AQA GCSE Chemistry Chemistry Paper 1 (Higher), November 2020: Question 6

9 marks · Standard Demand difficulty · Short Answer

Explain activation energy, determine the limiting reactant in the thermite reaction via mole calculations, complete an ionic displacement equation, and explain redox in terms of electron transfer.

Practise this question

Question

Question 06 contains four parts about displacement reactions. 06.1 asks for the definition of 'activation energy' for 1 mark. 06.2 provides the reaction 2Al + Fe2O3 -> 2Fe + Al2O3 and asks students to show that 1.00 kg of aluminium is the limiting reactant when mixed with 3.00 kg of iron oxide, given Ar values O = 16, Al = 27, Fe = 56 for 4 marks. 06.3 asks to complete the ionic equation Mg(s) + Zn2+(aq) -> with state symbols for 2 marks. 06.4 asks candidates to explain why the reaction between magnesium atoms and zinc ions is both oxidation and reduction for 2 marks.
Question text

06 This question is about displacement reactions.

06.1 The displacement reaction between aluminium and iron oxide has a high

activation energy.

What is meant by ‘activation energy’?

[1 mark]

06.2 A mixture contains 1.00 kg of aluminium and 3.00 kg of iron oxide.

The equation for the reaction is:

2Al + Fe2O3 → 2Fe + Al2O3

Show that aluminium is the limiting reactant.

Relative atomic masses (Ar): O = 16 Al = 27 Fe = 56

[4 marks]

Magnesium displaces zinc from zinc sulfate solution.

06.3 Complete the ionic equation for the reaction.

You should include state symbols.

*16* [2 marks]

Mg(s) + Zn2+(aq) → … + …

06.4 Explain why the reaction between magnesium atoms and zinc ions is both oxidation

and reduction.

[2 marks]

Mark scheme

Show the mark scheme Mark scheme for Question 6. 06.1 accepts minimum energy needed for particles to react or for a reaction to occur (1 mark). 06.2 awards up to 4 marks for finding Mr of Fe2O3 = 160, moles of Fe2O3 = 18.75 mol, moles of Al = 37.0 mol, and concluding 37.0 mol is less than the required 37.5 mol, or alternative methods via reacting masses. 06.3 awards 2 marks for Mg2+(aq) + Zn(s). 06.4 awards 1 mark for magnesium losing electrons (oxidised) and 1 mark for zinc ions gaining electrons (reduced).

Question 6

AO /

Question Answers Extra information Mark

Spec. Ref.

06.1 the (minimum) energy needed 1 AO1

for particles to react 4.5.1.2

or

the (minimum) energy needed allow the (minimum) energy

for a reaction to occur needed to start a reaction

06.2 (Mr of Fe2O3 =) 160 1 AO2

4.3.1.2

4.3.2.1

4.3.2.2

3000 4.3.2.4

(moles Fe2O3 = =)

18.75 (mol) allow correct use of incorrectly 1

calculated Mr

1000 allow 37.037037 (mol) correctly 1

(moles Al = =) 37.0 (mol)

rounded to at least 2 significant

figures

if both MP2 and MP3 are not

awarded allow 1 mark for

0.01875 mol Fe2O3 and 0.037

mol Al

(aluminium is limiting because) allow correct use of incorrect 1

37.0 mol is less than the (2 x number of moles from steps 2

18.75 =) 37.5 mol (aluminium and/or 3

needed)

or

iron oxide is in excess because

18.75 mol is more than the

37.0

( =) 18.5 mol (iron oxide

needed)

Question 6 continued

AO /

Spec. Ref.

06.2 alternative approaches: AO2

17 4.3.1.2

ctd

approach 1: 4.3.2.1

(finding required mass of 4.3.2.2

aluminium by moles method) 4.3.2.4

(Mr of Fe2O3 =) 160 (1)

3000

(moles Fe2O3 = =)

18.75 (mol) (1) allow correct use of incorrectly

calculated Mr

(moles Al needed

=18.75 × 2 = ) 37.5 (mol) allow correct use of incorrectly

and calculated moles of iron oxide

(mass Al needed = 37.5 × 27 =)

1012.5 (g) or 1.0125 kg (1) allow correct use of incorrectly

calculated moles of aluminium

needed

(so) 1.00 kg of aluminium is not dependent on calculated mass

enough (1) of aluminium needed being

greater than 1.00 (kg)

approach 2:

(finding required mass of

aluminium by proportion

method)

(Mr of Fe2O3 =) 160 (1)

(3.00 kg Fe2O3 needs)

3.00

× 2 × 27 (kg Al) (1) allow correct use of incorrectly

calculated Mr

(=) 1.0125 (kg) (1)

(so) 1.00 kg of aluminium is not dependent on calculated mass

enough (1) of aluminium needed being

greater than 1.00 (kg)

Question 6 continued

18 AO /

Spec. Ref.

06.2 alternative approaches: AO2

ctd 4.3.1.2

approach 3: 4.3.2.1

(finding required mass of iron 4.3.2.2

oxide by moles method) 4.3.2.4

Mr of Fe2O3 =) 160 (1)

1000

(moles Al = =) 37.0 (mol) allow 37.037037 (mol) correctly

rounded to at least 2 significant

(1)

figures

37.0

(moles Fe2O3 needed) = ) =

18.5 (mol) allow correct use of incorrectly

and calculated moles of aluminium

(mass Fe2O3 needed =

18.5 × 160 =) 2960 (g) or allow correct use of incorrectly

2.96 (kg) (1) calculated moles of iron oxide

needed

allow correct use of incorrectly

calculated Mr

(so) 3.00 kg of iron oxide is an dependent on calculated mass

excess (1) of iron oxide needed being less

than 3.00 (kg)

approach 4:

(finding required mass of iron

oxide by proportion method)

(Mr of Fe2O3 =) 160 (1)

1.00

(1.00 kg Al needs) ×160 allow correct use of incorrectly

2 x 27

(kg Fe2O3) (1) calculated Mr

(=) 2.96 (kg) (1)

(so) 3.00 kg of iron oxide is an dependent on calculated mass

excess (1) of iron oxide needed being less

than 3.00 (kg)

Question 6 continued19

AO /

Spec. Ref.

06.3 Mg(s) + Zn2+(aq) → allow multiples 2 AO2

Mg2+(aq) + Zn(s) 4.1.1.1

4.2.2.2

allow 1 mark for Mg2+ + Zn 4.4.1.4

with missing or incorrect state

symbols

06.4 magnesium (atoms) are 1 AO2

oxidised because they lose 4.4.1.4

electrons

(and) zinc (ions) are reduced 1

because they gain electrons

if no other marks awarded allow

1 mark for magnesium (atoms)

lose electrons and zinc (ions)

gain electrons

Total 9

How to answer it

Displacement Reactions, Limiting Reactants & Redox

What this question tests

This question assesses key skills across Quantitative Chemistry, Chemical Changes, and Energy Changes:

  • Recalling the exact scientific definition of activation energy.
  • Carrying out a multi-step limiting reactant calculation converting mass units (kg to g), finding moles ( n = m / Mᵣ ), and using stoichiometric molar ratios.
  • Constructing balanced ionic equations with full state symbols for single displacement reactions.
  • Explaining redox processes explicitly in terms of electron transfer ( OIL RIG ).
Question 06.1 • 1 Mark

Defining Activation Energy

Topic: Energy Changes (Reaction Profiles)

✅ Mark Scheme Answer

The minimum energy needed for particles to react.

(Also accepted: the minimum energy needed for a reaction to occur / to start a reaction.)

🧠 Exam Technique

The word minimum is essential. Saying just "the energy needed to start a reaction" will lose the mark on many exam series because it does not state that it is a threshold barrier.

❌ Common Errors

  • Omitting the word minimum (e.g. writing "the heat energy taken in to react").
  • Confusing activation energy with overall energy change (ΔH).

💡 Key Knowledge

  • Particles must collide with energy equal to or greater than the activation energy to have a successful collision.
  • High activation energy means strong bonds must be broken before new bonds form, so the mixture often requires a spark or flame to initiate.
Mark Breakdown: [1 mark] for stating minimum energy needed for particles to react / for a reaction to occur.
Question 06.2 • 4 Marks

Limiting Reactant Calculation: Aluminium & Iron Oxide

Equation: 2Al + Fe₂O₃ → 2Fe + Al₂O₃

📐 Step-by-Step Calculation (Comparing Available Moles)

Step 1: Calculate the formula mass (Mᵣ) of Fe₂O₃
Mᵣ(Fe₂O₃) = (2 × 56) + (3 × 16) = 112 + 48 = 160 [Mark 1]
Step 2: Convert kg to g and find moles of each reactant
• Moles of Fe₂O₃ = 3000 g / 160 = 18.75 mol [Mark 2]
• Moles of Al = 1000 g / 27 = 37.0 mol (or 37.04 mol) [Mark 3]
Step 3: Compare with the balanced molar ratio
From the equation: 2 moles of Al react with 1 mole of Fe₂O₃.
• To react all 18.75 mol of Fe₂O₃, required Al = 18.75 × 2 = 37.5 mol.
• We only have 37.0 mol of Al available (37.0 < 37.5).
Conclusion: Aluminium is the limiting reactant because there is not enough aluminium to react with all the iron oxide. [Mark 4]

❌ Common Calculation Traps

  • Unit conversion: Forgetting that 1 kg = 1000 g. If using 1.00 and 3.00, units are kmol, but students often forget this and divide 1 / 27 directly without keeping units consistent.
  • Ignoring the 2:1 ratio: Simply comparing 37.0 mol Al to 18.75 mol Fe₂O₃ and incorrectly claiming Fe₂O₃ is limiting because 18.75 is a smaller number. You must apply the reaction stoichiometry!
  • Mᵣ errors: Calculating Mᵣ(Fe₂O₃) as (56 + 16) or using atomic numbers instead of mass numbers.

🧠 Alternative Method (Mass-Based)

You can also show Al is limiting by mass:

  • 18.75 mol Fe₂O₃ needs 37.5 mol Al.
  • Required mass of Al = 37.5 mol × 27 g/mol = 1012.5 g (1.0125 kg).
  • Since 1.0125 kg is needed and only 1.00 kg is provided, aluminium runs out first and is the limiting reactant.
Mark Breakdown:
• Mark 1: Mᵣ of Fe₂O₃ = 160
• Mark 2: Moles of Fe₂O₃ = 3000 / 160 = 18.75 mol
• Mark 3: Moles of Al = 1000 / 27 = 37.0 mol
• Mark 4: Clear deduction comparing available moles to needed moles (37.0 < 37.5 mol).
Question 06.3 • 2 Marks

Completing an Ionic Equation with State Symbols

Reaction: Magnesium + Zinc Sulfate

✅ Correct Completed Equation

Mg(s) + Zn²⁺(aq) → Mg²⁺(aq) + Zn(s)

Products can be written in either order: Mg²⁺(aq) + Zn(s) or Zn(s) + Mg²⁺(aq) .

💡 Key Knowledge: Why do spectator ions vanish?

In full aqueous solution:

Mg(s) + Zn²⁺(aq) + SO₄²⁻(aq) → Mg²⁺(aq) + SO₄²⁻(aq) + Zn(s)

Sulfate ions (SO₄²⁻) do not change state or charge; they are spectator ions and cancel out on both sides.

❌ Common Errors

  • Missing out state symbols or writing incorrect ones (e.g., writing Mg²⁺(s) or Zn(aq)).
  • Writing incorrect charges such as Mg⁺ or Zn⁺. Both magnesium and zinc form 2+ ions.
  • Re-introducing the sulfate ion (SO₄²⁻) into an ionic equation.

🧠 Exam Technique

Read the question carefully: "You should include state symbols." In AQA mark schemes, this is worth an independent mark. Even if your formulae are correct, omitting state symbols caps your score at 1/2.

Mark Breakdown:
• 1 mark for correct species: Mg²⁺ + Zn
• 1 mark for correct state symbols: (aq) and (s)
Question 06.4 • 2 Marks

Explaining Redox in Terms of Electrons

Linking Oxidation and Reduction

✅ Mark Scheme Answer

  • Oxidation: Magnesium (atoms) are oxidised because they lose electrons. [Mark 1]
  • Reduction: Zinc (ions) are reduced because they gain electrons. [Mark 2]

💡 The Golden Rule: OIL RIG

  • Oxidation Is Loss of electrons:
    Mg → Mg²⁺ + 2e⁻
  • Reduction Is Gain of electrons:
    Zn²⁺ + 2e⁻ → Zn

❌ Common Errors & Examiner Commentary

  • Vague species identification: Saying "zinc is oxidised" instead of specifying zinc ions (Zn²⁺). In the reactant mixture, it is the Zn²⁺ ion gaining electrons, not zinc metal.
  • Reverting to oxygen definitions: Explaining the reaction as "magnesium gains oxygen" when there is no oxygen in the ionic equation!
  • Swapping the terms: Stating oxidation is gain of electrons. Always double-check with OIL RIG before writing.

🧠 Exam Technique

Structure your response into two distinct bullet points naming the exact species:

1. "Magnesium atoms lose 2 electrons to form Mg²⁺, so magnesium is oxidised."

2. "Zinc ions gain 2 electrons to form Zn atoms, so zinc ions are reduced."

Mark Breakdown:
• 1 mark for: magnesium (atoms) are oxidised because they lose electrons.
• 1 mark for: zinc (ions) are reduced because they gain electrons.

Topics

Chemistry · C3: Quantitative Chemistry · C4: Chemical Changes · C5: Energy Changes

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 1 (Higher), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.