AQA GCSE Chemistry Chemistry Paper 2 (Foundation), November 2020: Question 4

8 marks · Low Demand difficulty · Short Answer

Calculate an Rf value, identify chromatography phases, determine a component ratio, and evaluate properties of ink chromatography.

Practise this question

Question

Question 4 displays a paper chromatogram in Figure 6 showing a start line, a blue dye spot, a yellow dye spot, and a solvent front. Four vertical measurement arrows labelled A, B, C, and D are shown alongside. Sub-questions include: 04.1 asks to calculate the Rf value of the blue dye given a distance moved of 2.7 cm and solvent front distance of 9.0 cm; 04.2 asks which measurements are needed for the yellow dye's Rf value; 04.3 is a line-matching exercise linking mobile phase and stationary phase to Beaker, Ink, Paper, Solvent, or Start line; 04.4 asks for the simplest whole number ratio of 85% yellow dye to 15% blue dye; 04.5 asks to identify if green ink is a compound, element, formulation, or solvent; and 04.6 asks how changing dye percentages affects the Rf value of the yellow dye.
Question text

04 This question is about ink.

A student investigated green ink using paper chromatography in a beaker.

Figure 6 shows:

• the results the student obtained

• measurements A, B, C and D the student could make.

Figure 6

Diagram not to scale

04.1 The student calculated the Rf value of the blue dye.

The student measured:

• the distance moved by the blue dye = 2.7 cm

• the distance moved by the solvent = 9.0 cm

Calculate the Rf value of the blue dye.

Use the equation:

distance moved by dye

Rf =

distance moved by solvent

[2 marks]

Rf =

04.2 Which measurements on Figure 6 are needed to calculate the Rf value

of the yellow dye?

[1 mark]

*16* Tick ( ) one box.

A and B

A and C

B and D

C and D

04.3 Paper chromatography has a stationary phase and a mobile phase.

Draw one line from each phase to the identity of that phase in the

student’s investigation.

[2 marks]

Phase Identity

Beaker

Mobile phase Ink

Paper

Stationary phase Solvent

18 Start line

The green ink contains 85% yellow dye and 15% blue dye.

04.4 Determine the simplest whole number ratio of yellow dye : blue dye in the green ink.

[1 mark]

Yellow dye : Blue dye = :

04.5 Which word correctly describes the green ink?

[1 mark]

Tick ( ) one box.

Compound

Element

Formulation

Solvent

04.6 The student repeated the investigation using green ink containing 75% yellow dye and

25% blue dye.

What would happen to the Rf value of the yellow dye?

[1 mark]

Tick ( ) one box.

The Rf value would decrease.

The Rf value would increase.

The Rf value would stay the same.

Mark scheme

Show the mark scheme Mark scheme for Question 4 lists acceptable answers and mark allocations: 04.1 accepts 2.7 / 9.0 (1 mark) giving 0.3 (1 mark, ignore units); 04.2 awards 1 mark for 'C and D'; 04.3 awards 1 mark for connecting Mobile phase to Solvent and 1 mark for connecting Stationary phase to Paper; 04.4 awards 1 mark for the ratio 17 : 3; 04.5 awards 1 mark for 'formulation'; and 04.6 awards 1 mark for 'the Rf value would stay the same'. Total marks: 8.

Question 4

AO /

Question Answers Extra information Mark

Spec. Ref.

AO2

04.1 2.7 1 4.8.1.3

9.0 RPA6

= 0.3 ignore units 1

AO1

04.2 C and D 1 4.8.1.3

RPA6

04.3 AO1

4.8.1.3

RPA6

additional line from a box on the left negates the mark for that box

04.4 17 : 3 1 AO2

4.8.1.2

04.5 formulation 1 AO2

4.8.1.2

04.6 the Rf value would stay the 1 AO3

same 4.8.1.2

Total 8

How to answer it

Paper Chromatography & Formulations

📋 What this question tests

This question assesses fundamental practical and theoretical skills from AQA Chemistry Topic 8 (Chemical Analysis - RPA 6):

  • Calculating retention factors (Rf values) from experimental measurements.
  • Correctly identifying measurement baselines (always from the pencil start line, not the paper edge).
  • Distinguishing between the stationary phase and mobile phase.
  • Simplifying percentage compositions into whole-number ratios.
  • Recognising mixtures designed for a useful purpose as formulations.
  • Understanding factors affecting Rf values (concentration does not alter Rf).
Question 04.1

Calculating the Rf Value of the Blue Dye

2 Marks • AO2 Calculation

📐 Step-by-Step Calculation

  1. Identify formula & values:
    Distance moved by dye = 2.7 cm
    Distance moved by solvent = 9.0 cm
  2. Substitute values into equation:
    Rf = 2.7 / 9.0 [1 mark]
  3. Evaluate:
    Rf = 0.3 [1 mark]

❌ Common Errors

  • Inverting the fraction: Doing 9.0 / 2.7 = 3.33. An Rf value can never be greater than 1.0!
  • Adding units: Rf is a pure ratio (cm / cm), so it has no units. Writing "0.3 cm" is ignored by examiners, but always remember it has no units.
Mark Scheme: 2.7 / 9.0 (1 mark) • = 0.3 (1 mark). Ignore any units given.
Question 04.2

Identifying Correct Chromatogram Measurements

1 Mark • AO1 Practical Technique

✅ Correct Answer

C and D

  • C: Distance from the pencil start line to the solvent front.
  • D: Distance from the pencil start line to the centre of the yellow spot.

🧠 Exam Technique: Where to Measure

  • Always measure from the pencil start line, NEVER from the bottom edge of the chromatography paper.
  • Measurements A and B incorrectly start at the very bottom edge of the paper, making them invalid for Rf calculations.
Mark Scheme: C and D (1 mark).
Question 04.3

Stationary and Mobile Phases

2 Marks • AO1 Recall

✅ Correct Matches

  • Mobile phase → Solvent [1 mark]
  • Stationary phase → Paper [1 mark]

💡 Key Knowledge

  • Mobile phase: The phase that moves. In paper chromatography, this is the liquid solvent (e.g. water or ethanol) carrying the dyes up the strip.
  • Stationary phase: The phase that does not move. In this setup, it is the absorbent chromatography paper.

❌ Examiner Warning

Drawing more than one line from a box on the left automatically negates the mark for that box. Only draw exactly one line from each phase.

Mark Scheme: Mobile phase → Solvent (1 mark); Stationary phase → Paper (1 mark). Any extra line from a left-hand box negates that mark.
Question 04.4

Simplest Whole Number Ratio

1 Mark • AO2 Mathematical Skill

📐 Step-by-Step Calculation

  1. Write given ratio: Yellow dye : Blue dye = 85 : 15
  2. Find the highest common factor: Both numbers end in 5, so divide both by 5:
    85 ÷ 5 = 17
    15 ÷ 5 = 3
  3. Final whole-number ratio: 17 : 3

❌ Common Errors

  • Reversing the order: Writing 3 : 17 instead of 17 : 3 (the question explicitly asks for yellow dye : blue dye).
  • Failing to fully simplify: Leaving it as 85 : 15 scores 0 marks because the question requests the simplest whole number ratio.
Mark Scheme: 17 : 3 (1 mark).
Question 04.5

Classifying the Ink: Formulations

1 Mark • AO2 Classification

✅ Correct Answer

Formulation

💡 What is a Formulation?

A formulation is a complex mixture designed as a useful product, prepared by mixing components in carefully measured, exact quantities to give the product specific desired properties.

Common examples include: paints, inks, medicines, cleaning agents, cosmetics, and fertilisers.

❌ Why Other Options Are Incorrect

  • Compound: Chemical substances chemically bonded together in fixed ratios; ink components can be physically separated.
  • Element: Pure substance containing only one type of atom.
  • Solvent: The liquid used to dissolve substances (e.g. water), not the whole coloured ink mixture.
Mark Scheme: Formulation (1 mark).
Question 04.6

Effect of Concentration on Rf Value

1 Mark • AO3 Analysis & Understanding

✅ Correct Answer

The Rf value would stay the same.

💡 Key Knowledge: What Determines Rf?

An Rf value depends only on:

  • The substance itself (its relative affinity/solubility).
  • The mobile phase (solvent used).
  • The stationary phase (paper used).

Changing the concentration or percentage of dye alters the spot's size or colour intensity, but does not change the Rf value.

🧠 Exam Strategy Tip

When asked what happens to an Rf value if you change sample size or concentration, remember that Rf is a characteristic physical constant for a specific substance in a specific solvent system. It remains constant!

Mark Scheme: the Rf value would stay the same (1 mark).

Topics

Chemistry · Required Practicals · C8: Chemical Analysis · Required Practicals

Question and mark scheme from the AQA GCSE Chemistry examination, Chemistry Paper 2 (Foundation), November 2020. QuestionVault is an independent revision resource; questions remain the copyright of the awarding body.