (A) → E → D → C → B → (F) must be in this order 1 AO3

4.6.1.2

4.1.2.2

AO /

Spec Ref.

08.2 (start) 16 allow 8 pairs 1 AO3

(end) 8 the answer must be half the 1 AO2

value of the number at the start 4.6.1.2

AO /

Spec Ref.

08.3 (meiosis) forms gametes allow (meiosis) forms sex cells 1 AO1

allow (meiosis) forms eggs and 4.6.1.2

sperm

(two gametes) fuse / fertilise 1

(so) keeps chromosome number 1

constant (from generation to

generation)

or

(so) prevents doubling /

increase in chromosome

number (in each generation)

or

(so) gives normal / correct allow gives correct chromosome

chromosome number (for number (for offspring)

embryo / new cell)

AO /

Spec Ref.

08.4 random chromosome from ignore half the chromosomes 1 AO1

each pair (of chromosomes) ignore half the DNA 4.6.1.2

allow other processes for creating

variation

ignore mutation

moves to one end of the cell 1

or

goes into each new cell or

gamete

AO /

Spec Ref.

08.5 base(s) allow organic / nitrogenous base(s) 1 AO1

4.6.1.5

ignore adenine / cytosine / guanine

/ thymine

AO /

Spec Ref.

08.6 12 / twelve allow 6 pairs or six pairs 1 AO3

4.6.1.5

Total Question 8 10

How to answer it

Meiosis, Gamete Formation & DNA Structure

📋 What this question tests

This question assesses your understanding of cell division by meiosis and the molecular structure of DNA (AQA Biology Specification 4.6.1.2 and 4.6.1.5):

  • Tracing the sequence of cellular events during two consecutive divisions of meiosis.
  • Counting chromosomes in diagrammatic cells and calculating the reduction from diploid to haploid.
  • Explaining the biological importance of halving chromosome numbers for sexual reproduction and fertilization.
  • Describing how meiosis generates genetic variation (independent assortment/random distribution of chromosomes).
  • Identifying the components of a nucleotide: bases (A, C, G, T), pentose sugars, and phosphate groups.
Part 08.1 — Ordering the Stages of Meiosis [1 Mark]

Ordering the Stages of Cell Division

AO3 (Analysis of visual scientific data)

✅ Correct Answer

A → E → D → C → B → F

1 Mark: All stages in precisely this sequence. No partial credit.

💡 Stage-by-Stage Breakdown

  • A: Interphase / uncoiled chromatin copies itself.
  • E: Chromosomes condense and pair up (8 pairs visible).
  • D: Homologous pairs separate and pull apart to opposite poles (First division).
  • C: Cell divides into 2 cells (end of first division).
  • B: Chromatids pull apart in both cells (Second division).
  • F: 4 genetically distinct haploid gametes form.
Part 08.2 — Chromosome Counts [2 Marks]

Number of Chromosomes at Start vs. End

AO3 & AO2 (Observation and application)

✅ Correct Answer

  • Start: 16 (allow 8 pairs) [1 mark]
  • End: 8 [1 mark]
Note: The end answer must be exactly half of the start value provided.

📐 How to Count Correctly

  1. Look at image E: the label explicitly states "One pair of chromosomes" for two adjacent X-shaped chromosomes.
  2. Count all the chromosome pairs in cell E: there are 8 pairs = 16 chromosomes.
  3. Meiosis halves the number: 16 ÷ 2 = 8 chromosomes in each gamete at stage F.

❌ Common Errors

  • Writing 46 and 23 — this is true for human cells, but the question asks about Figure 13!
  • Counting each chromatid arm individually and writing 32.
Part 08.3 — Importance of Halving [3 Marks]

Why Halving the Chromosome Number Matters

AO1 (Recall and scientific explanation)

✅ 3-Point Model Answer

  1. Meiosis produces gametes (sex cells / sperm and egg cells). [1 mark]
  2. So that when two gametes fuse / fertilise... [1 mark]
  3. The full, normal chromosome number is restored / kept constant from generation to generation (prevents doubling every generation). [1 mark]

🧠 Exam Technique: Chain of Cause & Effect

Always state the biological consequence:

Halved (n) + Halved (n) ⟶ Fertilisation ⟶ Normal Diploid (2n)

If gametes remained diploid (16), fertilisation would create 32, then 64, doubling each generation indefinitely!

❌ Common Errors

  • Saying "so the baby has 46 chromosomes" (Figure 13 has a base number of 16, not 46).
  • Failing to mention fertilisation or fusion of gametes.
Part 08.4 — Genetic Variation in Meiosis [2 Marks]

How Meiosis Produces Genetically Different Cells

AO1 (Mechanism of genetic variation)

✅ Marking Points

  • A random chromosome from each homologous pair is chosen / separated... [1 mark]
  • ...and moves to each pole / goes into each new cell or gamete (independent assortment). [1 mark]

💡 What the Examiner Looks For

Examiners accept either a description of:

  • Independent assortment: Random alignment and separation of maternal and paternal chromosomes.
  • Crossing over: Swapping of alleles between non-sister chromatids in homologous pairs.

❌ Ignored & Rejected Answers

  • Do not write "mutation" — this is not the standard mechanism during normal meiosis.
  • Vague phrases like "they get half the DNA" or "half the chromosomes go in" get 0 marks. You must mention random distribution or selection from pairs.
Parts 08.5 & 08.6 — DNA Structure [2 Marks]

Interpreting the DNA Diagram (Figure 14)

AO1 & AO3 (Molecular recognition and counting)

✅ Part 08.5 Answer [1 Mark]

Base(s)

Also allowed: Organic base(s), nitrogenous base(s).

❌ Ignore: Naming the letters individually (e.g. "adenine, cytosine, guanine, thymine") because the question asks for the type of substance.

✅ Part 08.6 Answer [1 Mark]

12 (twelve nucleotides)

Also allowed: 6 pairs / six pairs.

💡 Anatomy of a Nucleotide

Each individual nucleotide consists of 3 parts:

  • One circular phosphate group
  • One pentagonal deoxyribose sugar
  • One rectangular base (A, T, C, or G)

In Figure 14, there are 6 rungs. Each rung contains 2 bases paired together. Therefore: 6 rungs × 2 nucleotides per rung = 12 nucleotides.

❌ Common Errors in 08.6

  • Writing "6" instead of 12 (counting base pairs instead of single nucleotides without adding the word "pairs").
  • Writing "24" or "4" by guessing based on base types.

Topics

Biology · B1: Cell Biology · B6: Inheritance, Variation and Evolution

Question and mark scheme from the AQA GCSE Biology examination, Biology Paper 2 (Higher), June 2023. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.