AQA GCSE Chemistry Chemistry Paper 1 (Higher), November 2020: Question 7
12 marks · High Demand difficulty · Short Answer
Analyze reaction profiles, fuel cells, particle models, and calculate the volume of hydrogen gas required for a fuel cell car journey.
Practise this questionQuestion
Question text
07 The reaction between hydrogen and oxygen releases energy.
07.1 A student drew a reaction profile for the reaction between hydrogen and oxygen.
Figure 3 shows the student’s reaction profile.
Figure 3
The student made two errors when drawing the reaction profile.
Describe the two errors.
[2 marks]
07.2 The reaction between hydrogen and oxygen in a hydrogen fuel cell is used
to produce electricity.
Hydrogen fuel cells and rechargeable cells are used to power some cars.
Give two advantages of using hydrogen fuel cells instead of using
rechargeable cells to power cars.
[2 marks]
*18* 1
07.3 Reactions occur at the positive electrode and at the negative electrode in a
hydrogen fuel cell.
Write a half equation for one of these reactions.
[1 mark]
07.4 The three states of matter can be represented by a simple particle model.
Figure 4 shows a simple particle model for hydrogen gas.
Figure 4
Give two limitations of this simple particle model for hydrogen gas.
[2 marks]
07.5 The hydrogen gas needed to power a car for 400 km would occupy a large volume.
Suggest one way that this volume can be reduced.
[1 mark]
07.6 The energy needed for a car powered by a hydrogen fuel cell to travel 100 km is
58 megajoules (MJ).
The energy released when 1 mole of hydrogen gas reacts with oxygen is 290 kJ
The volume of 1 mole of a gas at room temperature and pressure is 24 dm3
Calculate the volume of hydrogen gas at room temperature and pressure needed for
the car to travel 100 km
[4 marks]
Volume of hydrogen gas = dm3
Mark scheme
Show the mark scheme
Question 7
AO /
Question Answers Extra information Mark
Spec. Ref.
07.1 the activation energy should be ignore description of where the 1 AO3
from the reactants (line to the activation energy is on the 4.5.1.2
peak) diagram
the products (line) should be allow the product (line) is above 1
below the reactants (line) the reactants (line)
or
the products should have less allow the products have more
energy than the reactants energy than the reactants
allow the profile shows an
endothermic reaction
ignore the arrow for the overall
energy change should point
downwards
07.2 any two from: allow converse arguments for a 2 AO1
(hydrogen fuel cells) rechargeable cell 4.5.2.2
• no toxic chemicals to dispose
of at the end of the cell’s life
• take less time to refuel (than
to recharge rechargeable
cells)
• travel further before refuelling allow has a greater range
(than before recharging
rechargeable cells)
• no loss of efficiency (over allow does not lose capacity /
time) range in cold weather
Question 7 continued
AO /
Spec. Ref.
07.3 allow multiples 1 AO1
4.5.2.2
any one from:
21 • H → 2 H+ + 2 e-
2 allow H - 2 e- → 2 H+
• O + 4 H+ + 4 e- → 2 H O
22 allow H + 2 OH- - 2 e- → 2 H O
• H + 2 OH- → 2 H O + 2 e-
• O + 2 H O + 4 e- → 4 OH-
07.4 any two from: 2 AO1
• hydrogen is not shown as H2 / 4.2.2.1
molecules
• particles are shown as
spheres
• particles are shown as solid
• does not show the (weak)
forces (between particles)
• does not show the movement
/ speed (of particles)
• is only two-dimensional
07.5 any one from: 1 AO3
• under (higher) pressure allow increase concentration 4.2.2.1
• cool allow condense 4.5.2.2
• absorb / adsorb in a solid
allow store as a liquid / solid
allow develop more efficient
engines
Question 7 continued
AO /
Spec. Ref.
07.6 AO2
(58 MJ =) 58 000 kJ allow (58 MJ =) 58 000 000 J 1 4.3.2.1
or and 4.3.5
(290 kJ =) 0.290 MJ (290 kJ =) 290 000 J 4.5.2.2
58000 58 allow correct use of an 1
(moles = or = ) 200
290 0.290 incorrectly converted or
unconverted value of energy
(volume =) 200 × 24 allow correct use of an 1
incorrectly calculated number of
moles of hydrogen
= 4800 (dm3) 1
alternative approach:
(58 MJ =) 58 000 kJ (1)
(energy released per dm3 =
290 3
=) 12.08333 (kJ/dm ) (1)
58000
(volume =) (1) allow correct use of an
12.08333
incorrectly converted or
unconverted value of energy
allow correct use of an
incorrectly calculated energy
released per dm3
= 4800 (dm3) (1)
Total 12
How to answer it
Hydrogen Fuel Cells, Energy Profiles & Molar Volume
What this question tests
This question assesses fundamental concepts across Energy Changes, Chemical Cells, and Quantitative Chemistry:
- Reaction Profiles: Interpreting exothermic profiles, correct reference points for activation energy ( E a), and relative energy levels of reactants vs products.
- Fuel Cells vs Batteries: Evaluating the practical and environmental advantages of hydrogen fuel cells over rechargeable batteries.
- Half-Equations: Recalling electrode reactions occurring within alkaline or acid fuel cells.
- Particle Model Limitations: Critiquing simple sphere models representing diatomic gases.
- Gas Volumes & Mole Calculations: Multi-step unit conversion ( MJ to kJ ), reacting energy stoichiometry, and using molar gas volume ( 24 dm³ per mole).
Reaction Profile Errors
Identifying graphical mistakes for an exothermic reaction
✅ Correct Answers (Choose 2)
- Error 1: The activation energy arrow must start from the reactants line (up to the peak), not from the products level.
- Error 2: The reaction is exothermic (releases energy), so the products line (2H₂O) should be lower than the reactants line (2H₂ + O₂).
💡 Key Knowledge
- The prompt states: "The reaction releases energy". This explicitly defines it as exothermic.
- In an exothermic reaction: Energyproducts < Energyreactants.
- Activation energy ( E a) is always measured from the reactants' energy level to the highest point of the curve.
🧠 Exam Technique
Read the question stem carefully! It told you energy was released. Students who missed this tried to describe it as an endothermic reaction profile rather than pointing out that the diagram wrongly showed an endothermic profile.
❌ Common Errors
- Saying the activation energy arrow is "pointing the wrong way" without stating it starts from the wrong horizontal baseline.
- Stating "the overall energy change arrow is upside down" — the mark scheme explicitly ignores the direction of this arrow.
Advantages of Hydrogen Fuel Cells
Comparing hydrogen fuel cells to rechargeable lithium-ion cells
✅ Correct Answers (Any 2)
- Takes less time to refuel (compared to long recharging times for batteries).
- Can travel further before refuelling / greater driving range.
- No toxic chemicals to dispose of at the end of the cell's lifespan.
- No loss of efficiency / does not lose capacity or range over time or in cold weather.
🧠 Exam Technique
- Comparative words are essential: say "faster refuelling" rather than just "it refuels".
- Converse arguments about rechargeable batteries are allowed (e.g. "batteries take hours to recharge" or "batteries contain toxic metals that are hard to recycle").
❌ Common Errors
- "Produces only water / no pollutants": While true for the fuel cell in operation, rechargeable electric cars also produce zero exhaust emissions, so this is not a comparative advantage over rechargeable cells.
- Vague statements like "cheaper" or "greener" without qualified scientific explanation.
Electrode Half-Equations
Writing ionic half-equations in a fuel cell
✅ Correct Half-Equations (Give Any 1)
Acidic electrolyte:
- Negative electrode (oxidation): H₂ → 2H⁺ + 2e⁻
- Positive electrode (reduction): O₂ + 4H⁺ + 4e⁻ → 2H₂O
Alkaline electrolyte:
- Negative electrode: H₂ + 2OH⁻ → 2H₂O + 2e⁻
- Positive electrode: O₂ + 2H₂O + 4e⁻ → 4OH⁻
💡 Key Knowledge
The simplest and most reliable equation to memorise for AQA GCSE is the oxidation of hydrogen at the negative electrode:
H₂ → 2H⁺ + 2e⁻
Remember: Oxidation is loss of electrons (OIL), occurring at the negative terminal of a fuel cell.
❌ Common Errors
- Writing the overall equation ( 2H₂ + O₂ → 2H₂O ) instead of a half-equation involving electrons ( e⁻ ).
- Unbalanced charges or incorrect electron placement (e.g. writing + 2e⁻ on the reactant side for hydrogen oxidation).
Particle Model Limitations
Critiquing the simple sphere model of hydrogen gas
✅ Correct Answers (Any 2)
- Hydrogen is not shown as diatomic molecules / not shown as H₂ .
- Particles are shown as solid spheres (atoms/molecules are mostly empty space).
- Does not show the (weak intermolecular) forces between particles.
- Does not show the movement or speed of the particles.
- Model is only two-dimensional (2D), whereas real gas exists in three dimensions (3D).
🧠 Exam Technique
Whenever asked for limitations of the particle model in chemistry, standard specification recall points apply: no forces shown, particles shown as inelastic solid spheres, and 2D limitation. For hydrogen specifically, pointing out that it is diatomic ( H₂ ) rather than individual single atoms is a top-level response.
❌ Common Errors
- Writing "particles are too far apart" (gas particles really are far apart).
- Vague points like "not drawn to scale" without specifying what is inaccurate.
Reducing Gas Volume
Storage methods for hydrogen fuel
✅ Correct Answers (Any 1)
- Store under higher pressure (compress the gas).
- Cool the gas / condense into a liquid / store at low temperature.
- Absorb / adsorb into a solid material (e.g. metal hydride matrix).
💡 Key Knowledge
Gases have massive amounts of empty space between particles. According to Boyle's and Charles's Gas Laws:
- Increasing pressure forces gas particles closer together ( Volume ∝ 1/Pressure ).
- Decreasing temperature reduces kinetic energy, causing contraction or condensation into a dense liquid.
Calculation: Gas Volume Required
Multi-step quantitative calculation using energy and molar gas volume
📐 Step-by-Step Calculation
Energy needed = 58 MJ = 58 × 1000 kJ = 58 000 kJ
(Alternatively: convert both to Joules: 58 000 000 J and 290 000 J)
Each mole of H₂ provides 290 kJ .
Moles of H₂ = 58 000 kJ ÷ 290 kJ/mol = 200 mol
1 mole of any gas at room temperature and pressure occupies 24 dm³ .
Volume = moles × 24 dm³
Volume = 200 × 24 = 4800 dm³
❌ Common Errors & Traps
- Prefix failure: Forgetting that MJ is megajoules (10⁶) and doing 58 ÷ 290 = 0.2 mol , forgetting to convert to kJ first.
- Dividing instead of multiplying: Calculating 200 ÷ 24 instead of 200 × 24 for molar gas volume.
- Unit muddling: Trying to convert 24 dm³ into cm³ unnecessarily and losing track of powers of 10.
🧠 Exam Technique: Error Carried Forward (ecf)
- Always write out your conversions clearly! Even if you incorrectly converted 58 MJ, you can still gain marks 2, 3, and 4 via error carried forward if your method is clear.
- Check the reasonableness of your final value: 100 km requires a substantial volume of fuel gas, so an answer of 4.8 dm³ or 0.2 dm³ should instantly alert you to a unit slip.
Topics
Chemistry · C2: Bonding, Structure and the Properties of Matter · C3: Quantitative Chemistry · C5: Energy Changes
Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.