AQA GCSE Biology Biology Paper 2 (Foundation), June 2025: Question 5

8 marks · Low Demand difficulty · Short Answer

Identify DNA bases, calculate the number of amino acids coded by a DNA sequence, identify mutations, and calculate the rate of increase of MRSA cases from a graph.

Practise this question

Question

Question 5 shows Figure 8, a schematic of a DNA molecule highlighting complementary base pairs (A-T, G-C). Part 05.1 asks to identify what A, C, G, and T are called. Part 05.2 asks how many amino acids are coded for by a given 9-base sequence. Part 05.3 asks for the term for a change in DNA sequence. Figure 9 is a line graph showing MRSA cases per million people from 1991 to 2011, rising from 1 in 1993 to 40 in 2005. Part 05.4 asks to calculate the mean rate of increase between 1993 and 2005. Part 05.5 asks what describes bacteria not killed by antibiotics, and 05.6 asks to suggest a reason for the decrease in cases after 2006.
Question text

05 Figure 8 shows part of a DNA molecule.

Figure 8

The letters A, C, G and T in Figure 8 represent four different compounds.

05.1 What are A, C, G and T called?

[1 mark]

Tick ( ) one box.

Bases

Fatty acids

Sugars

05.2 The section of DNA shown in Figure 8 contains the following sequence of

these compounds:

A G T A A G T A C

A sequence of three compounds codes for one amino acid.

How many amino acids would this section of DNA code for?

[1 mark]

05.3 Sometimes a change occurs in the sequence of the compounds A, C, G and T in

the DNA.

What name is given to a change in DNA?

[1 mark]

Tick ( ) one box.

Differentiation

Mutation

Natural selection 24

Changes in the DNA of a bacterial pathogen can produce new strains of

the pathogen.

Many people have been infected with a bacterial pathogen called MRSA.

Figure 9 shows how many cases of MRSA occurred in one country from

1993 to 2011.

Figure 9

05.4 Calculate the mean rate of increase in MRSA cases per year in the 12 years from

1993 to 2005.

[3 marks]

Mean rate of increase = 25 cases per million people per year

05.5 Most antibiotics will not kill MRSA bacteria.

*24Which word describes bacteria that are* not killed by antibiotics?

[1 mark]

Tick ( ) one box.

Immune

Powerful

Resistant

05.6 Figure 9 shows that the number of cases of MRSA decreased after 2006.

Suggest one reason for this decrease.

[1 mark]

Mark scheme

Show the mark scheme Mark scheme for Question 5 lists the correct answers: 05.1: bases (1 mark); 05.2: 3 / three (1 mark); 05.3: mutation (1 mark); 05.4: graph figures 40 and 1 (1 mark), correct equation (40-1)/12 (1 mark), correct answer 3.25 (1 mark); 05.5: resistant (1 mark); 05.6: any one from discovery of a new antibiotic/treatment, vaccination, isolation of patients, better education, better hygiene (1 mark). Total 8 marks.

Question 5

AO /

Question Answers Extra information Mark

Spec. Ref.

05.1 bases 1 AO1

4.6.1.5

AO /

Spec. Ref.

05.2 3 / three 1 AO2

4.6.1.5

AO /

Spec. Ref.

05.3 mutation 1 AO1

4.6.2.1

AO /

Spec. Ref.

05.4 figures from graph AO2

40 and 1 1 4.6.3.7

correct equation

40 – 1 allow 39 1

12 12

correct answer

3.25 (cases per million people 1

per year)

AO /

Spec. Ref.

05.5 resistant 1 AO1

4.6.3.7

AO /

Spec. Ref.

05.6 any one from: 1 AO2

4.6.3.7

• discovery of a new antibiotic /

drug / treatment

• vaccination

• isolation of patients allow social distancing

• better / improved education allow increased awareness of

about MRSA MRSA

• better hygiene allow examples such as more /

better hand washing (in

hospitals)

Total Question 5 8

How to answer it

DNA Structure, Triplet Code & MRSA Resistance

📋 What this question tests

This question assesses your understanding of DNA structure (nucleotide bases and complementary pairing), protein synthesis basics (triplet codes for amino acids), genetic mutations, and how mutations can lead to antibiotic resistance in bacteria (MRSA). It also tests quantitative graph-reading skills by calculating the mean rate of increase from a line graph.

Question 05.1 • 1 Mark

Identifying Parts of a DNA Molecule

A, C, G and T in Figure 8

✅ Correct Answer

Tick: Bases

💡 Key Knowledge

  • DNA is a polymer made of repeating units called nucleotides.
  • Each nucleotide contains a sugar molecule, a phosphate group, and one of four bases: Adenine (A), Cytosine (C), Guanine (G), Thymine (T).
  • Complementary base pairing: A pairs with T, and C pairs with G.

❌ Common Errors

Confusing bases with the sugars (deoxyribose pentagons) or phosphates (circles) that form the DNA backbone.

Mark allocation: 1 mark for correctly ticking the 'Bases' checkbox.
Question 05.2 • 1 Mark

The Triplet Code and Amino Acids

Calculating Amino Acids Coded by AGTAAGTAC

✅ Correct Answer

3 (or three)

📐 Working Out

  1. Count the total number of bases: A-G-T-A-A-G-T-A-C = 9 bases.
  2. A sequence of 3 bases codes for 1 amino acid.
  3. Divide total bases by 3: 9 ÷ 3 = 3 amino acids.
  4. Grouped into triplets: [AGT] [AAG] [TAC] = 3 triplets.

🧠 Exam Technique

Always chunk long sequences into groups of three with a pencil on your exam paper to avoid miscounting.

Mark allocation: 1 mark for the correct number (3).
Question 05.3 • 1 Mark

Changes in the DNA Sequence

Terminology for genetic changes

✅ Correct Answer

Tick: Mutation

💡 Key Knowledge

  • Mutation: A random change in the DNA base sequence of an organism.
  • Differentiation: The process by which a cell changes to become specialised.
  • Natural selection: Survival and reproduction of organisms better adapted to their environment.

❌ Common Errors

Ticking 'Natural selection'. A mutation is the event that alters the DNA sequence; natural selection is the mechanism that drives evolution over generations.

Mark allocation: 1 mark for correctly ticking 'Mutation'.
Question 05.4 • 3 Marks

Calculating Mean Rate of Increase

Data interpretation from Figure 9 (1993 to 2005)

📐 Step-by-Step Calculation

  1. Step 1: Read values from the graph (Mark 1)
    In 1993: 1 case per million people
    In 2005: 40 cases per million people
  2. Step 2: Set up rate equation (Mark 2)
    Change in cases = 40 − 1 = 39
    Time period = 12 years
    Rate = 39 ÷ 12
  3. Step 3: Calculate the final value (Mark 3)
    39 ÷ 12 = 3.25 cases per million people per year

✅ Final Value

3.25

(Units already provided on the answer line: cases per million people per year)

❌ Common Errors & Traps

  • Misreading the starting value: Thinking 1993 starts at 0. Looking closely at the y-axis, 1 small square = 1 unit; 1993 is at exactly 1.
  • Dividing by the wrong year span: The question gives the time period directly (12 years), so do not guess or divide by 13.
  • Rounding incorrectly: Leaving it as a fraction without completing the division to a decimal.
Mark breakdown: 1 mark for identifying 40 and 1; 1 mark for (40 - 1) / 12 (or 39/12); 1 mark for 3.25.
Question 05.5 • 1 Mark

Antibiotic Resistance Terminology

Describing bacteria not killed by antibiotics

✅ Correct Answer

Tick: Resistant

💡 Key Knowledge

  • Bacteria become resistant to antibiotics via mutations.
  • Humans/animals become immune to pathogens via antibodies and memory white blood cells.
  • Golden rule: Bacteria are NEVER "immune" to antibiotics.

❌ Major Misconception

Selecting "Immune". This is one of the most common mistakes in GCSE Biology. Pathogens become resistant; hosts become immune.

Mark allocation: 1 mark for ticking 'Resistant'.
Question 05.6 • 1 Mark

Reasons for Decrease in MRSA Cases

Suggesting reasons for decline after 2006

✅ Accepted Answers (Any ONE)

  • Better hygiene (e.g. more hand-washing in hospitals / alcohol gel dispensers)
  • Isolation of patients infected with MRSA
  • Discovery of a new antibiotic / drug / treatment
  • Better / improved education or awareness about MRSA
  • Vaccination / social distancing

🧠 Exam Technique

  • Always be specific: write "better hand washing by doctors/nurses in hospitals" rather than just "cleaner".
  • You only need one reason—giving multiple conflicting reasons risks losing the mark if one is incorrect.

❌ Answers Not Awarded

  • "People became immune to MRSA" (MRSA does not readily produce permanent population immunity).
  • "Used more of the same antibiotic" (this would actually select for more resistance!).
Mark allocation: 1 mark for any valid biological or procedural reason matching the mark scheme.

Topics

Biology · B6: Inheritance, Variation and Evolution

Question and mark scheme from the AQA GCSE Biology examination, Biology Paper 2 (Foundation), June 2025. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.